Order or Hierarchy of Operations with Fractions

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Order or Hierarchy of Operations with Fractions

Fractions do not influence the order of operations, therefore, you should treat them like any other number in the exercise.

The correct order of mathematical operations is as follows:

  1. Parentheses
  2. Multiplications and divisions in the order they appear in the exercise
  3. Additions and subtractions in the order they appear in the exercise

Comprehensive explanation of BODMAS/PEMDAS rules with additional notes: fraction bars treated as parentheses and inclusion of reciprocal numbers, detailing brackets, order, division, multiplication, addition, and subtraction in mathematical operations.

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\( 8\times(5\times1)= \)

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Order or Hierarchy of Operations with Fractions

The order of mathematical operations with fractions is no different from the order of operations without fractions.
This means that if you know how to correctly solve a certain exercise based on the order of mathematical operations, you will also know how to solve an exercise with fractions in the same way.
Let's remember the order of operations:

  1. Parentheses - We always start by solving what is inside the parentheses, regardless of the type of operation it is.
  2. Multiplications and divisions – The exercise is read from left to right. Multiplications and divisions have the same hierarchy, therefore, we will resolve them according to their order of appearance in the exercise, from left to right.
  3. Additions and subtractions - After having solved the operations that were in parentheses and those of multiplying and dividing, we will continue with addition and subtraction.
    They also share the same hierarchy, therefore, we will resolve them according to their order of appearance in the exercise, from left to right.

Note - We have not given any importance to fractions, nor have we mentioned them.
We will treat fractions like any other number, whether it is a common fraction or a decimal number, it's all the same.


Examples

Exercise 1

3+6Γ—13=3+6 \times \frac{1}{3}=

Solution:

Multiplication comes before addition, therefore, we will first solve all the multiplications.
We will obtain:

3+633+\frac{6}{3}
Now we will add and get:
3+2=53+2=5


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Exercise 2

25Γ—(1+3)+4=\frac{2}{5} \times (1+3)+4=

Solution:
Parentheses come first, so we will start by solving what's inside them.

We will obtain:
25Γ—4+4=\frac{2}{5} \times 4+4=
Multiplication comes before addition, so we will continue with the multiplication.

We will obtain:
85+4\frac{8}{5}+4
Now we will add and get:

485=5354\frac{8}{5}=5\frac{3}{5}


Exercise 3

0.3+(0.4+0.1)Γ—4=0.3+(0.4+0.1) \times 4=

Solution:

We will start with the expression inside the parentheses.

We will solve and obtain:
0.3+0.5Γ—4=0.3+0.5 \times 4=

Multiplication is resolved before addition, so we will continue with it.

We will obtain:

0.3+2=0.3+2=

We will add and get:

0.3+2=2.30.3+2=2.3


Do you know what the answer is?

Exercise 4

8βˆ’9:18Γ—6+5=8-9:18 \times 6+5=

Solution:

We know that if there are no parentheses we start with multiplication and division.
But in what order?
According to the order of appearance in the exercise, from left to right.
We start reading the exercise and we come across a division, therefore, we will start with it.

We will obtain:

8βˆ’918Γ—6+5=8-\frac{9}{18} \times 6+5=

We will continue with the multiplication. We will realize that 9189 \over 18Β is, in fact, 121 \over 2
We will obtain:
8βˆ’12Γ—6+5=8-\frac{1}{2} \times 6+5=

8βˆ’3+5=8-3+5=

Now we will continue with the addition and subtraction operations according to the order of appearance.
When we start reading the exercise from the beginning we come across a subtraction, therefore, we will resolve it first. We will obtain:

5+5=105+5=10


Exercise 5

5Γ—3βˆ’48Γ—2βˆ’3=5 \times 3-\frac{4}{8} \times 2-3=

Solution:

There are no parentheses, so we will start with the multiplication and division operations according to their order of appearance in the exercise.
We will start with the first multiplication on the left.

We will obtain:

15βˆ’48Γ—2βˆ’3=15-\frac{4}{8} \times 2-3=

We will continue with the next multiplication and obtain:

15βˆ’88βˆ’3=15-\frac{8}{8}-3=

We will realize that 888 \over 8Β is 11.

We will subtract from left to right according to the order of appearance and obtain:

15βˆ’1βˆ’3=15-1-3=

14βˆ’3=1114-3=11


Check your understanding

Examples with solutions for Order or Hierarchy of Operations with Fractions

Exercise #1

8Γ—(5Γ—1)= 8\times(5\times1)=

Video Solution

Step-by-Step Solution

According to the order of operations, we first solve the expression in parentheses:

5Γ—1=5 5\times1=5

Now we multiply:

8Γ—5=40 8\times5=40

Answer

40

Exercise #2

7Γ—1+12=Β ? 7\times1+\frac{1}{2}=\text{ ?}

Video Solution

Step-by-Step Solution

According to the order of operations, we first place the multiplication operation inside parenthesis:

(7Γ—1)+12= (7\times1)+\frac{1}{2}=

Then, we perform this operation:

7Γ—1=7 7\times1=7

Finally, we are left with the answer:

7+12=712 7+\frac{1}{2}=7\frac{1}{2}

Answer

712 7\frac{1}{2}

Exercise #3

63Γ—1=Β ? \frac{6}{3}\times1=\text{ ?}

Video Solution

Step-by-Step Solution

According to the order of operations, we will solve the exercise from left to right since it only contains multiplication and division operations:

63=2 \frac{6}{3}=2

2Γ—1=2 2\times1=2

Answer

2 2

Exercise #4

(3Γ—5βˆ’15Γ—1)+3βˆ’2= (3\times5-15\times1)+3-2=

Video Solution

Step-by-Step Solution

This simple rule is the order of operations which states that exponentiation precedes multiplication and division, which precede addition and subtraction, and that operations enclosed in parentheses precede all others,

Following the simple rule, multiplication comes before division and subtraction, therefore we calculate the values of the multiplications and then proceed with the operations of division and subtraction

3β‹…5βˆ’15β‹…1+3βˆ’2=15βˆ’15+3βˆ’2=1 3\cdot5-15\cdot1+3-2= \\ 15-15+3-2= \\ 1 Therefore, the correct answer is answer B.

Answer

1 1

Exercise #5

(5Γ—4βˆ’10Γ—2)Γ—(3βˆ’5)= (5\times4-10\times2)\times(3-5)=

Video Solution

Step-by-Step Solution

This simple rule is the order of operations which states that multiplication precedes addition and subtraction, and division precedes all of them,

In the given example, a multiplication occurs between two sets of parentheses, thus we simplify the expressions within each pair of parentheses separately,

We start with simplifying the expression within the parentheses on the left, this is done in accordance with the order of operations mentioned above, meaning that multiplication comes before subtraction, we perform the multiplications in this expression first and then proceed with the subtraction operations within it, in reverse we simplify the expression within the parentheses on the right and perform the subtraction operation within them:

What remains for us is to perform the last multiplication that was deferred, it is the multiplication that occurred between the expressions within the parentheses in the original expression, we perform it while remembering that multiplying any number by 0 will result in 0:

Therefore, the correct answer is answer d.

Answer

0 0

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