Solve 2×(√36 + 9): Order of Operations with Square Root

2×(36+9)= 2\times(\sqrt{36}+9)=

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1

Understand the problem

2×(36+9)= 2\times(\sqrt{36}+9)=

2

Step-by-step solution

Let's solve this problem step by step using the order of operations (PEMDAS: Parentheses, Exponents, Multiplication/Division, Addition/Subtraction):

1. First, let's focus on what's inside the parentheses: 36+9 \sqrt{36}+9

2. We need to evaluate the square root first:

  • 36=6 \sqrt{36} = 6 (because 6×6=36 6 \times 6 = 36 )

3. Now our expression looks like this: 2×(6+9) 2\times(6+9)

4. Next, we perform the addition inside the parentheses:

  • 6+9=15 6 + 9 = 15

5. Our expression is now: 2×15 2\times15

6. Finally, we perform the multiplication:

  • 2×15=30 2 \times 15 = 30

Therefore, 2×(36+9)=30 2\times(\sqrt{36}+9) = 30

This matches the provided correct answer of 30.

3

Final Answer

30

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\( 20\div(4+1)-3= \)

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