Solve and Apply: Finding the Field of Application for (x+y:3)/(2x+6)=4

Question

x+y:32x+6=4 \frac{x+y:3}{2x+6}=4

What is the field of application of the equation?

Video Solution

Solution Steps

00:00 Find the domain of the function
00:03 According to mathematical laws, division by 0 is not allowed
00:07 Since there is a variable in the denominator, we must ensure it is not equal to 0
00:11 There is a variable in the function's main denominator
00:14 Therefore in this case we must ensure the denominator is not equal to 0
00:20 Let's isolate the variable X
00:47 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll follow these steps to find the domain:

  • Step 1: Recognize that the expression x+y:32x+6=4\frac{x+y:3}{2x+6}=4 involves a fraction. The denominator 2x+62x + 6 must not be zero, as division by zero is undefined.
  • Step 2: Set the denominator equal to zero and solve for xx to find the values that must be excluded: 2x+6=02x + 6 = 0.
  • Step 3: Solve 2x+6=02x + 6 = 0:
    • 2x+6=02x + 6 = 0
    • 2x=62x = -6
    • x=3x = -3
  • Step 4: Conclude that the domain of the function excludes x=3x = -3, meaning x3x \neq -3.

Thus, the domain of the given expression is all real numbers except x=3x = -3. This translates to:

x3 x\operatorname{\ne}-3

Answer

x3 x\operatorname{\ne}-3