What is the field of application of the equation?
\( \frac{25a+4b}{7y+4\cdot3+2}=9b \)
What is the field of application of the equation?
\( \frac{6}{x+5}=1 \)
What is the field of application of the equation?
\( \frac{x+y:3}{2x+6}=4 \)
What is the field of application of the equation?
\( \frac{3x:4}{y+6}=6 \)
What is the field of application of the equation?
\( \frac{xyz}{2(3+y)+4}=8 \)
What is the field of application of the equation?
What is the field of application of the equation?
To solve the problem, follow these steps:
Therefore, the equation is undefined when . The field of application excludes .
The choice that reflects this is .
What is the field of application of the equation?
To solve this problem, we will determine the domain, or field of application, of the equation .
Step-by-step solution:
Therefore, the field of application of the equation is all real numbers except where .
Thus, the domain is .
What is the field of application of the equation?
To solve this problem, we'll follow these steps to find the domain:
Thus, the domain of the given expression is all real numbers except . This translates to:
What is the field of application of the equation?
To determine the field of application of the equation , we must identify values of for which the equation is defined.
Therefore, the field of application, or the domain of the equation, is all real numbers except .
We must conclude that .
Comparing with the provided choices, the correct answer is choice 3: .
What is the field of application of the equation?
To find the domain of the given equation , we need to ensure the denominator is not zero. This means solving .
Let's solve this step-by-step:
If , the denominator becomes zero, which makes the original expression undefined.
Therefore, the value of must not be for the expression to be valid. In conclusion, the restriction on is that .
The correct answer choice is: .
\( \frac{\sqrt{15}+34:z}{4y-12+8:2}=5 \)
What is the field of application of the equation?
What is the field of application of the equation?
To solve this problem, we need to identify the values of for which the denominator of the expression becomes zero, as these values are not part of the domain.
First, let's simplify the denominator of the given equation:
Original equation:
Simplifying the terms:
Thus, the denominator becomes:
We need to ensure the denominator is not zero to avoid undefined expressions:
Simplify and solve for :
Therefore, the equation is undefined for , and the answer is that the field of application excludes .
Given the possible choices for the problem, the correct choice is:
The solution to this problem is .