Solving Equations by Simplifying Like Terms

๐Ÿ†Practice simplifying and combining like terms

Simplifying Like Terms in an Equation

When solving equations, simplifying like termsโ€”terms with the same variable and exponentโ€”makes the equation easier to solve by consolidating similar elements. Simplify the like terms in an equation involves combining the elements that belong to the same group. In other words: in all first-degree equations with one unknown, there are elements that belong to the group of unknowns (variables) and elements that belong to the group of numbers. The goal is to unite all the elements of each of the mentioned groups into respective sides to thus arrive at the result of the equation.

In order to so we need to follow these two steps:
  • Identify Like Terms: Locate terms with identical variable parts on each side of the equation.
  • Combine Terms: Add or subtract coefficients of like terms to simplify each side.

For example

X+2X=5+1 X+2X=5+1

In this equation, we can clearly see that the elements X X and 2X 2X belong to the group of unknowns, and therefore, we can combine them.

Conversely, the elements 5 5 and 1 1 belong to the group of numbers and thus can also be combined.ย 

3X=6 3X=6

X=2 X=2

The result of the equation is 2 2 .


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Test yourself on simplifying and combining like terms!

einstein

\( -16+a=-17 \)

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Below, we provide you with some examples where we apply this method.

Example 1

6Xโˆ’1=5X+5 6X-1=5X+5

In this equation, we can clearly see that the elements 6X 6X and 5X 5X belong to the group of variables, and therefore, we can combine them.

Conversely, the elements (โˆ’1) (-1) and 5 5 belong to the group of numbers, and thus they can also be combined.

6Xโˆ’5X=5+1 6X-5X=5+1

X=6 X=6

The result of the equation is 6 6 .


Exercises on Equations by Simplifying Like Terms

Exercise 2

Assignment

7a+8b+4a+9b=? 7a+8b+4a+9b=\text{?}

Solution

We arrange the corresponding elements

7a+4a+8b+9b=? 7a+4a+8b+9b=\text{?}

We add accordingly

11a+8b+9b=? 11a+8b+9b=\text{?}

11a+17b 11a+17b

Answer

11a+17b 11a+17b


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Exercise 3

Assignment:

3x+4x+7+2=? 3x+4x+7+2=\text{?}

Solution

We add the corresponding elements

7x+7+2=? 7x+7+2=\text{?}

7x+9 \text{7x+9}

Answer

7x+9 \text{7x+9}


Exercise 4

Assignment

18xโˆ’7+4xโˆ’9โˆ’8x=? 18x-7+4x-9-8x=\text{?}

Solution

We input the corresponding elements

18x+4xโˆ’8xโˆ’7โˆ’9=? 18x+4x-8x-7-9=\text{?}

We solve accordingly

22xโˆ’8xโˆ’7โˆ’9=? 22x-8x-7-9=\text{?}

14xโˆ’7โˆ’9=? 14x-7-9=\text{?}

Answer

14xโˆ’16 14x-16


Do you know what the answer is?

Exercise 5

Assignment

7.3โ‹…4a+2.3+8a=? 7.3\cdot4a+2.3+8a=\text{?}

Solution

First, we solve the multiplication exercise

29.2a+2.3+8a= 29.2a+2.3+8a=

We arrange the terms accordingly

29.2a+8a+2.3= 29.2a+8a+2.3=

We add the terms accordingly

37.2a+2.3 37.2a+2.3

Answer

37.2a+2.3 37.2a+2.3


Exercise 6

Assignment

38a+149b+119b+68a=?\frac{3}{8}a+\frac{14}{9}b+1\frac{1}{9}b+\frac{6}{8}a=\text{?}

Solution

We input the corresponding elements

38a+68a+149b+119b=\frac{3}{8}a+\frac{6}{8}a+\frac{14}{9}b+1\frac{1}{9}b=

We add accordingly

3+68a+149b+119b= \frac{3+6}{8}a+\frac{14}{9}b+1\frac{1}{9}b=

We convert the mixed number into an improper fraction

3+68a+149b+109b= \frac{3+6}{8}a+\frac{14}{9}b+\frac{10}{9}b=

We add accordingly

98a+14+109b= \frac{9}{8}a+\frac{14+10}{9}b=

98a+249b= \frac{9}{8}a+\frac{24}{9}b=

We convert the improper fractions into mixed numbers

118a+249b= 1\frac{1}{8}a+\frac{24}{9}b=

118a+269b 1\frac{1}{8}a+2\frac{6}{9}b

Answer

118a+269b 1\frac{1}{8}a+2\frac{6}{9}b


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Examples with solutions for Simplifying and Combining Like Terms

Exercise #1

โˆ’16+a=โˆ’17 -16+a=-17

Video Solution

Step-by-Step Solution

Let's solve the equation โˆ’16+a=โˆ’17 -16 + a = -17 by isolating the variable a a .

To isolate a a , add 16 to both sides of the equation to cancel out the โˆ’16 -16 :

โˆ’16+a+16=โˆ’17+16 -16 + a + 16 = -17 + 16

This simplification results in:

a=โˆ’1 a = -1

Thus, the solution to the equation โˆ’16+a=โˆ’17 -16 + a = -17 is a=โˆ’1 a = -1 .

If we review the answer choices given, the correct answer is Choice 4, โˆ’1 -1 .

The solution to the problem is a=โˆ’1 a = -1 .

Answer

โˆ’1 -1

Exercise #2

x+x=8 x+x=8

Video Solution

Step-by-Step Solution

To solve the equation x+x=8 x + x = 8 , follow these steps:

  • Step 1: Combine like terms. Since the left side of the equation is x+x x + x , it can be simplified to 2x 2x . This gives us the equation 2x=8 2x = 8 .
  • Step 2: Solve for x x by isolating it. Divide both sides of the equation by 2 to get x x .
  • Performing the division gives x=82 x = \frac{8}{2} .
  • Step 3: Calculate the result of the division. 82=4 \frac{8}{2} = 4 .

Therefore, the solution to the equation is x=4 x = 4 .

Answer

4

Exercise #3

2a+3a+45a=0 2a+3a+45a=0

a=? a=\text{?}

Video Solution

Step-by-Step Solution

To solve the equation 2a+3a+45a=0 2a + 3a + 45a = 0 , follow these steps:

  • Step 1: Combine Like Terms.

Add the coefficients of a a :

2+3+45=50 2 + 3 + 45 = 50

  • Step 2: Substitute and Simplify.

This simplifies the equation to:

50a=0 50a = 0

  • Step 3: Solve for a a .

To find a a , divide both sides of the equation by 50:

a=050 a = \frac{0}{50}

a=0 a = 0

Therefore, the solution to the problem is a=0 a = 0 .

Answer

0 0

Exercise #4

7m+3mโˆ’40m=0 7m+3m-40m=0

m=? m=\text{?}

Video Solution

Step-by-Step Solution

To solve this problem, we'll proceed with the following steps:

  • Step 1: Combine like terms of the given equation.
  • Step 2: Solve for the variable m m .

Now, let's work through these steps:

Step 1: Combine like terms:
We start with the equation 7m+3mโˆ’40m=0 7m + 3m - 40m = 0 .
Combining these like terms entails adding or subtracting the coefficients of m m :

(7+3โˆ’40)m=0 (7 + 3 - 40)m = 0
Calculate the sum and difference of these coefficients:
(10โˆ’40)m=0 (10 - 40)m = 0

This simplifies to:
โˆ’30m=0 -30m = 0

Step 2: Solve for m m :
To isolate m m , divide both sides by โˆ’30-30:
m=0โˆ’30 m = \frac{0}{-30}

Calculate the right-hand side:

m=0 m = 0

Therefore, the solution to the problem is m=0 m = 0 . This corresponds to choice 3 from the provided answer options.

Answer

0

Exercise #5

Solve for b b :

8โˆ’b=6 8-b=6

Video Solution

Step-by-Step Solution

First we will move terms so that -b remains remains on the left side of the equation.

We'll move 8 to the right-hand side, making sure to retain the plus and minus signs accordingly:

โˆ’b=6โˆ’8 -b=6-8

Then we will subtract as follows:

โˆ’b=โˆ’2 -b=-2

Finally, we will divide both sides by -1 (be careful with the plus and minus signs when dividing by a negative):

โˆ’bโˆ’1=โˆ’2โˆ’1 \frac{-b}{-1}=\frac{-2}{-1}

b=2 b=2

Answer

2 2

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