The distributive property of multiplication allows us to break down the highest term of the exercise into a smaller number. This simplifies the multiplication operation and we can solve the exercise without the need to use a calculator.
The distributive property of multiplication allows us to break down the highest term of the exercise into a smaller number. This simplifies the multiplication operation and we can solve the exercise without the need to use a calculator.
Let's assume we have an exercise with a multiplication that is simple, but with large numbers, for example:
Thanks to the distributive property, we can break it down into simpler exercises:
+
+
=
Solve the exercise:
84:4=
Assignment:
Solution:
We break down into numbers divisible by
We arrange the exercise into simple fractions
We divide accordingly
Answer:
Solve the following exercise
?=24:12
Solve the following exercise
?=93:3
\( 94+72= \)
Assignment:
What expression is equivalent to the exercise ?
Solution:
We break down the exercise into 2 multiplication operations to facilitate the calculation
Answer:
Then subtract 3
Assignment:
Solution:
First, we multiply the element inside the parentheses by
To facilitate the calculation, we break down into numbers and the rest of the exercise can be multiplied
First, we solve the parentheses
Now we add and subtract accordingly
Answer:
\( 63-36= \)
\( 143-43= \)
\( 133+30= \)
Assignment:
Solution:
We break down into numbers to make the calculation easier
We solve the exercise accordingly
Answer:
Assignment:
Solution:
We break down into numbers to make the calculation easier
We solve the exercise accordingly
Answer:
\( 140-70= \)
Solve the following exercise
=90:5
Solve:
\( 72:6= \)
The distributive property of multiplication over addition or subtraction is the property that helps us simplify and more easily carry out an operation where it is expressed with grouping symbols and related to the order of operations. We can express it as:
Distributive property of multiplication over addition.
Distributive property of multiplication over subtraction.
Just like the distributive property of multiplication, the distributive property of division with respect to addition and subtraction helps us to simplify an operation, and it can be expressed as:
Solve the exercise:
=102:2
Solve the exercise:
=74:4
\( 35\times4= \)
P
Assignment
Answer
Assignment
We can break down in the following way:
We apply the distributive property of multiplication
Answer
Assignment
Applying the distributive property of division
Result
Assignment
We break down the into two numbers
We apply the distributive law of division with respect to subtraction
Answer
\( 74\times8= \)
\( 480\times3= \)
Solve the exercise:
84:4=
In order to simplify the calculation , we first break down 94 and 72 into smaller and preferably round numbers.
We obtain the following exercise:
Using the associative property, we then rearrange the exercise to be more functional.
We solve the exercise in the following way, first the round numbers and then the small numbers.
Which results in the following exercise:
166
To solve the problem, first we will use the distributive property on the two numbers:
(60+3)-(30+6)
Now, we will use the substitution property to arrange the exercise in the way that is most convenient for us to solve:
60-30+3-6
It is important to pay attention that when we open the second parentheses, the minus sign moved to the two numbers inside.
30-3 =
27
27
We will use the distributive law and split the number 143 into a sum of 100 and 43.
The distributive law allows us to distribute, meaning, to split a number into two or more numbers. This actually allows us to work with smaller numbers and simplify the operation.
We will operate according to the order of operations
We can remove parentheses and perform addition and subtraction operations in any order since there are only addition and subtraction operations in the equation
Therefore, the answer is option C - 100.
And now let's see the solution to the exercise in a centered format:
100
In order to solve the question, we first use the distributive property for 133:
We then use the distributive property for 33:
We rearrange the exercise into a more practical form:
We solve the middle exercise:
Which results in the final exercise as seen below:
163
In order to simplify the resolution process, we begin by using the distributive property for 140:
We then rearrange the exercise using the substitution property into a more practical form:
Lastly we solve the exercise from left to right:
70