Simplifying Expressions (Collecting Like Terms)

πŸ†Practice variables and algebraic expressions

The simplification of expressions consists of creating an equivalent expression written in a shorter and simpler way in which we combine all of the similar terms (collecting like terms).

For example, the expression:

3+3+3+3+3+5Xβˆ’3X 3+3+3+3+3+5X-3X

After having simplified it, it would be:

15+2X 15+2X

What we have done is created two groups of numbers and variables:
3+3+3+3+3 3+3+3+3+3 and 5Xβˆ’3X 5X-3X .

This can be simplified further, resulting in only two terms:15+2X 15+2X

Solving a basic algebraic equation: X + 3X = 8 + 4. Step-by-step breakdown of combining like terms on both sides to get 4X = 12. Fundamental algebra simplification process.

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Test yourself on variables and algebraic expressions!

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\( 3x+4x+7+2=\text{?} \)

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After having studied what algebraic expressions and equivalent algebraic expressions are, the next thing to do is to understand how to collect like terms.

Since the numbers and variables are not similar (or, 'like') terms, they cannot be simplified into a single group and, therefore, we have to write them separately (X,Y X,Y).

Example with Two Variables

The expression 4+2+2X+3X+Y+2Y= 4+2+2X+3X+Y+2Y= can be simplified as follows:

5X+3Y+6 5X+3Y+6

Practice Exercises: Collecting Like Terms

Combine like terms in order to obtain shorter expressions:

  • X+X=X+X=
  • 5+8βˆ’9+5Xβˆ’4X=5+8-9+5X-4X=
  • 5+0+8Xβˆ’5=5+0+8X-5=
  • 11+5Xβˆ’2X+8=11+5X-2X+8=
  • 13X+5βˆ’4.5X+7.5X=13X+5-4.5X+7.5X=

Collect like terms to obtain shorter expressions. Then, using what we have learned about the numerical value of algebraic expressions, apply X=5 X=5 and solve.

  • 2X+5Xβ‹…4=2X+5X\cdot4=
  • 2.3X+0.4Xβˆ’0.7X=2.3X+0.4X-0.7X=
  • X15+X15={X\over15}+{X\over15}=
  • 38Xβˆ’28X+5={3\over8}X-{2\over8}X+5=
  • (7+Y):3=(7+Y):3=

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Exercises: Collecting Like Terms

Exercise 1

Task:

3baβ‹…138a+58b+418m+910a+23m=?3\frac{b}{a}\cdot1\frac{3}{8}a+\frac{5}{8}b+\frac{4}{18}m+\frac{9}{10}a+\frac{2}{3}m=\text{?}

Solution:

Enter the corresponding elements.

3baΓ—138a+58b+910a+418m+23m=3\frac{b}{a}\times1\frac{3}{8}a+\frac{5}{8}b+\frac{9}{10}a+\frac{4}{18}m+\frac{2}{3}m=

Convert the mixed fractions into improper fractions.

3baΓ—(8+3)8a+58b+910a+418m+23m=3\frac{b}{a}\times\frac{(8+3)}{8}a+\frac{5}{8}b+\frac{9}{10}a+\frac{4}{18}m+\frac{2}{3}m=

Solve accordingly.

3Γ—11Γ—bΓ—a8Γ—a+58b+910a+4+2Γ—618m= \frac{3\times11\times b\times a}{8\times a}+\frac{5}{8}b+\frac{9}{10}a+\frac{4+2\times6}{18}m=

Simplify to a a in the equation.

338b+58b+910a+1618m=\frac{33}{8}b+\frac{5}{8}b+\frac{9}{10}a+\frac{16}{18}m=

33+58b+910a+89m= \frac{33+5}{8}b+\frac{9}{10}a+\frac{8}{9}m=

388b+910a+89m= \frac{38}{8}b+\frac{9}{10}a+\frac{8}{9}m=

434b+910a+89m= 4\frac{3}{4}b+\frac{9}{10}a+\frac{8}{9}m=

Answer:

434b+910a+89m= 4\frac{3}{4}b+\frac{9}{10}a+\frac{8}{9}m=


Exercise 2

Task:

38a+149b+119b+68a=?\frac{3}{8}a+\frac{14}{9}b+1\frac{1}{9}b+\frac{6}{8}a=\text{?}

Solution:

First, group the terms together:

38a+68a+149b+119b\frac{3}{8}a+\frac{6}{8}a+\frac{14}{9}b+1\frac{1}{9}b

Then reduce in correspondence and convert the mixed fractions into improper fractions.

3+68a+109b+149b= \frac{3+6}{8}a+\frac{10}{9}b+\frac{14}{9}b=

98a+10+149b= \frac{9}{8}a+\frac{10+14}{9}b=

118a+249b= 1\frac{1}{8}a+\frac{24}{9}b=

118a+269b= 1\frac{1}{8}a+2\frac{6}{9}b=

118a+223b 1\frac{1}{8}a+2\frac{2}{3}b

Answer:

118a+223b 1\frac{1}{8}a+2\frac{2}{3}b


Do you know what the answer is?

Exercise 3

7.3Γ—4a+2.3+8a=? 7.3\times4a+2.3+8a=?

Solution:

We start with the multiplication operation.

(7.3Γ—4a)+2.3+8a= (7.3\times4a)+2.3+8a=

(29.2a)+2.3+8a= (29.2a)+2.3+8a=

Then we add together as much as we can and rewrite the equation to make it clearer:

29.2a+8a+2.3= 29.2a+8a+2.3=

37.2a+2.3= 37.2a+2.3=

Answer:

37.2a+2.3 37.2a+2.3


Exercise 4

Task:

Solve the following equation:

a+b+bc+9a+10b+3c=? a+b+bc+9a+10b+3c=\text{?}

Solution:

The terms are substituted into the expression according to the order: a,b,ca, b, c.

a+9a+b+bc+10b+3c= a+9a+b+bc+10b+3c=

We continue with the addition operations.

10a+11b+bc+3c= 10a+11b+bc+3c=

The terms containing cc are converted for the equation since they cannot be simplified further.

10a+11b+(b+3)c 10a+11b+(b+3)c

Answer:

10a+11b+(b+3)c 10a+11b+(b+3)c


Check your understanding

Exercise 5

Task:

Solve the following equation:

3z+19zβˆ’4z=? 3z+19z-4z=\text{?}

Solution:

We start with the addition operation:

22zβˆ’4z= 22z-4z=

We continue solving accordingly.

18z 18z

Answer:

18z 18z


Review Questions

What are like terms?

Like terms in an algebraic expression are those that have the same variable with the same exponent, regardless of the sign and the coefficientβ€”that is, the sign and the coefficient can be different, but the variable and the exponent must be the same. For example:

3x2 3x^2 y βˆ’11x2 -11x^2

8a5 8a^5 y 8a5 8a^5

βˆ’7m -7m y 23m \frac{2}{3}m


How do you simplify expressions?

In order to simplify algebraic expressions, we need to work out if there are any like terms and then group them together before performing the operations (addition, subtraction, etc.).

Example 1

Task: Simplify the following expression:

3x2βˆ’7x+6βˆ’5x2βˆ’xβˆ’1 3x^2-7x+6-5x^2-x-1

Solution:

First we need to group the like terms and then perform the operations.

3x2βˆ’5x2βˆ’7xβˆ’x+6βˆ’1 3x^2-5x^2-7x-x+6-1

βˆ’2x2βˆ’8x+5 -2x^2-8x+5

Answer:

βˆ’2x2βˆ’8x+5 -2x^2-8x+5

Example 2

Task: Simplify the following expression:

8m2+2m+7=3m3+5m2+2mβˆ’5 8m^2+2m+7=3m^3+5m^2+2m-5

Solution:

In this case we need to put all the terms on one side and combine the like terms:

βˆ’3m3+8m2βˆ’5m2+2mβˆ’2m+7+5= -3m^3+8m^2-5m^2+2m-2m+7+5=

βˆ’3m3+3m2+12= -3m^3+3m^2+12=

Answer:

βˆ’3m3+3m2+12= -3m^3+3m^2+12=


How do you simplify a function?

In order to simplify a function, we must also work out if there are any like terms and group them together in order to simplify them.

Example

Question: Simplify the following function:

f(a)=βˆ’5a2+2aβˆ’4+2a2+5a f\left(a\right)=-5a^2+2a-4+2a^2+5a

Solution:

In this function we can see that there are like terms, so we can group them to simplify them.

f(a)=βˆ’5a2+2a2+2a+5aβˆ’4 f\left(a\right)=-5a^2+2a^2+2a+5a-4

f(a)=βˆ’3a2+7aβˆ’4 f\left(a\right)=-3a^2+7a-4

Answer:

f(a)=βˆ’3a2+7aβˆ’4 f\left(a\right)=-3a^2+7a-4


Do you think you will be able to solve it?

Examples with solutions for Simplifying Expressions (Collecting Like Terms)

Exercise #1

3x+4x+7+2=? 3x+4x+7+2=\text{?}

Video Solution

Step-by-Step Solution

Let's simplify the expression 3x+4x+7+2 3x + 4x + 7 + 2 step-by-step:

  • Step 1: Combine Like Terms Involving x x
    The terms 3x 3x and 4x 4x are like terms because both involve the variable x x . To combine them, add their coefficients:
    3x+4x=(3+4)x=7x 3x + 4x = (3 + 4)x = 7x

  • Step 2: Combine Constant Terms
    The expression includes constant terms 7 7 and 2 2 . These can be added together to simplify:
    7+2=9 7 + 2 = 9

  • Step 3: Write the Simplified Expression
    Now, combine the results from Step 1 and Step 2 to form the final simplified expression:
    7x+9 7x + 9

Therefore, the simplified expression is 7x+9 7x + 9 .

Reviewing the choices provided, the correct choice is:

  • Choice 2: 7x+9 7x + 9

This matches our simplified expression, confirming our solution is correct.

Answer

7x+9 7x+9

Exercise #2

3z+19zβˆ’4z=? 3z+19z-4z=\text{?}

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Combine like terms by identifying and adding their coefficients.
  • Step 2: Simplify the expression.
  • Step 3: Verify the resulting expression with the provided choices.

Let's work through each step:

Step 1: Identify the coefficients in the expression 3z+19zβˆ’4z 3z + 19z - 4z . The coefficients are 3 3 , 19 19 , and βˆ’4 -4 .

Step 2: Add and subtract these coefficients: 3+19βˆ’4 3 + 19 - 4 .

Step 3: Calculate: 3+19=22 3 + 19 = 22 and then 22βˆ’4=18 22 - 4 = 18 .

Therefore, the simplified expression is 18z 18z .

The solution to the problem is 18z 18z .

Answer

18z 18z

Exercise #3

Are the expressions the same or not?

20x 20x

2Γ—10x 2\times10x

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Simplify the expression 2Γ—10x 2 \times 10x .
  • Step 2: Compare the simplified expression with 20x 20x .

Now, let's work through each step:
Step 1: The expression 2Γ—10x 2 \times 10x can be rewritten using associativity as 2Γ—(10Γ—x) 2 \times (10 \times x) .
Step 2: Apply the associative property of multiplication: (2Γ—10)Γ—x=20Γ—x=20x (2 \times 10) \times x = 20 \times x = 20x .

Comparing this with the given expression, we see that both expressions are indeed the same, as they simplify to 20x 20x .

Therefore, the solution to the problem is Yes.

Answer

Yes

Exercise #4

Are the expressions the same or not?

3+3+3+3 3+3+3+3

3Γ—4 3\times4

Video Solution

Step-by-Step Solution

To solve this problem, we'll analyze the expressions 3+3+3+33+3+3+3 and 3Γ—43 \times 4 to determine if they are equivalent.

First, evaluate the expression 3+3+3+33+3+3+3:

  • Add the numbers: 3+3=63 + 3 = 6
  • Add again: 6+3=96 + 3 = 9
  • Add the last 33: 9+3=129 + 3 = 12

The result of 3+3+3+33+3+3+3 is 1212.

Next, evaluate the expression 3Γ—43 \times 4:

  • Perform the multiplication: 3Γ—4=123 \times 4 = 12

The result of 3Γ—43 \times 4 is also 1212.

Since both expressions result in the same number, we conclude that

The expressions are the same.

Therefore, the correct answer is Yes.

Answer

Yes

Exercise #5

Are the expressions the same or not?

18x 18x

2+9x 2+9x

Video Solution

Step-by-Step Solution

To determine if the expressions 18x 18x and 2+9x 2 + 9x are equivalent, we'll analyze their structures.

  • 18x 18x is a linear expression with a single term involving the variable x x , and its coefficient is 18.
  • 2+9x 2 + 9x consists of two terms: a constant term 2 2 and a linear term 9x 9x with coefficient 9.

For two expressions to be equivalent, each corresponding term must be equal. Here, the expression 18x 18x has no constant term, whereas 2+9x 2 + 9x has a constant term of 2. Furthermore, the linear term coefficients differ: 18β‰ 9 18 \neq 9 .

Therefore, the expressions 18x 18x and 2+9x 2 + 9x are not the same. They structurally differ and cannot be made equivalent just through similar values of x x .

Therefore, the solution to this problem is: No.

Answer

No

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