The order of operations is a convention used to determine which operations are performed first. In every math exercise that combines more than one operation (addition, subtraction, multiplication, division, etc.), each operation must be performed in a specific order:

  1. Parentheses
  2. Powers and Roots
  3. Multiplication and division (from left to right)
  4. Addition and subtraction (from left to right)
  • When a type of operation is repeated in an exercise, they must be solved in order from left to right.
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Test yourself on the order of operations!

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Indicate whether the equality is true or not.

\( (5^2+3):2^2=5^2+(3:2^2) \)

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It is important to perform the operations in the right order to arrive at the correct result.

  1. The first operations we have to solve are those in parentheses. Once solved, we can continue. Some exercises include parentheses inside other parentheses. In such cases, we must first solve the internal parentheses before solving the external ones.
  2. The next operations that we must solve are powers and roots, also referred to as 'exponents'. When these are inside parentheses, we solve them first in order to solve the parentheses.
  3. The next operations we must perform are multiplication and division. When there is more than one in the exercise, they must be solved in order from left to right.
  4. The last operations to perform are addition and subtraction. These must also be solved from left to right in instances when there is more than one in the same exercise.

Order of Elementary Operations with Combined Operations

Before talking about more advanced mathematical operations, it is important to know the order in which the elementary mathematical operations (addition, subtraction, multiplication and division) are solved.

In each exercise we will solve these operations in the following order:

  1. Multiplication and division
  2. Addition and subtraction

For example, in the exercise:

  • 4+5ร—7 4+5\times7

First, we solve the multiplication (5ร—7=35) \left(5\times7=35\right) before adding the 4 4 . The result is 39 39 .

When we have only one type of operation (only multiplication and division, or only addition and subtraction), we solve the exercise from left to right.

Let's look at the following example:

  • 4โˆ’3+7โˆ’5 4-3+7-5

In this exercise, we have only one type of operation (addition and subtraction). Therefore, we solve it from left to right:

  • 4โˆ’3=1 4-3=1
  • 1+7=8 1+7=8
  • 8โˆ’5=3 8-5=3


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Order of Operations โ€“ Parentheses


Whenever there are parentheses, the first thing to do is to perform the operations contained within them.

The order of operations in cases where there are parentheses and basic operations is as follows:

  1. Parentheses
  2. Powers and roots
  3. Multiplication and division (from left to right)
  4. Addition and subtraction (from left to right)

For example, in the exercise:

  • 4ร—5+(7โˆ’3) 4\times5+(7-3)

First, we perform the operation inside the parentheses: (7โˆ’3)=4 \left(7-3\right)=4 .

Then, we solve the operation outside of the parentheses: 4ร—5=20 4\times5=20 .

Finally, we add both figures together: 20+4=24 20+4=24 .

Use parentheses '( )' instead of brackets '[ ]'.


Order of Operations โ€“ Powers

When an exercise includes powers or roots, these operations will be solved before the multiplication and division. Therefore, the order to follow is:

  1. Parentheses
  2. Powers and Roots
  3. Multiplication and division
  4. Addition and subtraction

For example:

  • 4+3ร—32ร—(7โˆ’5)= 4+3\times3^2\times(7-5)=

First, we solve the operation inside parentheses:

  • 7โˆ’5=2 7-5=2
  • 4+3ร—32ร—2= 4+3\times3^2\times2=

Next, we simplify the power:

  • 32=9 3^2=9
  • 4+3ร—9ร—2= 4+3\times9\times2=

Then, we perform the multiplications (from left to right):

  • 3X9=27 3X9=27
  • 4+27ร—2= 4+27\times2=

We continue with the second multiplication:

  • 27ร—2=54 27\times2=54
  • 4+54= 4+54=

Finally, we perform the addition that will give us the answer:

  • 4+54=58 4+54=58

Do you know what the answer is?

Order of Operations โ€“ Powers and Roots


Order of Operations โ€“ Multiplications and Divisions

  1. Parentheses
  2. Powers and roots
  3. Multiplication and division
  4. Addition and subtraction


Check your understanding

Order of Operations โ€“ Addition and Subtraction (from left to right)

  1. Parentheses
  2. Powers and roots
  3. Multiplication and division
  4. Addition and subtraction

Review Questions

What is the order when solving an equation?

It depends on the type of equation. However, it is important not to confuse the term 'equation' with the term 'expression'. This article deals with arithmetic expressions.

To solve an equation, for example a first-degree equation, both sides must be simplified using the order of operations. If there are unknown variables on both sides, they must be put together on a single side.


What is solved first in an expression?

  1. Operations inside parentheses
  2. Powers and roots
  3. Multiplication and division
  4. Addition and subtraction

Which is performed first, addition or subtraction?

They are performed in order from left to right.


What is a combined operation?

An arithmetic expression which include several operations.


What is the order of combined operations without parentheses?

  1. Powers and roots
  2. Multiplication and division
  3. Addition and subtraction

What is the order of operations?

It is the order in which operations are carried out in an exercise.


Which operation has the highest priority?

The powers and roots. Parentheses are not really operations, but rather symbols that help us group operations together.


Which is solved first when there are no parentheses, addition or multiplication?

Multiplication.


Do you think you will be able to solve it?

Oder of Operations Exercises

Exercise 1

What is the solution to this exercise?

5โˆ’2ร—12+1= 5-2\times\frac{1}{2}+1=

Solution:

In the first step of the exercise, you must calculate the multiplication.

2ร—12=21ร—12=22=1 2\times\frac{1}{2}=\frac{2}{1}\times\frac{1}{2}=\frac{2}{2}=1

From here, you can continue with the remaining addition and subtraction operations.

5โˆ’1+1=5 5-1+1=5

Answer: 5 5


Exercise 2

What is the solution to this exercise?

12:(4ย โˆ’93)= 12:(4\ -\frac{9}{3})=

Solution:

We begin with the parentheses and the division operation inside it.

9:3=3 9:3=3

Then we perform the subtraction operation.

4โˆ’3=1 4-3=1

Finally, we perform the division operation that is outside of the parentheses.

12:1=12 12:1=12

Answer:

12 12


Test your knowledge

Exercise 3

What is the solution to this exercise?

(X+4)(3+X) (X+4)(3+X)

Given that:

X=4 X=4

Solution:

We start by substituting the value of X X .

(4+4)(3+4) (4+4)(3+4)

Then, we perform the calculations in parentheses.

(8)(7) (8)(7)

Once we have solved the parentheses, we simply multiply the resulting figures together.

7ร—8=56 7\times 8=56

Answer: 56 56


Exercise 4

Determine the missing number in the equation:

?โ€‰โฃ:(โˆ’6)+[โˆ’2(94โˆ’73)]=โˆ’153 ?\colon(-6)+\lbrack-2(94-73)\rbrack=-153

Solution:

Calculate according to the order of operations to work out the value of the unknown variable.

?=X ?=X

X:โˆ’6+(โˆ’2(94โˆ’73))=โˆ’153 X:-6+(-2(94-73))=-153

X:โˆ’6+(โˆ’2(21))=โˆ’153 X:-6+(-2(21))=-153

X:โˆ’6โˆ’42=โˆ’153 X:-6-42=-153

X:โˆ’6=โˆ’153+42 X:-6=-153+42

X=โˆ’111ร—6 X=-111\times 6 / ร—โˆ’6 \times -6

X=666 X=666

Answer:

X=666 X=666


Do you know what the answer is?

Exercise 5

In a flower field there are a number of flowers.

One bush contains 5 5 flowers, and there are 13 13 such bushes.

Another area has 99 plants with 2 2 flowers each. The flower pickers picked 30 30 flowers from the bushes and 10 10 from the plants.

Task:

How many flowers are left in the field?

Solution:

We will turn the question into an expression with which we are familiar:

(5ร—13โˆ’30)+(9ร—2โˆ’10) \left(5\times 13-30\right)+\left(9\times 2-10\right)

First, we will solve everything in the parentheses, starting with multiplication and division from left to right.

(65โˆ’30)+(18โˆ’10) \left(65-30\right)+\left(18-10\right)

Then, we perform the addition and subtraction operations found in parentheses.

35+8 35+8

Finally, we perform the operations outside the parentheses.

35+8=43 35+8=43

Answer:

43 43


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On the Tutorela blog, you can find a variety of helpful articles on the subject of mathematics!


Exercises for practicing the order of basic operations

  • 2+3ร—4= 2+3\times4=
  • 3โˆ’5ร—2+3= 3-5\times2+3=
  • 6ร—7+3ร—4= 6\times7+3\times4=
  • 2โˆ’3+5ร—6:2= 2-3+5\times6:2=
  • 3+4โˆ’12:3:2ร—6= 3+4-12:3:2\times6=

Check your understanding

Exercises for practicing the order of operations with parentheses

  • 3+5ร—(2+3)= 3+5\times(2+3)=
  • (3โˆ’5)ร—(2+3)= \left(3-5\right)\times(2+3)=
  • 3+4โˆ’12:3:(2ร—2)= 3+4-12:3:(2\times2)=
  • (2โˆ’3)+5ร—(6:2)= \left(2-3\right)+5\times(6:2)=

Exercises for practicing the order of operations with powers

  • 2+2ร—42= 2+2\times4^2=
  • 2+(2ร—4)2= 2+(2\times4)^2=
  • 32โˆ’12:3:(2X2)= 3^2-12:3:(2X2)=
  • (2โˆ’3)+5ร—(6:2)2+(22โˆ’3)= \left(2-3\right)+5\times(6:2)^2+(2^2-3)=

Do you think you will be able to solve it?

Answers to the exercise: order of basic operations

  • 2+3ร—4=14 2+3\times4=14
  • 3โˆ’5ร—2+3=โˆ’4 3-5\times2+3=-4
  • 6ร—7+3ร—4=54 6\times7+3\times4=54
  • 2โˆ’3+5ร—6:2=14 2-3+5\times6:2=14
  • 3+4โˆ’12:3:2ร—6=โˆ’5 3+4-12:3:2\times6=-5

Answers to the exercise: order of operations with parenthesis

  • 3+5ร—(2+3)=28 3+5\times(2+3)=28
  • (3โˆ’5)ร—(2+3)=โˆ’10 \left(3-5\right)\times(2+3)=-10
  • 3+4โˆ’12:3:(2ร—2)=6 3+4-12:3:(2\times2)=6
  • (2โˆ’3)+5ร—(6:2)=14 \left(2-3\right)+5\times(6:2)=14

Test your knowledge

Answers to the exercise: order of operations with powers

  • 2+2ร—42=34 2+2\times4^2=34
  • 2+(2ร—4)2=66 2+(2\times4)^2=66
  • 32โˆ’12:3:(2ร—2)=8 3^2-12:3:(2^{\times}2)=8
  • (2โˆ’3)+5ร—(6:2)2+(22โˆ’3)=45 \left(2-3\right)+5\times(6:2)^2+(2^2-3)=45

More exercises for individual practice of the order of operations

  • 10ร—2:4= 10\times2:4=
  • 80:4:2:5= 80:4:2:5=
  • 36โˆ’4:2= 36-4:2=
  • 24:2โˆ’4โˆ’3:3= 24:2-4-3:3=
  • 5ร—5ร—2โˆ’12:4= 5\times5\times2-12:4=
  • 100:2โˆ’10:2+3ร—4โˆ’6โˆ’5ร—2= 100:2-10:2+3\times4-6-5\times2=

Do you know what the answer is?

Examples with solutions for The Order of Operations

Exercise #1

Indicate whether the equality is true or not.

(52+3):22=52+(3:22) (5^2+3):2^2=5^2+(3:2^2)

Video Solution

Step-by-Step Solution

In order to determine the correctness (or incorrectness) of the given equation, let's simplify both sides separately:

A. Let's start with the expression on the left side:

(52+3):22 (5^2+3):2^2 Let's simplify this expression while remembering the order of operations which states that exponents come before multiplication and division, which come before addition and subtraction, and parentheses come before everything else, therefore we'll start by simplifying the expression inside the parentheses, this is done by calculating the numerical value of the terms with exponents within them, then we'll calculate the addition operation in the parentheses:

(52+3):22=(25+3):22=28:22 (5^2+3):2^2 =\\ (25+3):2^2 =\\ 28:2^2 We'll continue and remember that exponents come before division, therefore, we'll first calculate the term with the exponent which is the divisor in the expression (in fact, if we were to convert the division operation to a fraction, this term would be in the denominator), then we'll calculate the result of the division operation:

28:22=28:4=7 28:2^2 =\\ 28:4 =\\ 7 We've finished simplifying the expression on the left side of the given equation, let's summarize the simplification process:

(52+3):22=28:22=28:4=7 (5^2+3):2^2 =\\ 28:2^2= \\ 28:4 =\\ 7 B. Let's continue with the expression on the right side of the given equation:

52+(3:22) 5^2+(3:2^2) Similar to what we did in the previous part we'll simplify the expression while adhering to the order of operations mentioned earlier, therefore, we'll again start by simplifying the expression inside the parentheses, this is first done by calculating the numerical value of the term with the exponent (since exponents come before division), then we'll perform the division operation on the second term from the left (in parentheses), simultaneously we'll calculate the numerical value of the term with the exponent (the first from the left) and then we'll perform the addition operation:

52+(3:22)=52+(3:4)=25+34=2534 5^2+(3:2^2) =\\ 5^2+(3:4)=\\ 25+\frac{3}{4}=\\ 25\frac{3}{4} Note that since the division operation yielded a non-whole number we settled for converting this operation to a fraction, finally we performed the addition operation between the whole number and the fraction and wrote the result as a mixed number, this fraction can be converted to a decimal but there's no need for that,

Note that in this expression the parentheses are actually meaningless because multiplication and division come before addition and subtraction anyway, but good practice says that if they're noted in the problem, they should be given precedence in the approach,

We've finished simplifying the expression on the right side of the equation, since the calculation is short there's no need to summarize,

Let's return then to the original equation and substitute in place of the expressions on both sides the results of the simplifications detailed in A and B in order to determine its correctness (or incorrectness):

(52+3):22=52+(3:22)โ†“7=2534 (5^2+3):2^2=5^2+(3:2^2) \\ \downarrow\\ 7=25\frac{3}{4} Now we can definitively determine that the given equation is incorrect, meaning - we have a false statement,

Therefore the correct answer is answer B.

Answer

Not true

Exercise #2

Solve:

3โˆ’4+2+1 3-4+2+1

Video Solution

Step-by-Step Solution

We will use the substitution property to arrange the exercise a bit more comfortably, we will add parentheses to the addition operation:
(3+2+1)โˆ’4= (3+2+1)-4=
We first solve the addition, from left to right:
3+2=5 3+2=5

5+1=6 5+1=6
And finally, we subtract:

6โˆ’4=2 6-4=2

Answer

2

Exercise #3

Solve:

โˆ’5+4+1โˆ’3 -5+4+1-3

Video Solution

Step-by-Step Solution

According to the order of operations, addition and subtraction are on the same level and, therefore, must be resolved from left to right.

However, in the exercise we can use the substitution property to make solving simpler.

-5+4+1-3

4+1-5-3

5-5-3

0-3

-3

Answer

โˆ’3 -3

Exercise #4

Solve:

9โˆ’3+4โˆ’2 9-3+4-2

Video Solution

Step-by-Step Solution

According to the rules of the order of operations, we will solve the exercise from left to right since it only has addition and subtraction operations:

9โˆ’3=6 9-3=6

6+4=10 6+4=10

10โˆ’2=8 10-2=8

Answer

8

Exercise #5

0+0.2+0.6= 0+0.2+0.6= ?

Video Solution

Step-by-Step Solution

According to the order of operations, the exercise is solved from left to right as it contains only an addition operation:

0+0.2=0.2 0+0.2=0.2

0.2+0.6=0.8 0.2+0.6=0.8

Answer

0.8

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