Commutative, Distributive and Associative Properties
The Distributive Property for 7th Grade
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What is the distributive property?
a⋅(b+c)=ab+ac
(a+b)(c+d)=ac+ad+bc+bd
The distributive property is a rule in mathematics that says that multiplying a number by the sum of two or more numbers will give us the same result as multiplying that number by the two numbers separately and then adding them together.
For example, 4x4 will give us the same result as (4x2) + (4x2).
How does this help us? Well, it allows us to distribute, or to split up a number into two or more smaller numbers that are easier to work with. When we're working with large numbers, or expressions with variables, the distributive property can save us time and a headache!
Using the distributive property, we can break down a number into two or more smaller numbers using addition or subtraction, giving us an expression that is easier to solve without changing its final value.
Here is the formula for the basic distributive property:
Z⋅(X+Y)=ZX+ZY
Z⋅(X−Y)=ZX−ZY
The distributive property: the extended version
At first, we learn to use the distributive property using expressions with only one pair of parentheses. After we feel comfortable, we can move on to the extended distributive property.
The extended distributive property is used to multiply two sets of parentheses, one by the other.
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Naturally, the distributive property is useful in school, but it's also helpful in your daily life! Splitting up a check at a restaurant? Planning a group trip? The distributive property can make your real-life calculating and planning less of a headache, and everyone will be impressed by how quickly you can get things done. From basic distribution, to complex algebraic equations, to real world dilemmas - the distributive property is a fundamental part of the math we use every day, and getting a good understanding of how and when to use it can help you go far!
The distributive property of multiplication
Let's say you have a multiplication exercise with numbers that are too large to calculate in your head.
For example: 532×8
By using the distributive property, we will be able to break it down into simpler terms to solve:
With division exercises, the concept is the same. Again, we will use the distributive property to break down large numbers, and make our work easier. Suppose we are asked to solve the following: 76:4
First, we will take the large, awkward number and round up to the next integer that is a multiple of the divisor (the number that 76 is being divided by, which is 4).
In our example, the number closest to 76 that is a multiple of 4 is 80.
So,
76:4=(80−4):4
=
80:4−4:4
=
20−1=19
And we get:
76:4=19
The extended distributive property
At first, we try to focus on simpler expressions that have only one pair of parentheses. After we have mastered these, we can move on to the extended distributive property. Now, we will start solving exercises that have more than one pair of parentheses.
For example:
(7+2)×(5+8)
We will use the extended distributive property to simplify the exercise. How?
We multiply each of the terms in the first pair of parentheses by each of the terms in the second pair of parentheses:
Examples with solutions for The Distributive Property for 7th Grade
Exercise #1
Solve the exercise:
84:4=
Video Solution
Step-by-Step Solution
There are several ways to solve the following exercise,
We will present two of them.
In both ways, we begin by decomposing the number 84 into smaller units; 80 and 4.
44=1
Subsequently we are left with only the 80.
Continuing on with the first method, we will then further decompose 80 into smaller units; 10×8
We know that:48=2
And therefore, we are able to reduce the exercise as follows: 410×8
Eventually we are left with2×10
which is equal to 20
In the second method, we decompose 80 into the following smaller units:40+40
We know that: 440=10
And therefore: 440+40=480=20=10+10
which is also equal to 20
Now, let's remember the 1 from the first step and add it in to our above answer:
20+1=21
Thus we are left with the following solution:484=21
Answer
21
Exercise #2
Solve the following exercise
?=24:12
Video Solution
Step-by-Step Solution
We will use the distributive property of division and split the number 24 into a sum of 12 and 12, which makes the division operation easier and allows us to solve the exercise without a calculator.
Note - it's best to choose to split the number based on knowledge of multiples. In this case of the number 12 because we need to divide by 12.
Reminder - The distributive property of division actually allows us to split the larger term in a division problem into a sum or difference of smaller numbers, which makes the division operation easier and allows us to solve the exercise without a calculator
We will use the formula of the distributive property
(a+b):c=a:c+b:c
24:12=(12+12):12
(12+12):12=12:12+12:12
12:12+12:12=1+1
1+1=2
Therefore the answer is section a - 2.
Answer
2
Exercise #3
Solve the following exercise
?=93:3
Video Solution
Step-by-Step Solution
We will use the distributive property of division and split the number 93 into a sum of 90 and 3, which makes the division operation easier and allows us to solve the exercise without a calculator.
Note - it's best to choose to split the number based on knowledge of multiples. In this case, we use 3 because we need to divide by 3. Additionally, in this case, splitting by tens and ones is suitable and makes the division operation easier.
Reminder - The distributive property of division essentially allows us to split the larger term in the division problem into a sum or difference of smaller numbers, which makes the division operation easier and allows us to solve the exercise without a calculator
We will use the formula of the distributive property
(a+b):c=a:c+b:c
93:3=(90+3):3
(90+3):3=90:3+3:3
90:3+3:3=30+1
30+1=31
Therefore, the answer is option B - 31.
Answer
31
Exercise #4
133+30=
Video Solution
Step-by-Step Solution
In order to solve the question, we first use the distributive property for 133:
(100+33)+30=
We then use the distributive property for 33:
100+30+3+30=
We rearrange the exercise into a more practical form:
100+30+30+3=
We solve the middle exercise:
30+30=60
Which results in the final exercise as seen below:
100+60+3=163
Answer
163
Exercise #5
140−70=
Video Solution
Step-by-Step Solution
In order to simplify the resolution process, we begin by using the distributive property for 140:
100+40−70=
We then rearrange the exercise using the substitution property into a more practical form: