Order of Operations: Exponents

πŸ†Practice powers and roots

As part of combined operations, we learned that parentheses always come first.

Once solved, we can begin to simplify powers (or roots).

After simplifying them, we can continue solving the exercise according to the order of basic operations:

Firstly, the multiplications and divisions, and lastly, the additions and subtractions.

Let's refresh the order of operations:

  1. Parentheses
  2. Powers and roots
  3. Multiplications and divisions
  4. Additions and subtractions
Detailed explanation of the BODMAS/PEMDAS rule highlighting 'Order' (Exponents) with symbols like √x and x², crucial for solving complex arithmetic expressions step by step.

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Test yourself on powers and roots!

einstein

\( 6+\sqrt{64}-4= \)

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In the event that we have an exercise with parentheses that are within other parentheses, we will first solve the inner parentheses and then move on to the outer parentheses.

Let's take a look at the following exercise with combined operations and see it step by step.

For example, Exercise 1

2+5β‹…42β‹…(3βˆ’1)=2 + 5 \cdot 4^2 \cdot (3-1) =

First, we perform the operations inside the parentheses. Once done, we obtain the following:
2+5β‹…42β‹…2=2 + 5 \cdot 4^2 \cdot 2 =

Note that we have a combined operation involving powers, multiplications, and additions, so we proceed to solve the power.

Once done, we obtain:
2+5β‹…16β‹…2=2+5 \cdot16 \cdot 2 =

Now it's time to solve the multiplications (remember: from left to right):
​​2+80β‹…2=​​2+80\cdot2=,2+160=​​2+160=​​

Lastly, we add:
2+160=1622+160=162


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Exercise 2

Now we will do the same exercise, but with a small variation.

2+5β‹…42β‹…(32βˆ’1)=2 + 5 \cdot 4^2 \cdot (3^2-1) =

First, we must solve the operation inside the parentheses, where there is a power and a subtraction, so following the order of operations we calculate the power and then the subtraction.

2+5β‹…42β‹…(32βˆ’1)=2 + 5 \cdot 4^2 \cdot (3^2-1) =

2+5β‹…42β‹…(9βˆ’1)=2 + 5 \cdot 4^2 \cdot (9-1) =

Now we can proceed with solving the exercise just as we have been doing so far.

2+5β‹…42β‹…8=2 + 5 \cdot 4^2 \cdot 8 =

2+5β‹…16β‹…8=2 + 5 \cdot 16 \cdot 8 =

2+80β‹…8=2 + 80 \cdot 8 =

2+640=6422 + 640 = 642


Exercise 3

(23+42)+8β‹…(92βˆ’1)= (23+4^2)+8\cdot(9^2-1)=

We solve the operations within each parenthesis, applying the order of operations within them.

(23+16)+8β‹…(81βˆ’1)= (23+16)+8\cdot(81-1)=

Now is the time to solve the multiplications (we remember: from left to right):

39+8β‹…80= 39+8\cdot80=

39+640= 39+640=

Lastly, we add:
39+640=679 39+640=679

Remember that the order of operations will always be the same, even when combined operations with fractions appear.


Do you know what the answer is?

Combined Operations Exercises

Basic Example 4

4+22=4+2^2=

First, the powers

4+4=4+4=

Lastly, we add

4+4=8 4+4=8


Basic Example 5

4+2+52=4+2+5^2=

First, the powers

4+2+25=4+2+25=

Lastly, we add

4+2+25=314+2+25=31


Check your understanding

Basic Example 6

5+5βˆ’52+42=5+5-5^2+4^2=

First, the powers

5+5βˆ’25+16=5+5-25+16=

Lastly, we add

5+5βˆ’25+16=1 5+5-25+16=1


Exercises to Practice the Order of Basic Operations (Powers)

  • 3β‹…3+32=3 \cdot3+3^2=
  • (3+1)2βˆ’(4+1)=(3+1)^2-(4+1)=
  • 10:2βˆ’22=10:2-2^2=
  • 100:52+32=100:5^2+3^2=
  • 53:52β‹…23=5^3:5^2\cdot2^3=
  • 0:22β‹…110+30:2^2\cdot1^{10}+3
  • (14)2+116=({1\over4})^2+{1\over16}=
  • (12)2+(13)2+14=({1\over2})^2+({1\over3})^2+{1\over4}=
  • 8βˆ’32:3=8-3^2:3=
  • (2+1β‹…2)2=(2+1 \cdot2)^2=
  • (20βˆ’3β‹…22)2=(20-3 \cdot2^2)^2=
  • (15+9:3βˆ’42)2=(15+9:3-4^2)^2=
  • [(4βˆ’22)]3=[(4-2^2)]^3=
  • 5+82=5+8^2=
  • 26+3=2^6+3=
  • 12βˆ’32=12-3^2=
  • 22βˆ’34=22-3^4=
  • (13)2β‹…60=({1\over3})^2\cdot60=
  • 7βˆ’8β‹…2βˆ’32=7-8 \cdot 2-3^2=
  • 25β‹…[(12)2+22]=25\cdot[({1\over2})^2+2^2]=
  • 27.5+1.53β‹…6=27.5+1.5^3\cdot6=
  • 0.22β‹…5=0.2^2\cdot5=
  • (6βˆ’6)β‹…22=(6-6)\cdot2^2=
  • 1+202β‹…15=1+20^2\cdot{1\over5}=

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Review Questions

What is the order of operations when there are exponents and powers?

Exponents and roots should always be performed before multiplication or division; and before addition or subtraction.


What is the correct order of mathematical operations?

When working with combined operations that include parentheses, exponents and roots, multiplications and divisions, as well as additions and subtractions, we must use the order of operations which indicates the sequence in which we should perform the operations.

  • Parentheses are solved first. If there are parentheses within other parentheses, we solve the inner ones first and then the outer ones.
  • Exponents and roots are solved next.
  • Multiplications and divisions are solved (from left to right).
  • Additions and subtractions are solved (from left to right).

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What Are Operations with Powers?

Powers are used to abbreviate the multiplication of a number (called the base) by itself, a certain number β€œn” of times.

When we have combined basic operations that include powers, we must remember that powers are to be resolved after the parentheses.


How to Solve Order of Operations with Exponents?

We solve the parentheses, and subsequently we raise the bases to the indicated exponent, this is done by multiplying it by itself, as many times as the exponent indicates.


Do you know what the answer is?

Examples with solutions for Order of Operations: (Exponents)

Exercise #1

6+64βˆ’4= 6+\sqrt{64}-4=

Video Solution

Step-by-Step Solution

To solve the expression 6+64βˆ’4= 6+\sqrt{64}-4= , we need to follow the order of operations (PEMDAS/BODMAS):


  • P: Parentheses (or Brackets)
  • E: Exponents (or Orders, i.e., powers and roots, etc.)
  • MD: Multiplication and Division (left-to-right)
  • AS: Addition and Subtraction (left-to-right)

In this expression, we first need to evaluate the square root since it falls under the exponent category:


64=8 \sqrt{64} = 8


Next, we substitute the computed value back into the expression:


6+8βˆ’4 6+8-4


We then perform the addition and subtraction from left to right:


6+8=14 6+8 = 14


14βˆ’4=10 14-4 = 10


Thus, the final answer is:


10 10

Answer

10

Exercise #2

10:2βˆ’22= 10:2-2^2=

Video Solution

Step-by-Step Solution

The given mathematical expression is 10:2βˆ’22 10:2-2^2 .

According to the order of operations (often remembered by the acronym PEMDAS/BODMAS), we perform calculations in the following sequence:

  • Parentheses/Brackets
  • Exponents/Orders (i.e., powers and roots)
  • Multiplication and Division (from left to right)
  • Addition and Subtraction (from left to right)

In this expression, there are no parentheses, but there is an exponent: 222^2. We calculate the exponent first:

22=42^2 = 4

Substituting back into the expression, we have:

10:2βˆ’4 10:2-4

Next, we perform the division from left to right. Here, ":" is interpreted as division:

10Γ·2=5 10 \div 2 = 5

Now, substitute this back into the expression:

5βˆ’4 5 - 4

The final step is to perform the subtraction:

5βˆ’4=1 5 - 4 = 1

Therefore, the answer is 1 1 .

Answer

1

Exercise #3

3Γ—3+32=Β ? 3\times3+3^2=\text{ ?}

Video Solution

Step-by-Step Solution

First we need to remind ourselves of the order of operations:

  1. Parentheses

  2. Exponents and Roots

  3. Multiplication and Division

  4. Addition and Subtraction

There are no parentheses in this problem, therefore we will start with exponents:

3 * 3 + 3Β² =

3 * 3 + 9 =

Let's continue to the next stepβ€”multiplication operations:

3 * 3 + 9 =

9 + 9 =

Finally, we are left with a simple addition exercise:

9 + 9 = 18

Answer

18

Exercise #4

8βˆ’32:3= 8-3^2:3=

Video Solution

Step-by-Step Solution

Let's solve the expression step by step using the order of operations, often remembered by the acronym PEMDAS, which stands for Parentheses, Exponents, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right).

The given expression is: 8βˆ’32:3= 8-3^2:3=

Step 1: Evaluate Exponents
The expression has an exponent, which we need to evaluate first. The exponent is 323^2.
Calculate 323^2 which equals 99.
Now the expression becomes: 8βˆ’9:3 8 - 9 : 3

Step 2: Division
Next, perform the division operation. Here we divide 99 by 33.
Calculate 9:39 : 3 which equals 33.
Now the expression becomes: 8βˆ’3 8 - 3

Step 3: Subtraction
Finally, perform the subtraction.
Calculate 8βˆ’38 - 3 which equals 55.

Therefore, the solution to the expression 8βˆ’32:38-3^2:3 is 55.

Answer

5 5

Exercise #5

4+2+52= 4+2+5^2=

Video Solution

Step-by-Step Solution

To solve the expression 4+2+52 4 + 2 + 5^2 , we need to follow the order of operations, often remembered by the acronym PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).

  • Step 1: Calculate Exponents
    In the expression we have an exponent: 525^2. This means 5 is raised to the power of 2. We calculate this first:
    52=255^2 = 25.

  • Step 2: Perform Addition
    Now, substitute the calculated value back into the expression:
    4+2+254 + 2 + 25.
    Perform the additions from left to right:
    4+2=64 + 2 = 6
    Finally add the result to 25:
    6+25=316 + 25 = 31.

Therefore, the final answer is 3131.

Answer

31

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