The Distributive Property

🏆Practice the distributive property for 7th grade

What is the distributive property?

a(b+c)=ab+ac a \cdot (b + c) = ab + ac

(a+b)(c+d)=ac+ad+bc+bd (a+b)(c +d) =ac+ad+bc+bd

The distributive property is a rule in mathematics that says that multiplying a number by the sum of two or more numbers will give us the same result as multiplying that number by the two numbers separately and then adding them together.

For example, 4x4 will give us the same result as (4x2) + (4x2).

How does this help us? Well, it allows us to distribute, or to split up a number into two or more smaller numbers that are easier to work with. When we're working with large numbers, or expressions with variables, the distributive property can save us time and a headache!

A - What is the distributive property

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Test yourself on the distributive property for 7th grade!

einstein

Solve the exercise:

84:4=

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The distributive property: the basic version

1- Distributive property

Using the distributive property, we can break down a number into two or more smaller numbers using addition or subtraction, giving us an expression that is easier to solve without changing its final value.


Here is the formula for the basic distributive property:

Z(X+Y)=ZX+ZY Z \cdot (X + Y) = ZX + ZY

Z(XY)=ZXZY Z \cdot (X - Y) = ZX - ZY

The distributive property: the extended version

2- Distributive property

At first, we learn to use the distributive property using expressions with only one pair of parentheses. After we feel comfortable, we can move on to the extended distributive property.

The extended distributive property is used to multiply two sets of parentheses, one by the other.


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The distributive property in practice

Naturally, the distributive property is useful in school, but it's also helpful in your daily life! Splitting up a check at a restaurant? Planning a group trip? The distributive property can make your real-life calculating and planning less of a headache, and everyone will be impressed by how quickly you can get things done. From basic distribution, to complex algebraic equations, to real world dilemmas - the distributive property is a fundamental part of the math we use every day, and getting a good understanding of how and when to use it can help you go far!


The distributive property of multiplication

Let's say you have a multiplication exercise with numbers that are too large to calculate in your head.

For example: 532×8 532\times8

By using the distributive property, we will be able to break it down into simpler terms to solve:

8×532=8×(500+30+2) 8\times 532=8\times\left(500+30+2\right)

8×500=4000 8\times 500=4000

+ +

8×30=240 8\times 30=240

+ +

8×2=16 8\times2=16

= =

4000+240+16=4256 4000+240+16=4256


Do you know what the answer is?

The distributive property of division

With division exercises, the concept is the same. Again, we will use the distributive property to break down large numbers, and make our work easier. Suppose we are asked to solve the following: 76:4 76:4

First, we will take the large, awkward number and round up to the next integer that is a multiple of the divisor (the number that 76 is being divided by, which is 4).

In our example, the number closest to 76 76 that is a multiple of 4 4 is 80 80 .

So,

76:4=(804):4 76:4=\left(80-4\right):4

= =

80:44:4 80:4-4:4

= =

201=19 20-1=19

And we get:

76:4=19 76:4=19


The extended distributive property

At first, we try to focus on simpler expressions that have only one pair of parentheses. After we have mastered these, we can move on to the extended distributive property. Now, we will start solving exercises that have more than one pair of parentheses.

For example:

(7+2)×(5+8) \left(7+2\right)\times\left(5+8\right)

We will use the extended distributive property to simplify the exercise. How?

We multiply each of the terms in the first pair of parentheses by each of the terms in the second pair of parentheses:

(5+8)×(7+2) \left(5+8\right)\times\left(7+2\right)

= =

5×7+5×2+8×7+8×2 5\times7+5\times2+8\times7+8\times2

= =

35+10+56+16 35+10+56+16

= =

117 117


Check your understanding

The extended distributive property: with variables

Similarly, we can use the extended distributive property to solve equations with variables.

For example:

(X+2)(3X5) \left(X+2\right)\cdot\left(3X-5\right)

= =

(X3X)+(X5)+(23X)+(25) \left(X\cdot3X\right)+\left(X\cdot-5\right)+\left(2\cdot3X\right)+\left(2\cdot-5\right)

= =

3X25X+6X10 3X²-5X+6X-10

= =

3X2+X10 3X²+X-10


Example exercises

Exercise 1

Task:

Solve the following:

?=84:4 ?=84:4

Solution:

We distribute the number 84 into several smaller numbers.

We recommend to distribute into numbers that are easy to divide by 4, like 40, then we will divide by 4.

Therefore:

40+40+4=84 40+40+4=84

84:4=? 84:4=\text{?}

(40+40+4):4=? (40+40+4):4=\text{?}

+40:4=10 +40:4=10

+40:4=10 +40:4=10

+4:4=1 +4:4=1

Therefore: 84:4=21 84:4=21

Answer:

21 21


Do you think you will be able to solve it?

Exercise 2

Task:

Solve the following:

72:6=? 72:6=\text{?}

Solution:

We distribute the number 72 into two numbers.

We choose numbers that are easier to divide by 6.

60+12=72 60+12=72

72:6=? 72:6=\text{?}

(60+12):6= (60+12):6=

+60:6=10 +60:6=10

+12:6=2 +12:6=2

72:6= 72:6=

Answer:

12 12


Exercise 3

Task:

Solve the following:

?=65:13 ?=65:13

Solution:

We distribute 65 into 3 numbers: 26+26+13=65 26+26+13=65

Then, we divide each of them by 13:

65:13=? 65:13=\text{?}

(26+26+13):13=? (26+26+13):13=\text{?}

+26:13=2 +26:13=2

+26:13=2 +26:13=2

+13:13=1 +13:13=1

(2+2+1)=5 (2+2+1)=5

65:13=5 65:13=5

Answer:

5 5


Test your knowledge

Exercise 4

Task:

Solve the following:

742:4= 742:4=

Solution:

742:4=(700+40+2):4 742:4=(700+40+2):4

=(400+200+100+40+2):4 =(400+200+100+40+2):4

=4004+2004+1004+404+24==\frac{400}{4}+\frac{200}{4}+\frac{100}{4}+\frac{40}{4}+\frac{2}{4}=

=100+50+25+10+12=18512 =100+50+25+10+\frac{1}{2}=185\frac{1}{2}

Answer:

18512 185\frac{1}{2}


Exercise 5

Task:

Solve the following:

(3+20)×(12+4)=? (3+20)\times(12+4)=\text{?}

Solution:

(3+20)×(12+4)=3×12+3×4+20×12+20×4(3+20)\times(12+4)=3\times12+3\times4+20\times12+20\times4

=36+12+240+80=48+320=368 =36+12+240+80=48+320=368

Answer:

368 368


Do you know what the answer is?

Exercise 6

Task:

Solve the following:

(7+2+3)(7+6)(1234)=? (7+2+3)(7+6)(12-3-4)=\text{?}

Solution:

(7+2+3)(7+6)(1234)=? (7+2+3)(7+6)(12-3-4)=\text{?}

(7+2+3)×13×5=12×13×5=12×5×13(7+2+3)\times13\times5=12\times13\times5=12\times5\times13

=60×13=780 =60\times13=780

Answer:

780 780


More practice for seventh graders

Exercise 1

Task:

Solve the following exercises by using the distributive property:

  • =294:3= =294:3=
  • 105×4= 105\times4=
  • 505:5= 505:5=
  • 207×5= 207\times5=
  • 168:8= 168:8=

Solutions:

  • 294:3=(3006):3=300:36:3=1002=98 294:3=(300−6):3=300:3−6:3=100−2=98
  • 105×4=(100+5)×4=100×4+5×4=400+20=420 105\times4=(100+5)\times4=100\times4+5\times4=400+20=420
  • 505:5=(500+5):5=500:5+5:5=100+1=101 505:5=(500+5):5=500:5+5:5=100+1=101
  • 207×5=(200+7)×5=200×5+7×5=1000+35=1035 207\times5=(200+7)\times5=200\times5+7\times5=1000+35=1035
  • 168:8=(160+8):8=160:8+8:8=20+1=21 168:8=(160+8):8=160:8+8:8=20+1=21


Check your understanding

Exercise 2

Task:

351 351 students in a school were divided equally into 9 9 classes.

How many students are there in each class?

Answer by making use of the distributive property.

Solution:

First, let's write the expression:

351:9=(3609):9=360:99:9=401=39 351:9=(360−9):9=360:9−9:9=40−1=39

Answer:

In each of the classes there are 39 39 students.


Exercise 3

Task:

Dani bought 15 15 packages. In each package there were 9 9 pieces of candy.

How many pieces of candy did Dani buy in total?

Find the answer using the distributive property.

Solution:

Let's write out the exercise:

15×9=(10+5)×9=10×9+5×9=90+45=135 15\times9=(10+5)\times9=10\times9+5\times9=90+45=135

Answer:

Dani bought 135 pieces of candy in total.


Do you think you will be able to solve it?

Exercise 4

Task:

Laura packed 246 246 notebooks into 6 6 equal packages.

How many notebooks did Laura put in each package?

Use the distributive property.

Solution:

Let's write the exercise:

246:6=(240+6):6=240:6+6:6=40+1=41 246:6=(240+6):6=240:6+6:6=40+1=41

Answer:

Laura packed 41 41 notebooks in each package.


Exercise 5

Task:

A mother had $894 894 . She divided the money equally among her three children.

How much money did each child receive?

Find the answer by using the distributive property.

Solution:

Let's write out the exercise:

894:3=(9006):3=900:36:3=3002=298 894:3=(900−6):3=900:3−6:3=300−2=298

Answer:

Each of the children received $298 298 .


Task:

Use the distributive property to solve the following exercises:

  • 187(85)=187(85)= 187\cdot(8-5)=187⋅(8−5)=
  • (10+5+18)4=(10+5+18)4= (10+5+18)\cdot4=(10+5+18)⋅4=
  • (5.50.8)5=(5.50.8)5= (5.5-0.8)\cdot5=(5.5−0.8)⋅5=
  • 340:(127)=340:(127)= 340:(12-7)=340:(12−7)=
  • (294):5=(294):5= (29-4):5=(29−4):5=
  • 15:(6+15)=15:(6+15)= 15:(6+1-5)=15​:(6+1−5)=
  • 18:(5+7+4)=18:(5+7+4)= 18:(5+7+4)=18:(5+7+4)=
  • (7131):4=(7131):4= (71-31):4=(71​−31​):4=
  • 9712=9712= 97\cdot12=97⋅12=
  • 336=336= 3\cdot36=3⋅36=
  • 120:97=120:97= 120:97=120:97=
  • 8:21=8:21= 8:21=8:21​=
  • 15123=15123= 151\cdot23=151⋅23=

Test your knowledge

Examples with solutions for The Distributive Property for 7th Grade

Exercise #1

Solve the exercise:

84:4=

Video Solution

Step-by-Step Solution

There are several ways to solve the following exercise,

We will present two of them.

In both ways, we begin by decomposing the number 84 into smaller units; 80 and 4.

44=1 \frac{4}{4}=1

Subsequently we are left with only the 80.

 

Continuing on with the first method, we will then further decompose 80 into smaller units; 10×8 10\times8

We know that:84=2 \frac{8}{4}=2

And therefore, we are able to reduce the exercise as follows: 104×8 \frac{10}{4}\times8

Eventually we are left with2×10 2\times10

which is equal to 20

In the second method, we decompose 80 into the following smaller units:40+40 40+40

We know that: 404=10 \frac{40}{4}=10

And therefore: 40+404=804=20=10+10 \frac{40+40}{4}=\frac{80}{4}=20=10+10

which is also equal to 20

Now, let's remember the 1 from the first step and add it in to our above answer:

20+1=21 20+1=21

Thus we are left with the following solution:844=21 \frac{84}{4}=21

Answer

21

Exercise #2

Solve the following exercise

?=24:12

Video Solution

Step-by-Step Solution

We will use the distributive property of division and split the number 24 into a sum of 12 and 12, which makes the division operation easier and allows us to solve the exercise without a calculator.

Note - it's best to choose to split the number based on knowledge of multiples. In this case of the number 12 because we need to divide by 12.

Reminder - The distributive property of division actually allows us to split the larger term in a division problem into a sum or difference of smaller numbers, which makes the division operation easier and allows us to solve the exercise without a calculator

We will use the formula of the distributive property

 (a+b):c=a:c+b:c 

24:12=(12+12):12 24:12=(12+12):12

(12+12):12=12:12+12:12 (12+12):12=12:12+12:12

12:12+12:12=1+1 12:12+12:12=1+1

1+1=2 1+1=2

Therefore the answer is section a - 2.

Answer

2

Exercise #3

Solve the following exercise

?=93:3

Video Solution

Step-by-Step Solution

We will use the distributive property of division and split the number 93 into a sum of 90 and 3, which makes the division operation easier and allows us to solve the exercise without a calculator.

Note - it's best to choose to split the number based on knowledge of multiples. In this case, we use 3 because we need to divide by 3. Additionally, in this case, splitting by tens and ones is suitable and makes the division operation easier.

Reminder - The distributive property of division essentially allows us to split the larger term in the division problem into a sum or difference of smaller numbers, which makes the division operation easier and allows us to solve the exercise without a calculator

We will use the formula of the distributive property

 (a+b):c=a:c+b:c 

93:3=(90+3):3 93:3=(90+3):3

(90+3):3=90:3+3:3 (90+3):3=90:3+3:3

90:3+3:3=30+1 90:3+3:3=30+1

30+1=31 30+1=31

Therefore, the answer is option B - 31.

Answer

31

Exercise #4

133+30= 133+30=

Video Solution

Step-by-Step Solution

In order to solve the question, we first use the distributive property for 133:

(100+33)+30= (100+33)+30=

We then use the distributive property for 33:

100+30+3+30= 100+30+3+30=

We rearrange the exercise into a more practical form:

100+30+30+3= 100+30+30+3=

We solve the middle exercise:

30+30=60 30+30=60

Which results in the final exercise as seen below:

100+60+3=163 100+60+3=163

Answer

163

Exercise #5

14070= 140-70=

Video Solution

Step-by-Step Solution

In order to simplify the resolution process, we begin by using the distributive property for 140:

100+4070= 100+40-70=

We then rearrange the exercise using the substitution property into a more practical form:

10070+40= 100-70+40=

Lastly we solve the exercise from left to right:

10070=30 100-70=30

30+40=70 30+40=70

Answer

70

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