Vertical Addition: Simple addition of 3-digit and 1-digit numbers

To solve this problem, we will use vertical addition.

Let's perform the steps:

• Step 1: Write the numbers 100 and 5 vertically, aligning them by place value. Since 5 is a single-digit number, it will align under the ones place of 100. This gives us:

  $\begin{aligned} &100 \\ +& \\ &~~5 \\ \end{aligned}$

• Step 2: Add the numbers column by column, starting from the right.

  • Add the ones place: $0 + 5 = 5$
  • Add the tens place: $0 + 0 = 0$
  • Add the hundreds place: $1 + 0 = 1$

  This results in a sum of $105$.

Therefore, the solution to the problem is $105$.

To solve this problem, we'll perform vertical addition by following these steps:

• Step 1: Align the numbers 215 and 3 vertically, ensuring the rightmost digits (the ones place) line up:

$\begin{array}{r} 215 \\ + \phantom{1}3 \\ \underline{\phantom{776}} \\ \end{array}$

• Step 2: Add the digits in the ones place: $5 + 3 = 8$. Write 8 in the ones place of the sum.
• Step 3: Move to the tens place. Since there is no digit in the tens place for 3, we add $1 + 0 = 1$. Write 1 in the tens place of the sum.
• Step 4: For the hundreds place, there is only the digit 2 from 215, so write 2 in the hundreds place of the sum.

The resulting sum is:

$\begin{array}{r} \phantom{1}218 \\ \end{array}$

Therefore, the solution to the problem is $218$.

We will solve the problem using vertical addition as follows:

• Step 1: Align the numbers by their place values.
  $\begin{aligned} &957 \\ + &~~~~3 \\ \end{aligned}$
• Step 2: Add the digits starting from the rightmost side, which is the units column.

First, add the digits in the units place:
$7 + 3 = 10$.

Since 10 is composed of 0 in the units place and carry over 1 to the tens place, write 0 in the units place and remember to carry over the 1.

Next, move to the tens place and add up the digits, considering the carryover:
$5 + 0 + 1 = 6$.

Finally, add the hundreds place, which has no other digits to add:
$\begin{aligned} & 9 \\ &\underline{ }\ \\ & 9 \quad\ (hundreds)\\ \end{aligned}$

Summarizing, the addition yields the following:

$\begin{aligned} \qquad\qquad &957 \\ + &~~~~3 \\ &\underline{\phantom{776}} \\ \quad\ &960 \\ \end{aligned}$

Therefore, the result of adding 957 and 3 is $\mathbf{960}$.

The correct answer from the choices given is Choice 4: 960.

Thus, the correct solution to the problem is $960$.

To solve the problem of adding $862$ and $4$ vertically, follow these steps:

• Step 1: Align the numbers as follows:
  $\begin{array}{c} 862 \\ + 4 \\ \underline{\phantom{776}} \\ \end{array}$
• Step 2: Add the digit in the units’ place:
  $2 + 4 = 6$
• Step 3: Since $6$ is less than $10$, place the $6$ directly in the units’ place of the result:
• Step 4: Move to the tens and hundreds places. Since there is no carry, just bring down the $6$ from the tens place and the $8$ from the hundreds place directly.

Therefore, the sum of $862$ and $4$ is $866$.

The correct answer choice is: :

866

To solve this problem, we will add the numbers 521 and 8 using vertical addition:

• Step 1: Write the numbers in vertical form, aligning by the units place:

$\begin{array}{c} 521 \\ +~~8 \\ \hline \underline{\phantom{529}} \end{array}$

• Step 2: Add the digits in the units place: $1 + 8 = 9$. Write the result below the line in the units place.
• Step 3: Add the digits in the tens place: $2 + 0 = 2$. Write the result in the tens place.
• Step 4: Add the digits in the hundreds place: $5 + 0 = 5$. Write the result in the hundreds place.

Thus, the sum of 521 and 8 is $529$.

Therefore, the solution to the problem is $\boxed{529}$.