The Order of Operations - Examples, Exercises and Solutions

Let's begin by multiplying the numerator:

$25+25=50$

We obtain the following fraction:

$\frac{50}{10}$

Finally let's reduce the numerator and denominator by 10 and we are left with the following result:

$\frac{5}{1}=5$

According to the order of operations rules, we first divide and then add:

$0:7=0$

$0+1=1$

According to the order of operations, the exercise is solved from left to right as it only involves an addition operation:

$12+1=13$

$13+0=13$

According to the order of operations, the exercise is solved from left to right as it contains only an addition operation:

$0+0.2=0.2$

$0.2+0.6=0.8$

According to the order of operations, since the exercise only involves addition operations, we will solve the problem from left to right:

$\frac{1}{2}+0=\frac{1}{2}$

$\frac{1}{2}+\frac{1}{2}=\frac{1}{1}=1$

According to the order of operations rules, since the exercise only involves addition and subtraction, we will solve the problem from left to right:

$9-0=9$

$9+0.5=9.5$

According to the order of operations rules, since the exercise only involves addition and subtraction operations, we will solve the problem from left to right:

$19+1=20$

$20-0=20$

According to the order of operations rules, we first divide and then add:

$0:3=0$

$2+0=2$

According to the order of operations, we first multiply and then add:

$3\times0=0$

$12+0=12$

According to the order of operations, we first solve the expression in parentheses:

$5\times1=5$

Now we multiply:

$8\times5=40$

According to the order of operations, we first place the multiplication operation inside parenthesis:

$(7\times1)+\frac{1}{2}=$

Then, we perform this operation:

$7\times1=7$

Finally, we are left with the answer:

$7+\frac{1}{2}=7\frac{1}{2}$

According to the order of operations, we will solve the exercise from left to right since it only contains multiplication and division operations:

$\frac{6}{3}=2$

$2\times1=2$

We will use the substitution property to arrange the exercise a bit more comfortably, we will add parentheses to the addition operation:
$(3+2+1)-4=$
We first solve the addition, from left to right:
$3+2=5$

$5+1=6$
And finally, we subtract:

$6-4=2$

According to the rules of the order of operations, we will solve the exercise from left to right since it only has addition and subtraction operations:

$9-3=6$

$6+4=10$

$10-2=8$

According to the order of operations, addition and subtraction are on the same level and, therefore, must be resolved from left to right.

However, in the exercise we can use the substitution property to make solving simpler.

-5+4+1-3

4+1-5-3

5-5-3

0-3

-3