Linear Equations Practice Problems - One Variable Solutions

To solve the equation $5 - x = 4$, we aim to isolate $x$ on one side of the equation.

We start by considering the equation:
$5 - x = 4$

Step 1: Eliminate 5 from the left side to isolate terms involving $x$. To do this, subtract 5 from both sides of the equation:

$(5 - x) - 5 = 4 - 5$

Step 2: Simplify both sides:

$-x = -1$

Step 3: To solve for $x$, multiply or divide both sides by $-1$ to change the sign of $x$:

$-1 \cdot -x = -1 \cdot -1$

This simplifies to:

$x = 1$

Therefore, the solution to the equation $5 - x = 4$ is $x = 1$.

The correct answer is $x = 1$.

First, simplify both sides of the equation:

Left side: $x - 3 + 5 = x + 2$

Right side: $8 - 2 = 6$

Now the equation is: $x + 2 = 6$

Subtract 2 from both sides to isolate $x$:

$x + 2 - 2 = 6 - 2$

Simplifying gives:

$x = 4$

To solve the equation $6x \cdot 2 = 24$, follow these steps:

1. First, identify the operation involved. In this case, it is multiplication.

2. Divide both sides of the equation by 12 (since $6 \times 2 = 12$) to isolate $x$:

$x = \frac{24}{12}$

3. Calculate $x$:

$x = 2$

To solve this linear equation, we need to isolate the variable $x$. Here are the steps to follow:

• Step 1: Simplify the equation by dividing both sides by 10. This gives us:

$\frac{8x \cdot 10}{10} = \frac{80}{10}$

This simplifies to:

$8x = 8$

• Step 2: Now, isolate $x$ by dividing both sides by 8:

$\frac{8x}{8} = \frac{8}{8}$

This simplifies to:

$x = 1$

Therefore, the solution to the equation $8x \cdot 10 = 80$ is

$x = 1$.

First, simplify both sides of the equation:

Left side: $x + 4 - 2 = x + 2$

Right side: $6 + 1 = 7$

Now the equation is: $x + 2 = 7$

Subtract 2 from both sides to isolate$x$:

$x + 2 - 2 = 7 - 2$

Simplifying gives:

$x = 5$