Order of Operations: Exponents

๐Ÿ†Practice powers and roots

As part of combined operations, we learned that parentheses always come first.

Once solved, we can begin to simplify powers (or roots).

After simplifying them, we can continue solving the exercise according to the order of basic operations:

Firstly, the multiplications and divisions, and lastly, the additions and subtractions.

Let's refresh the order of operations:

  1. Parentheses
  2. Powers and roots
  3. Multiplications and divisions
  4. Additions and subtractions
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Test yourself on powers and roots!

einstein

\( 10:2-2^2= \)

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In the event that we have an exercise with parentheses that are within other parentheses, we will first solve the inner parentheses and then move on to the outer parentheses.

Let's take a look at the following exercise with combined operations and see it step by step.

For example, Exercise 1

2+5โ‹…42โ‹…(3โˆ’1)=2 + 5 \cdot 4^2 \cdot (3-1) =

First, we perform the operations inside the parentheses. Once done, we obtain the following:
2+5โ‹…42โ‹…2=2 + 5 \cdot 4^2 \cdot 2 =

Note that we have a combined operation involving powers, multiplications, and additions, so we proceed to solve the power.

Once done, we obtain:
2+5โ‹…16โ‹…2=2+5 \cdot16 \cdot 2 =

Now it's time to solve the multiplications (remember: from left to right):
โ€‹โ€‹2+80โ‹…2=โ€‹โ€‹2+80\cdot2=,2+160=โ€‹โ€‹2+160=โ€‹โ€‹

Lastly, we add:
2+160=1622+160=162


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Exercise 2

Now we will do the same exercise, but with a small variation.

2+5โ‹…42โ‹…(32โˆ’1)=2 + 5 \cdot 4^2 \cdot (3^2-1) =

First, we must solve the operation inside the parentheses, where there is a power and a subtraction, so following the order of operations we calculate the power and then the subtraction.

2+5โ‹…42โ‹…(32โˆ’1)=2 + 5 \cdot 4^2 \cdot (3^2-1) =

2+5โ‹…42โ‹…(9โˆ’1)=2 + 5 \cdot 4^2 \cdot (9-1) =

Now we can proceed with solving the exercise just as we have been doing so far.

2+5โ‹…42โ‹…8=2 + 5 \cdot 4^2 \cdot 8 =

2+5โ‹…16โ‹…8=2 + 5 \cdot 16 \cdot 8 =

2+80โ‹…8=2 + 80 \cdot 8 =

2+640=6422 + 640 = 642


Exercise 3

(23+42)+8โ‹…(92โˆ’1)= (23+4^2)+8\cdot(9^2-1)=

We solve the operations within each parenthesis, applying the order of operations within them.

(23+16)+8โ‹…(81โˆ’1)= (23+16)+8\cdot(81-1)=

Now is the time to solve the multiplications (we remember: from left to right):

39+8โ‹…80= 39+8\cdot80=

39+640= 39+640=

Lastly, we add:
39+640=679 39+640=679

Remember that the order of operations will always be the same, even when combined operations with fractions appear.


Do you know what the answer is?

Combined Operations Exercises

Basic Example 4

4+22=4+2^2=

First, the powers

4+4=4+4=

Lastly, we add

4+4=8 4+4=8


Basic Example 5

4+2+52=4+2+5^2=

First, the powers

4+2+25=4+2+25=

Lastly, we add

4+2+25=314+2+25=31


Check your understanding

Basic Example 6

5+5โˆ’52+42=5+5-5^2+4^2=

First, the powers

5+5โˆ’25+16=5+5-25+16=

Lastly, we add

5+5โˆ’25+16=1 5+5-25+16=1


Exercises to Practice the Order of Basic Operations (Powers)

  • 3โ‹…3+32=3 \cdot3+3^2=
  • (3+1)2โˆ’(4+1)=(3+1)^2-(4+1)=
  • 10:2โˆ’22=10:2-2^2=
  • 100:52+32=100:5^2+3^2=
  • 53:52โ‹…23=5^3:5^2\cdot2^3=
  • 0:22โ‹…110+30:2^2\cdot1^{10}+3
  • (14)2+116=({1\over4})^2+{1\over16}=
  • (12)2+(13)2+14=({1\over2})^2+({1\over3})^2+{1\over4}=
  • 8โˆ’32:3=8-3^2:3=
  • (2+1โ‹…2)2=(2+1 \cdot2)^2=
  • (20โˆ’3โ‹…22)2=(20-3 \cdot2^2)^2=
  • (15+9:3โˆ’42)2=(15+9:3-4^2)^2=
  • [(4โˆ’22)]3=[(4-2^2)]^3=
  • 5+82=5+8^2=
  • 26+3=2^6+3=
  • 12โˆ’32=12-3^2=
  • 22โˆ’34=22-3^4=
  • (13)2โ‹…60=({1\over3})^2\cdot60=
  • 7โˆ’8โ‹…2โˆ’32=7-8 \cdot 2-3^2=
  • 25โ‹…[(12)2+22]=25\cdot[({1\over2})^2+2^2]=
  • 27.5+1.53โ‹…6=27.5+1.5^3\cdot6=
  • 0.22โ‹…5=0.2^2\cdot5=
  • (6โˆ’6)โ‹…22=(6-6)\cdot2^2=
  • 1+202โ‹…15=1+20^2\cdot{1\over5}=

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Review Questions

What is the order of operations when there are exponents and powers?

Exponents and roots should always be performed before multiplication or division; and before addition or subtraction.


What is the correct order of mathematical operations?

When working with combined operations that include parentheses, exponents and roots, multiplications and divisions, as well as additions and subtractions, we must use the order of operations which indicates the sequence in which we should perform the operations.

  • Parentheses are solved first. If there are parentheses within other parentheses, we solve the inner ones first and then the outer ones.
  • Exponents and roots are solved next.
  • Multiplications and divisions are solved (from left to right).
  • Additions and subtractions are solved (from left to right).

Test your knowledge

What Are Operations with Powers?

Powers are used to abbreviate the multiplication of a number (called the base) by itself, a certain number โ€œnโ€ of times.

When we have combined basic operations that include powers, we must remember that powers are to be resolved after the parentheses.


How to Solve Order of Operations with Exponents?

We solve the parentheses, and subsequently we raise the bases to the indicated exponent, this is done by multiplying it by itself, as many times as the exponent indicates.


Do you know what the answer is?

Examples with solutions for Order of Operations: (Exponents)

Exercise #1

10:2โˆ’22= 10:2-2^2=

Video Solution

Step-by-Step Solution

The given mathematical expression is 10:2โˆ’22 10:2-2^2 .

According to the order of operations (often remembered by the acronym PEMDAS/BODMAS), we perform calculations in the following sequence:

  • Parentheses/Brackets
  • Exponents/Orders (i.e., powers and roots)
  • Multiplication and Division (from left to right)
  • Addition and Subtraction (from left to right)

In this expression, there are no parentheses, but there is an exponent: 222^2. We calculate the exponent first:

22=42^2 = 4

Substituting back into the expression, we have:

10:2โˆ’4 10:2-4

Next, we perform the division from left to right. Here, ":" is interpreted as division:

10รท2=5 10 \div 2 = 5

Now, substitute this back into the expression:

5โˆ’4 5 - 4

The final step is to perform the subtraction:

5โˆ’4=1 5 - 4 = 1

Therefore, the answer is 1 1 .

Answer

1

Exercise #2

10โˆ’52:5= 10-5^2:5=

Step-by-Step Solution

First, compute the power: 52=25 5^2 = 25 .

Next, divide: 25รท5=5 25 \div 5 = 5 .

Finally, subtract: 10โˆ’5=5 10 - 5 = 5 .

Answer

5 5

Exercise #3

15โˆ’42:2= 15-4^2:2=

Step-by-Step Solution

First, compute the power: 42=16 4^2 = 16 .

Next, divide: 16รท2=8 16 \div 2 = 8 .

Finally, subtract: 15โˆ’8=7 15 - 8 = 7 .

Answer

7 7

Exercise #4

20โˆ’33:3= 20-3^3:3=

Step-by-Step Solution

First, compute the power: 33=27 3^3 = 27 .

Next, divide: 27รท3=9 27 \div 3 = 9 .

Finally, subtract: 20โˆ’9=11 20 - 9 = 11 .

Answer

11 11

Exercise #5

3ร—2+81= 3 \times 2 + \sqrt{81} =

Step-by-Step Solution

First, evaluate the square root: 81=9\sqrt{81}=9.

Then, follow the order of operations (PEMDAS/BODMAS):

1. Multiplication: 3ร—2=63 \times 2 = 6

2. Addition: 6+9=156 + 9 = 15

So, the correct answer is 15 15 .

Answer

15 15

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