Vertical Addition: Simple addition of 2-digit and 2-digit numbers

To solve this problem, we'll follow these steps:

• Step 1: Align the numbers vertically so that each digit lines up according to its place value. Arrange 10 and 32 as follows:

$\begin{aligned} &10 \\ +& \\ &32 \\ &\underline{\phantom{776}} \end{aligned}$

• Step 2: Add the digits in the rightmost column (units place). Add $0$ (from 10) and $2$ (from 32) to obtain $2$.

Write the result $2$ beneath the line in the units column:

$\begin{aligned} &10 \\ +& \\ &32 \\ &\underline{\phantom{776}} \\ &\phantom{7}2 \\ \end{aligned}$

• Step 3: Move to the next column to the left (tens place) and add $1$ (from 10) and $3$ (from 32) to obtain $4$.

Write the result $4$ to the left of the $2$ in the tens column:

$\begin{aligned} &10 \\ +& \\ &32 \\ &\underline{\phantom{776}} \\ &42 \\ \end{aligned}$

Therefore, the solution to the problem is $42$.

To solve this problem, we'll use vertical addition, adding two two-digit numbers, 23 and 51. Here’s how to proceed:

• Step 1: Align the numbers vertically by their place values.

Arrange the numbers:

$\begin{aligned} &23 \\ + &51 \\ \end{aligned}$

• Step 2: Add the units digits, which are 3 and 1.

$3 + 1 = 4$

• Step 3: Add the tens digits, which are 2 and 5.

$2 + 5 = 7$

• Step 4: Combine both results.

The sum of the units digits is 4, and the sum of the tens digits is 7, giving the final total of:

$\begin{aligned} &23 \\ + &51 \\ \underline{\phantom{76}} & \\ &74 \\ \end{aligned}$

Therefore, the final result of adding 23 and 51 is $74$.

To solve this problem, we'll follow these steps:

• Step 1: Add the units place digits (rightmost column) of both numbers: 6 (from 36) and 3 (from 43).
• Step 2: Calculate $6 + 3 = 9$. Place 9 under the units column.
• Step 3: Add the tens place digits (left side) of both numbers: 3 (from 36) and 4 (from 43).
• Step 4: Calculate $3 + 4 = 7$. Place 7 under the tens column.

Now, let's work through each step:
Step 1: Add the rightmost digits, 6 and 3, to get 9.
Step 2: Since the sum is less than 10, we write 9 immediately below the line.
Step 3: Proceed with the tens digits. Add 3 and 4 to get 7.
Step 4: Since there's no carrying involved, write 7 in the result's tens column.

Thus, the solution to the addition problem is $79$, corresponding to choice 4.

To solve this problem, we'll follow these steps:

• Step 1: Add the units digits.
• Step 2: Add the tens digits, including any carry-over from the units column.

Let's work through these steps:

Step 1: Add the units digits, which are 7 and 2.

$7 + 2 = 9$.

Since 9 is less than 10, we don't need to carry over to the tens column.

Step 2: Add the tens digits, which are 4 and 2.

$4 + 2 = 6$.

Combine these results: The sum of 47 and 22 is 69.

Therefore, the solution to the problem is $69$.

To solve this problem, we'll use vertical addition. Let's follow these steps to ensure accuracy:

• Step 1: Align the two numbers vertically by their place values. The given numbers are 75 and 10. Write 75 on top and 10 below it, making sure that the digits are aligned in the correct columns:

$\begin{array}{c} 75 \\ +10 \\ \underline{\phantom{776}} \end{array}$

• Step 2: Add the digits in the units column (the rightmost column). This means adding 5 (from 75) and 0 (from 10):
  $5 + 0 = 5$
• Step 3: Move to the tens column (the next column on the left). Add 7 (from 75) and 1 (from 10):
  $7 + 1 = 8$
• Step 4: Combine the results from each column to form the sum. Since there are no carries, the direct sum of the columns is:
  $\begin{array}{c} 75 \\ +10 \\ \underline{85} \end{array}$ The resulting sum is 85.

Therefore, the solution to the problem is $85$.

To solve the given problem, we will perform vertical addition:

• Step 1: Align the numbers by their rightmost digits:
  $\begin{aligned} &86 \\ +& \\ &11 \\ &\underline{\phantom{776}} \\ \end{aligned}$
• Step 2: Add the digits in the units column:
  - The units digits are 6 and 1. Adding them gives us $6 + 1 = 7$.
• Step 3: Add the digits in the tens column:
  - The tens digits are 8 and 1. Adding them gives us $8 + 1 = 9$.
• Step 4: Combine the results:
  - Write down the addition result starting with the tens followed by the units to get the final sum of 97.

Thus, the result of the addition is $97$.

Since this problem requires a choice, the correct choice from the given options is: : $97$