The exponent of a power

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The exponent implies the number of times the base of the power must multiply itself.
In order for the base of the power to know how many times it should multiply itself, we must look at the exponent. The exponent denotes the power to which the base must be raised, that is, it determines how many times we will multiply the base of the power by itself.
How can they remember it?
It is called the exponent because (from the Latin exponentis) it makes visible or exposes how many times the base of the power will be multiplied.
In reality, it not only exposes but also determines.
How will we identify the exponent?
The exponent appears as a small number that is placed in the upper right corner of the base of the power.
It is not the main factor as the base is, therefore, its size is smaller and it appears discreetly to the right side and above it.

A - Base and the exponent of the power

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einstein

What is the missing exponent?

\( -7^{\square}=-49 \)

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Let's see the following example:
a4a^4

Could you indicate what the exponent is?
4 of course!
We can clearly see that the exponent is smaller and located at the top right corner of the base of the power.

The number of times that a) must be multiplied by itself is 4.

We can say that:
a4=a×a×a×a a^4=a\times a\times a\times a
In this example: a) must be multiplied by itself 4 times, as indicated by the exponent.


Exercises on the exponent of a power:

Exercise 1

Assignment

Solve the following exercise:

(4×9×11)a (4\times9\times11)^a

Solution

We will use the formula

(abc)m=am×bm×cm (abc)^m=a^m\times b^m\times c^m

We solve accordingly

(4×9×11)a=4a×9a×11a=4a9a11a (4\times9\times11)^a=4^a\times9^a\times11^a=4^a9^a11^a

Answer

4a9a11a 4^a9^a11^a


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Exercise 2

Prompt

(4x)y= \left(4^x\right)^y=

Solution

We multiply the two powers together.

4x×y=4xy 4^{x\times y}=4^{xy}

Answer

4xy 4^{xy}


Exercise 3

Assignment

xa=? x^{-a}=\text{?}

Solution

xa=x0a x^{-a}=x^{0-a}

x0xa= \frac{x^0}{x^a}=

1xa \frac{1^{}}{x^a}

Answer

1xa \frac{1^{}}{x^a}


Do you know what the answer is?

Exercise 4

25=? 2^{-5}=\text{?}

Solution

25=205= 2^{-5}=2^{0-5}=

2025= \frac{2^0}{2^5}=

125= \frac{1}{2^5}=

We solve the exercise in the fraction according to the power

25=2×2×2×2×2= 2^5=2\times2\times2\times2\times2=

We solve the multiplications from left to right

4×2×2×2= 4\times2\times2\times2=

8×2×2= 8\times2\times2=

16×2=32 16\times2=32

Answer

132 \frac{1}{32}


Exercise 5

Assignment

41=? 4^{-1}=\text{?}

Solution

41=4041= 4^{-1}=\frac{4^0}{4^1}=

14 \frac{1}{4}

Answer

14 \frac{1}{4}


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Review Questions

What does the exponent in a number's power represent?

The exponent of a base is the number that is found in the upper right part of the base and it is the number that represents or indicates how many times the base should be multiplied by itself.

For example:

24= 2^4=

In this power, the base is 2 2 and the exponent is 4 4 , therefore the exponent indicates that the two should be multiplied by itself 4 4 times, that is:

24= 2×2×2×2 2^4=\text{ }2\times2\times2\times2


When a power has no exponent, what number is it?

When a power does not explicitly have an exponent, that is, it lacks an exponent, we must assume that it has an exponent 1 1

Examples:

a=a1 a=a^1

3=31 3=3^1

7=71 7=7^1


Do you think you will be able to solve it?

What is a power with base one?

In this case, the base will be one, and for this type of power the following holds true:

1m=1 1^m=1

This property tells me that the base one raised to any power will result in 1 1 , since one is always multiplied several times, or in this case, the number of times indicated by the exponent.

Examples

13=1×1×1=1 1^3=1\times1\times1=1

15=1 1^5=1

18=1 1^8=1


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Examples with solutions for The exponent of a power

Exercise #1

Choose the expression that is equal to the following:

27 2^7

Video Solution

Step-by-Step Solution

To solve this problem, we'll focus on expressing the power 27 2^7 as a series of multiplications.

  • Step 1: Identify the given power expression 27 2^7 .
  • Step 2: Convert 27 2^7 into a product of repeated multiplication. This involves writing 2 multiplied by itself for a total of 7 times.
  • Step 3: The expanded form of 27 2^7 is 2×2×2×2×2×2×2 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 .

By comparing this expanded form with the provided choices, we see that the correct expression is:

2222222 2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2

Therefore, the solution to the problem is the expression that matches this expanded multiplication form, which is the choice 1: 2222222\text{1: } 2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2.

Answer

2222222 2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2

Exercise #2

Which of the following is equivalent to the expression below?

10,0001 10,000^1

Video Solution

Step-by-Step Solution

To solve this problem, we will apply the rule of exponents:

  • Any number raised to the power of 1 remains unchanged. Therefore, by the identity property of exponents, 10,0001=10,000 10,000^1 = 10,000 .

Given the choices:

  • 10,00010,000 10,000 \cdot 10,000 : This is 10,0002 10,000^2 .
  • 10,0001 10,000 \cdot 1 : Simplifying this expression yields 10,000, which is equivalent to 10,0001 10,000^1 .
  • 10,000+10,000 10,000 + 10,000 : This results in 20,000, not equivalent to 10,0001 10,000^1 .
  • 10,00010,000 10,000 - 10,000 : This results in 0, not equivalent to 10,0001 10,000^1 .

Therefore, the correct choice is 10,0001 10,000 \cdot 1 , which simplifies to 10,000, making it equivalent to 10,0001 10,000^1 .

Thus, the expression 10,0001 10,000^1 is equivalent to:

10,0001 10,000 \cdot 1

Answer

10,0001 10,000\cdot1

Exercise #3

62= 6^2=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Recognize that 62 6^2 means 6×6 6 \times 6 .
  • Step 2: Perform the multiplication of 6 by itself.

Now, let's work through each step:
Step 1: The expression 62 6^2 indicates we need to multiply 6 by itself.
Step 2: Calculating 6×6 6 \times 6 gives us 36.

Therefore, the value of 62 6^2 is 36.

Answer

36

Exercise #4

112= 11^2=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Set up the multiplication as 11×11 11 \times 11 .
  • Step 2: Compute the product using basic arithmetic.
  • Step 3: Compare the result with the provided multiple-choice answers to identify the correct one.

Now, let's work through each step:
Step 1: We begin with the calculation 11×11 11 \times 11 .
Step 2: Perform the multiplication:

  1. Multiply the units digits: 1×1=1 1 \times 1 = 1 .
  2. Next, for the tens digits: 11×10=110 11 \times 10 = 110 .
  3. Add the results: 110+1=111 110 + 1 = 111 . This doesn't seem right, so let's break it down further.

Let's examine a more structured multiplication method:

Multiply 11 11 by 1 1 (last digit of the second 11), we get 11.
Multiply 11 11 by 10 10 (tens place of the second 11), we get 110.

If we align correctly and add the partial products:

     11
+   110
------------
   121

Step 3: The correct multiplication yields the final result as 121 121 . Upon reviewing the provided choices, the correct answer is choice 4: 121 121 .

Therefore, the solution to the problem is 121 121 .

Answer

121

Exercise #5

Which of the following clauses is equal to 100?

Video Solution

Step-by-Step Solution

To determine which expression equals 100, we need to evaluate each option:

  • Option 1: 5255^2\cdot5
    - Calculate 52=255^2 = 25.
    - Then compute 255=12525 \cdot 5 = 125.
  • Option 2: 4244^2\cdot4
    - Calculate 42=164^2 = 16.
    - Then compute 164=6416 \cdot 4 = 64.
  • Option 3: 25425^4
    - Calculate (254)(25^4), which simplified through breakdown is larger than 100 because 252=62525^2 = 625. Hence this 25 to the power of 4 will definitely be much larger than 100.
  • Option 4: 52225^2\cdot2^2
    - Calculate 52=255^2 = 25.
    - Calculate 22=42^2 = 4.
    - Compute 254=10025 \cdot 4 = 100.

Therefore, the expression in Option 4, 52225^2\cdot2^2, equals 100. Thus, the correct choice is 4.

Thus, the clause that equals 100 is 52225^2\cdot2^2.

Answer

5222 5^2\cdot2^2

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