7y+4⋅3+225a+4b=9b
What is the field of application of the equation?
To solve the problem, follow these steps:
- Step 1: Understand that the equation 7y+4⋅3+225a+4b=9b is undefined when the denominator equals zero.
- Step 2: Simplify the denominator: 7y+4⋅3+2.
- Step 3: Calculate the constant part: 4⋅3=12, so the expression becomes 7y+12+2.
- Step 4: Combine constants: 12+2=14. The denominator is 7y+14.
- Step 5: Set the denominator equal to zero to find values of y that make the equation undefined: 7y+14=0.
- Step 6: Solve for y:
- Subtract 14 from both sides: 7y=−14.
- Divide by 7: y=−2.
Therefore, the equation is undefined when y=−2. The field of application excludes y=−2.
The choice that reflects this is y=−2.
y=−2