Quadratic Equations Factoring Practice Problems

Let's first expand the parentheses using the formula:

$a(x+b)=ax+ab$

$(2\times x)+(2\times4)+8=0$

$2x+8+8=0$

Next, we will substitute in our terms accordingly:

$2x+16=0$

Then, we will move the 16 to the left-hand side, keeping the appropriate sign:

$2x=-16$

Finally, we divide both sides by 2:

$\frac{2x}{2}=-\frac{16}{2}$

$x=-8$

Let's proceed to solve the linear equation $3(a+1) - 3 = 0$:

Step 1: Distribute the 3 in the expression $3(a+1)$.

We get:
$3 \cdot a + 3 \cdot 1 - 3 = 0$

This simplifies to:
$3a + 3 - 3 = 0$

Step 2: Simplify the expression by combining like terms.

We simplify this to:
$3a + 0 = 0$ or simply $3a = 0$

Step 3: Isolate $a$ by dividing both sides by 3.

$\frac{3a}{3} = \frac{0}{3}$

Thus,
$a = 0$

Therefore, the solution to the problem is $a = 0$.

The correct choice is the option corresponding to $a = 0$.

To open parentheses we will use the formula:

$a(x+b)=ax+ab$

$(7\times-2x)+(7\times5)=77$

We multiply accordingly

$-14x+35=77$

We will move the 35 to the right section and change the sign accordingly:

$-14x=77-35$

We solve the subtraction exercise on the right side and we will obtain:

$-14x=42$

We divide both sections by -14

$\frac{-14x}{-14}=\frac{42}{-14}$

$x=-3$

To solve the equation $-2(-4 + y) - y = 0$, we will follow these steps:

• Step 1: Distribute $-2$ inside the parenthesis.
• Step 2: Simplify and combine like terms.
• Step 3: Solve the equation for $y$.

Let's proceed with the solution:

Step 1: Distribute $-2$ in the expression $-2(-4 + y)$. This will transform the expression as follows:

$-2(-4 + y) = -2 \times -4 + (-2) \times y = 8 - 2y$.

After distributing, the equation becomes:

$8 - 2y - y = 0$.

Step 2: Combine like terms. Notice that $-2y - y$ is equivalent to $-3y$:

$8 - 3y = 0$.

Step 3: Solve for $y$. First, isolate the term with $y$ by subtracting 8 from both sides:

$-3y = -8$.

Next, divide both sides by $-3$ to find $y$:

$y = \frac{-8}{-3} = \frac{8}{3}$.

Thus, the solution for $y$ is $\frac{8}{3}$, which can be written as a mixed number:

$y = 2\frac{2}{3}$.

Therefore, the solution to the problem is $y = 2\frac{2}{3}$.

To solve the given linear equation $5 - (3b - 1) = 0$, follow these steps:

• Step 1: Simplify the equation.
  Start by distributing the negative sign through the parentheses:
  $5 - 3b + 1 = 0$
• Step 2: Combine like terms.
  Combine the constant terms on the left side:
  $6 - 3b = 0$
• Step 3: Isolate the variable $b$.
  Subtract 6 from both sides of the equation to isolate the term with $b$:
  $-3b = -6$
• Step 4: Solve for $b$.
  Divide both sides by -3 to solve for $b$:
  $b = \frac{-6}{-3} = 2$

Therefore, the solution to the equation is $b = 2$.