Solving Equations Using All Methods: Using fractions

Find the value of the parameter X

$\frac{1}{3}x+\frac{5}{6}=-\frac{1}{6}$

First, we will arrange the equation so that we have variables on one side and numbers on the other side.

Therefore, we will move $\frac{5}{6}$ to the other side, and we will get

$\frac{1}{3}x=-\frac{1}{6}-\frac{5}{6}$

Note that the two fractions on the right side share the same denominator, so you can subtract them:

 $\frac{1}{3}x=-\frac{6}{6}$

Observe the minus sign on the right side!

$\frac{1}{3}x=-1$

Now, we will try to get rid of the denominator, we will do this by multiplying the entire exercise by the denominator (that is, all terms on both sides of the equation):

$1x=-3$

 $x=-3$

-3

Find the value of the parameter X

$3x-\frac{1}{9}=\frac{8}{9}$

$\frac{1}{3}$

Solve for X:

$\frac{1}{6}x-\frac{1}{3}=\frac{1}{3}$

$4$

Find the value of the parameter X

$\frac{1}{3}x=\frac{1}{9}$

$\frac{1}{3}$

Solve for X:
$\frac{2}{3}x-\frac{4}{6}=\frac{1}{3}$

$\frac{3}{2}$

Find the value of the parameter X

$\frac{2}{3}x+\frac{1}{4}=\frac{3}{4}$

$\frac{3}{4}$

Solve for X:

$\frac{9}{11}-\frac{8}{15}x=\frac{8}{22}$

$\frac{75}{88}$

Solve for X:
$\frac{4}{5}x+\frac{3}{7}=\frac{2}{14}$

$-\frac{5}{14}$

Find the value of the parameter X

$\frac{8}{3}-\frac{4}{5}x=-\frac{2}{10}x$

$\frac{40}{9}$

Solve for X:
$\frac{4}{9}+\frac{3}{5}x=\frac{4}{3}$

$\frac{40}{27}$