Solving Equations Using All Methods - Examples, Exercises and Solutions

Question Types:
Simplifying and Combining Like Terms: Combining like termsSimplifying and Combining Like Terms: Equations with variables on both sidesSimplifying and Combining Like Terms: Exercises with fractionsSimplifying and Combining Like Terms: One sided equationsSimplifying and Combining Like Terms: Opening parenthesesSimplifying and Combining Like Terms: Solving an equation using all techniquesSimplifying and Combining Like Terms: Solving an equation with fractionsSimplifying and Combining Like Terms: Using additional geometric shapesSimplifying and Combining Like Terms: Worded problemsSolving an Equation by Multiplication/ Division: Addition, subtraction, multiplication and divisionSolving an Equation by Multiplication/ Division: Combining like termsSolving an Equation by Multiplication/ Division: Decimal numbersSolving an Equation by Multiplication/ Division: Equations with variables on both sidesSolving an Equation by Multiplication/ Division: Exercises on Both Sides (of the Equation)Solving an Equation by Multiplication/ Division: Number of termsSolving an Equation by Multiplication/ Division: One sided equationsSolving an Equation by Multiplication/ Division: Rearranging EquationsSolving an Equation by Multiplication/ Division: Solving an equation using all techniquesSolving an Equation by Multiplication/ Division: Solving an equation with fractionsSolving an Equation by Multiplication/ Division: BinomialSolving an Equation by Multiplication/ Division: Using additional geometric shapesSolving an Equation by Multiplication/ Division: Using fractionsSolving an Equation by Multiplication/ Division: Worded problemsSolving Equations by using Addition/ Subtraction: Complete the missing numberSolving Equations by using Addition/ Subtraction: Equations with variables on both sidesSolving Equations by using Addition/ Subtraction: Exercises on Both Sides (of the Equation)Solving Equations by using Addition/ Subtraction: More than Two TermsSolving Equations by using Addition/ Subtraction: One sided equationsSolving Equations by using Addition/ Subtraction: MonomialSolving Equations by using Addition/ Subtraction: Solving an equation by multiplying/dividing both sidesSolving Equations by using Addition/ Subtraction: Solving an equation using all techniquesSolving Equations by using Addition/ Subtraction: Solving an equation with fractionsSolving Equations by using Addition/ Subtraction: Simplifying expressionsSolving Equations by using Addition/ Subtraction: Test if the coefficient is different from 1Solving Equations by using Addition/ Subtraction: BinomialSolving Equations by using Addition/ Subtraction: Using variablesSolving Equations by using Addition/ Subtraction: Worded problemsSolving Equations Using All Methods: Addition, subtraction, multiplication and divisionSolving Equations Using All Methods: Combining like termsSolving Equations Using All Methods: Decimal numbersSolving Equations Using All Methods: Domain of definitionSolving Equations Using All Methods: Equations with variables on both sidesSolving Equations Using All Methods: Exercises with fractionsSolving Equations Using All Methods: Number of termsSolving Equations Using All Methods: One sided equationsSolving Equations Using All Methods: Opening parenthesesSolving Equations Using All Methods: Rearranging EquationsSolving Equations Using All Methods: MonomialSolving Equations Using All Methods: BinomialSolving Equations Using All Methods: Using additional geometric shapesSolving Equations Using All Methods: Using fractionsSolving Equations Using All Methods: Worded problemsSolving Quadratic Equations using Factoring: Equations with variables on both sidesSolving Quadratic Equations using Factoring: One sided equationsSolving Quadratic Equations using Factoring: Solving an equation using all techniquesSolving Quadratic Equations using Factoring: Solving an equation with fractionsSolving Quadratic Equations using Factoring: Solving the problemSolving Quadratic Equations using Factoring: Worded problems

First-degree equation in one variable – solving by all methods

2x6=342x-6=34Variable

A first-degree equation is an equation where the highest power is 11 and there is only one variable 11.

Solving an Equation by Adding/Subtracting from Both Sides If the number is next to XX with a plus, we need to subtract it from both sides.
If the number is next to XX with a minus, we need to add it to both sides.

Solving an Equation by Multiplying/Dividing Both Sides We will need to multiply or divide both sides of the equations where there is a coefficient for XX.

Solving an Equation by Combining Like Terms Move all the XXs to the right side and all the numbers to the left side.

Solving an equation using the distributive property We will solve according to the distributive property
a(b+c)=ab+bca(b+c)=ab+bc

Suggested Topics to Practice in Advance

  1. Solving Equations by Adding or Subtracting the Same Number from Both Sides
  2. Solving Equations by Multiplying or Dividing Both Sides by the Same Number
  3. Solving Equations by Simplifying Like Terms
  4. Solving Equations Using the Distributive Property

Practice Solving Equations Using All Methods

Examples with solutions for Solving Equations Using All Methods

Exercise #1

Solve for x:

2(4x)=8 2(4-x)=8

Video Solution

Step-by-Step Solution

To solve this equation, follow these steps:

  • Step 1: Apply the distributive property to the equation:

    2(4x)=2×42×x=82x 2(4-x) = 2 \times 4 - 2 \times x = 8 - 2x

  • Step 2: Simplify the equation:

    The equation now becomes: 82x=88 - 2x = 8

  • Step 3: Isolate the variable xx by simplifying the equation:

    First, subtract 8 from both sides:
    82x8=88 8 - 2x - 8 = 8 - 8
    This simplifies to:
    2x=0-2x = 0

  • Step 4: Solve for xx by dividing both sides by -2:

    x=02=0 x = \frac{0}{-2} = 0

Therefore, the solution to the equation is x=0x = 0.

Answer

0

Exercise #2

x+7=14 x+7=14

x=? x=\text{?}

Video Solution

Step-by-Step Solution

To solve the equation x+7=14 x + 7 = 14 , we aim to find the value of x x by isolating it on one side.

  • Step 1: Identify the current equation: x+7=14 x + 7 = 14 .
  • Step 2: To isolate x x , perform the inverse operation. Subtract 7 from both sides to maintain equality.
  • Step 3: Simplify both sides: x+77=147 x + 7 - 7 = 14 - 7 .
  • Step 4: This simplifies to x=7 x = 7 .

Therefore, we have found that the solution to the equation x+7=14 x + 7 = 14 is x=7 x = 7 , which matches the given answer choice 2.

Answer

7

Exercise #3

Solve for X:

5x=25 5x=25

Video Solution

Step-by-Step Solution

To solve the equation 5x=255x = 25, we will isolate xx using division:

  • Divide both sides of the equation by 5:
5x5=255 \frac{5x}{5} = \frac{25}{5}

After performing the division, we get:

x=5 x = 5

Thus, the solution to the equation is x=5 x = 5 .

Answer

5

Exercise #4

Solve for X:

x+8=10 x + 8 = 10

Video Solution

Step-by-Step Solution

To solve for x x , start by isolating x x on one side of the equation:
Subtract 8 from both sides:
x+88=108 x + 8 - 8 = 10 - 8 simplifies to
x=2 x = 2 .

Answer

2

Exercise #5

Solve for X:

13x=9 \frac{1}{3}x=9

Video Solution

Step-by-Step Solution

To solve the equation 13x=9\frac{1}{3}x = 9, we need to isolate the variable xx. To accomplish this, we can multiply both sides of the equation by 3, the reciprocal of 13\frac{1}{3}.

Step-by-step solution:

  • Step 1: Multiply both sides by 3.
    (3×13)x=3×9\left(3 \times \frac{1}{3}\right)x = 3 \times 9
  • Step 2: Simplify the left side.
    This gives us 1x=271x = 27, since (3×13)=1\left(3 \times \frac{1}{3}\right) = 1.
  • Step 3: Conclude that x=27x = 27.

Therefore, the solution to the equation is x=27 x = 27 . This matches choice number 1 from the provided options.

Answer

27

Exercise #6

Find the value of the parameter X:

x+5=8 x+5=8

Video Solution

Step-by-Step Solution

To solve the equation x+5=8x + 5 = 8, follow these steps:

  • Step 1: Start with the original equation:
    x+5=8x + 5 = 8.
  • Step 2: Subtract 5 from both sides of the equation to isolate xx:
    x+55=85x + 5 - 5 = 8 - 5.
  • Step 3: Simplify both sides:
    x=3x = 3.

Therefore, the solution to the equation is x=3x = 3.

The correct answer choice is: :

3

Answer

3

Exercise #7

x+x=8 x+x=8

Video Solution

Step-by-Step Solution

To solve the equation x+x=8 x + x = 8 , follow these steps:

  • Step 1: Combine like terms. Since the left side of the equation is x+x x + x , it can be simplified to 2x 2x . This gives us the equation 2x=8 2x = 8 .
  • Step 2: Solve for x x by isolating it. Divide both sides of the equation by 2 to get x x .
  • Performing the division gives x=82 x = \frac{8}{2} .
  • Step 3: Calculate the result of the division. 82=4 \frac{8}{2} = 4 .

Therefore, the solution to the equation is x=4 x = 4 .

Answer

4

Exercise #8

Solve for X:

x+7=12 x + 7 = 12

Video Solution

Step-by-Step Solution

To solve for x x , start by isolating x x on one side of the equation:
Subtract 7 from both sides:
x+77=127 x + 7 - 7 = 12 - 7 simplifies to
x=5 x = 5 .

Answer

5

Exercise #9

Solve for X:

5x=4 5-x=4

Video Solution

Step-by-Step Solution

To solve the equation 5x=45 - x = 4, we aim to isolate xx on one side of the equation.

We start by considering the equation:
5x=45 - x = 4

Step 1: Eliminate 5 from the left side to isolate terms involving xx. To do this, subtract 5 from both sides of the equation:

(5x)5=45(5 - x) - 5 = 4 - 5

Step 2: Simplify both sides:

x=1-x = -1

Step 3: To solve for xx, multiply or divide both sides by 1-1 to change the sign of xx:

1x=11-1 \cdot -x = -1 \cdot -1

This simplifies to:

x=1x = 1

Therefore, the solution to the equation 5x=45 - x = 4 is x=1x = 1.

The correct answer is x=1x = 1.

Answer

1

Exercise #10

Solve for x:

7(2x+5)=77 7(-2x+5)=77

Video Solution

Step-by-Step Solution

To open parentheses we will use the formula:

a(x+b)=ax+ab a(x+b)=ax+ab

(7×2x)+(7×5)=77 (7\times-2x)+(7\times5)=77

We multiply accordingly

14x+35=77 -14x+35=77

We will move the 35 to the right section and change the sign accordingly:

14x=7735 -14x=77-35

We solve the subtraction exercise on the right side and we will obtain:

14x=42 -14x=42

We divide both sections by -14

14x14=4214 \frac{-14x}{-14}=\frac{42}{-14}

x=3 x=-3

Answer

-3

Exercise #11

7m+3m40m=0 7m+3m-40m=0

m=? m=\text{?}

Video Solution

Step-by-Step Solution

To solve this problem, we'll proceed with the following steps:

  • Step 1: Combine like terms of the given equation.
  • Step 2: Solve for the variable m m .

Now, let's work through these steps:

Step 1: Combine like terms:
We start with the equation 7m+3m40m=0 7m + 3m - 40m = 0 .
Combining these like terms entails adding or subtracting the coefficients of m m :

(7+340)m=0 (7 + 3 - 40)m = 0
Calculate the sum and difference of these coefficients:
(1040)m=0 (10 - 40)m = 0

This simplifies to:
30m=0 -30m = 0

Step 2: Solve for m m :
To isolate m m , divide both sides by 30-30:
m=030 m = \frac{0}{-30}

Calculate the right-hand side:

m=0 m = 0

Therefore, the solution to the problem is m=0 m = 0 . This corresponds to choice 3 from the provided answer options.

Answer

0

Exercise #12

Solve for X:

x+3=7 x + 3 = 7

Video Solution

Step-by-Step Solution

To solve for x x , start by isolating x x on one side of the equation:
Subtract 3 from both sides:
x+33=73 x + 3 - 3 = 7 - 3 simplifies to
x=4 x = 4 .

Answer

4

Exercise #13

Solve for X:

3+x=4 3+x=4

Video Solution

Step-by-Step Solution

To solve this problem, we will follow these steps:

  • Step 1: Identify the given equation 3+x=4 3 + x = 4 .
  • Step 2: Use subtraction to isolate the variable x x .

Now, let's work through these steps:
Step 1: We have the equation: 3+x=4 3 + x = 4 .
Step 2: Subtract 3 from both sides of the equation to isolate x x :

3+x3=43 3 + x - 3 = 4 - 3

This simplifies to:

x=1 x = 1

Therefore, the solution to the equation is x=1 x = 1 .

Answer

1

Exercise #14

Solve for X:

x+9=15 x + 9 = 15

Video Solution

Step-by-Step Solution

Step-by-step solution:

1. Begin with the equation: x+9=15 x + 9 = 15

2. Subtract 9 from both sides: x+99=159 x + 9 - 9 = 15 - 9 , which simplifies to x=6 x = 6

Answer

6

Exercise #15

Solve for X:

6x=72 6x=72

Video Solution

Step-by-Step Solution

To solve for xx in the equation 6x=726x = 72, follow these steps:

Step 1: Identify the equation and the coefficient of xx.
The given equation is 6x=726x = 72, where the coefficient of xx is 6.

Step 2: Isolate xx by dividing both sides of the equation by the coefficient (6).
Perform the division: x=726x = \frac{72}{6}.

Step 3: Simplify the result.
Calculating 726\frac{72}{6}, we get x=12x = 12.

Therefore, the solution to the equation is x=12x = 12.

Answer

12

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