Solving Equations Using All Methods: Opening parentheses

$(a+3a)\times(5+2)=112$

Calculate a a

We begin by solving the two exercises inside of the parentheses:

$4a\times7=112$

We then divide each of the sections by 4:

$\frac{4a\times7}{4}=\frac{112}{4}$

In the fraction on the left side we simplify by 4 and in the fraction on the right side we divide by 4:

$a\times7=28$

Remember that:

$a\times7=a7$

Lastly we divide both sections by 7:

$\frac{a7}{7}=\frac{28}{7}$

$a=4$

4

$(7x+3)\times(10+4)=238$

We begin by solving the addition exercise in the right parenthesis:

$(7x+3)+14=238$

We then multiply each of the terms inside of the parentheses by 14:

$(14\times7x)+(14\times3)=238$

Following this we solve each of the exercises inside of the parentheses:

$98x+42=238$

We move the sections whilst retaining the appropriate sign:

$98x=238-42$

$98x=196$

Finally we divide the two parts by 98:

$\frac{98}{98}x=\frac{196}{98}$

$x=2$

2

Solve for X:

$5(x-4)-6(7-x)=5x$

$10.33$

Solve for X:

$6+3(x+4)=7-3(x-2)$

$-\frac{5}{6}$

Solve for X:

$7(x-4)=(6-x)\times3$

$4.6$

Solve for X:

$7(x+5)-3(x-2)=5$

$-9$

Solve for X:

$7(x-4)+3=5-4(x+5)$

$\frac{10}{11}$

Solve for X:

$6(x+4)-4=8(x+5)$

$-10$

Solve for X:

$7-8(x+4)=-3x$

$-5$

Solve for X:

$3(x-2)=4$

$\frac{10}{3}$

Solve for X:

$3-4(x-2)=6x+4(3-x)$

$-\frac{1}{6}$

Solve for X:

$3(x+2)=5(2-x)$

$x=\frac{1}{2}$