Elimination of Parentheses in Real Numbers

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In previous articles, we have studied real numbers and the grouping of terms, as well as the order of mathematical operations with parentheses. In this article, we move forward and combine these topics in order to understand when and how we can eliminate parentheses in real numbers.

What does the elimination of parentheses in real numbers mean?

When we perform grouping of like terms ("addition and subtraction") with real numbers, we confine the real number within parentheses.

Parentheses can be removed but when eliminating them, the following rules must be remembered:

  • ++=+++ = +
    1+(+3)=1+31+(+3) = 1+3
     
  • =+-- = +
    1(3)=1+31-(-3) = 1+3
     
  • +=+- = -
    1+(3)=131+(-3) = 1-3
     
  • +=-+ = -
    1(+3)=131-(+3) = 1-3
Elimination of Parentheses in Real Numbers

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What is the inverse number of \( 0.7 \)

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The logic in this case is that the subtraction sign allows us to obtain the number opposite to the one given to us.
Consequently:

  • "Minus minus six" is equal to "plus six", that is, "six".
  • Similarly, "minus plus six" is equal to "minus six".

However, the plus sign does not indicate a modification in the number.
Therefore,

  • "plus minus six" is equal to "minus six"
  • and "plus plus six" is equal to "plus six", that is, "six".

Examples:

  • (+50)+(20)=(+30)(+50)+(-20) = (+30)
  • (8)(+2)=(10)(-8)-(+2) = (-10)
  • (3)(4)=(+1)(-3)-(-4) = (+1)

Let's look again at the three previously solved exercises, now we will write them without parentheses.

  • (+50)+(20)=(+30)(+50)+(-20) = (+30)
    5020=3050-20 = 30
     
  • (8)(+2)=(10)(-8)-(+2) = (-10)
    82=10-8-2 = -10
     
  • (3)(4)=(+1)(-3)-(-4)=(+1)
    3+4=1-3+4 = 1

As we surely remember from the class on "real numbers", when a number has no sign, we understand it to be positive.
Therefore,

  • in the first exercise, we can write "50" and "30" instead of "+50" and "+30".
  • However, we cannot remove the plus sign in the third exercise: in "+4".

Remember: We can only omit the plus sign if the number is the first in the sequence.

When solving exercises with real numbers, in the first phase we will remove the parentheses according to mathematical rules.

Example:

(+58)(34)+(+9)(+5)+(2)=(+58)-(-34)+(+9)-(+5)+(-2) =
58+34+952=9458+34+9-5-2 = 94


Exercises on Eliminating Parentheses in Real Numbers

Exercise 1

Complete:

  • (10)=–(-10) = __
  • +(+8)=+(+8) = __
  • __(9)=9(-9) = 9
  • __(9)=9(-9) = -9
  • __+(5)=5+(-5) = -5
  • ((__3)=33) = -3
  • -((__)=20) = 20

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Exercise 2

Solve the following exercises, first of all, remove the parentheses:

  • (5)+(+35)(22)=(-5)+(+35)-(-22) =
  • (9)(+2)+(+10)=(-9)-(+2)+(+10) =
  • (+56)+(43)(4)(+5)=(+56)+(-43)-(-4)-(+5) =
  • (12.8)(3.7)(+5)=(-12.8)-(-3.7)-(+5) =
  • (90)+(+4.7)(2.2)=(-90)+(+4.7)-(-2.2) =

Exercise 3

Assignment

Mark the correct answer

[(32+4)222]:(97)3= [(3-2+4)^2-2^2]:\frac{(\sqrt{9}\cdot7)}{3}=

Solution

We solve the expressions inside the parentheses according to the order of arithmetic operations

[(1+4)222]:(37)3= [(1+4)^2-2^2]:\frac{(3\cdot7)}{3}=

We continue solving the expressions inside the parentheses accordingly.

[5222]:213= [5^2-2^2]:\frac{21}{3}=

[254]:213= [25-4]:\frac{21}{3}=

21:7=3 21:7=3

Answer

3 3


Do you know what the answer is?

Exercise 4

Assignment

(7+2+3)(7+6)(1234)=? (7+2+3)(7+6)(12-3-4)=\text{?}

Solution

First, we solve the expressions within the parentheses according to the laws of addition and subtraction

(9+3)(7+6)(94)=? \left(9+3\right)\left(7+6\right)\left(9-4\right)=?

12×13×5=? 12\times13\times5=\text{?}

We arrange the multiplication exercise we obtained to make it easier to solve.

12×5×13=? 12\times5\times13=\text{?}

We solve the exercise from left to right

12×5=60 12\times5=60

60×13=780 60\times13=780

Answer

780 780


Exercise 5

Assignment

(9+7+3)(4+5+3)(734)\left(9+7+3\right)\left(4+5+3\right)\left(7-3-4\right)

Solution

First, we solve the expressions within the parentheses according to the laws of addition and subtraction

(9+10)(9+3)(44)= \left(9+10\right)\left(9+3\right)\left(4-4\right)=

19×12×0= 19\times12\times0=

Note that we obtained a multiplication exercise with the number 0 0 and we solve it first to simplify the calculation.

12×0=0 12\times0=0

19×0=0 19\times0=0

Answer

0 0


Check your understanding

Exercise 6

Assignment

(831)×4×3= (8-3-1)\times4\times3=

Solution

First, we solve the operations inside the parentheses according to the rules of addition and subtraction

(51)×4×3= (5-1)\times4\times3=

4×4×3= 4\times4\times3=

We solve the operation from left to right

4×4=16 4\times4=16

16×3=48 16\times3=48

Answer

48 48


Exercise 7

Assignment

(7+2)×(3+8)= (7+2)\times(3+8)=

Solution

We multiply the first element inside the parentheses by the elements of the second parentheses

Then we multiply the second element inside the primary parentheses by the elements of the second parentheses

7×3+7×8+2×3+2×8= 7\times3+7\times8+2\times3+2\times8=

We solve all the multiplication exercises from left to right

21+56+6+16= 21+56+6+16=

Now we add from left to right

21+56=77 21+56=77

77+6=83 77+6=83

83+16=99 83+16=99

Answer

99 99


Do you think you will be able to solve it?

Examples with solutions for Elimination of Parentheses in Real Numbers

Exercise #1

What is the inverse number of 0.7 0.7

Video Solution

Step-by-Step Solution

To determine the opposite number of 0.7 0.7 , we will simply change its sign, following these steps:

  • Step 1: Identify the given number, which is 0.7 0.7 .
  • Step 2: Change the sign of 0.7 0.7 to find its opposite. Since 0.7 0.7 is positive, its opposite will be negative.

By changing the sign of 0.7 0.7 , we get 0.7-0.7. Therefore, the opposite number of 0.7 0.7 is 0.7-0.7.

In conclusion, the solution to the problem is 0.7 -0.7 .

Answer

0.7 -0.7

Exercise #2

What is the additive inverse number of 87 87

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the given number
  • Step 2: Apply the definition of an opposite number
  • Step 3: Conclude with the opposite number

Now, let's work through each step with detailed explanations:
Step 1: We are given the number 87 87 . This is a positive integer.
Step 2: The definition of an opposite number states that the opposite of any number x x is x-x. Here, x=87 x = 87 .
Step 3: Using the definition, the opposite number of 87 87 is calculated as 87-87.

Therefore, the solution to the problem is 87 -87 .

Answer

87 -87

Exercise #3

What is the inverse number of 5 5

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the given number.
  • Step 2: Find its opposite by changing the sign.

Now, let's work through each step:
Step 1: The problem gives us the number 5 5 .
Step 2: The opposite of a positive number is the same number with a negative sign.
Thus, the opposite of 5 5 is 5 -5 .

Therefore, the opposite number of 5 5 is 5 -5 .

Answer

5 -5

Exercise #4

What is the inverse number of 7 -7

Video Solution

Step-by-Step Solution

To solve the problem of finding the opposite number of 7-7, we will use the concept of opposite numbers:

  • Step 1: Identify the given number, which is 7-7.
  • Step 2: Determine the opposite number by changing the sign. The opposite of 7-7 is calculated as follows:

The opposite of a negative number is its positive counterpart. So, the opposite of 7-7 is 77.

Therefore, the answer is 7 7 .

Answer

7 7

Exercise #5

(+43)(+15)= (+43)-(+15)=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the given numbers.
  • Step 2: Apply the subtraction operation.
  • Step 3: Calculate the result.

Now, let's work through each step:
Step 1: The given numbers are +43 +43 and +15 +15 .
Step 2: We need to subtract +15 +15 from +43 +43 .
Step 3: Performing this calculation gives us 4315=28 43 - 15 = 28 .

Therefore, the solution to the problem is 28 28 .

Answer

28 28

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