Vertical Addition: 5-digits

To solve this problem, we'll follow these steps:

• Step 1: Start by adding the numbers column by column from right to left.
• Step 2: Handle any carries appropriately as you move from one column to the next.
• Step 3: Verify the result by comparing it to the provided answer choices.

Now, let's perform the addition step by step:

Step 1: Add the units column:
6 (from 10,256) + 5 (from 17,435) = 11
Write down 1 and carry over 1 to the tens column.

Step 2: Add the tens column:
5 + 3 = 8, plus the carry over 1, totals 9.
Write down 9.

Step 3: Add the hundreds column:
2 + 4 = 6.
Write down 6.

Step 4: Add the thousands column:
0 + 7 = 7.
Write down 7.

Step 5: Add the ten-thousands column:
1 + 1 = 2.
Write down 2.

Therefore, the sum of 10,256 and 17,435 is $27,691$.

To solve this problem, we will perform vertical addition of the given numbers:

$\begin{aligned} &24789\\ +& \\ &35140 \\ &\underline{\phantom{776}}\\ \end{aligned}$

We add column by column starting from the rightmost digit (units):

• Units: $9 + 0 = 9$. Write 9 below the line.
• Tens: $8 + 4 = 12$. Write 2 below the line and carry over 1 to the next column.
• Hundreds: $7 + 1 + 1 (\text{carry}) = 9$. Write 9 below the line.
• Thousands: $4 + 5 = 9$. Write 9 below the line.
• Ten-thousands: $2 + 3 = 5$. Write 5 below the line.

Putting it all together, the sum is $59929$.

Therefore, the solution to the problem is $59929$.

To solve this problem, we'll use vertical addition, carefully ensuring each digit is correctly placed and carried over if necessary:

• Write the numbers on top of each other as such:
       35612
  +
       44675

Begin with the rightmost column (ones place):

• Column 1 (Units): $2 + 5 = 7$. Place 7 below the line.
• Column 2 (Tens): $1 + 7 = 8$. Place 8 below the line.
• Column 3 (Hundreds): $6 + 6 = 12$. The sum is greater than 9, so place 2 below the line and carry over 1 to the next column.
• Column 4 (Thousands): $5 + 4 = 9$, then add the carryover 1 to get 10. Place 0 below the line and carry over 1.
• Column 5 (Ten-Thousands): $3 + 4 = 7$, then add the carryover 1 to get 8. Place 8 below the line.

The complete addition step-by-step is as follows:

     35612
+
     44675
    _____
     80287

Therefore, the sum of $35612$ and $44675$ is $80287$.

Comparing with the choices given, our result matches choice 2.

Thus, the solution to the problem is $80287$.

To solve this addition problem, follow these steps:

We'll first perform vertical addition with the given numbers:

• 46891
• +27108

Align the numbers vertically, ensuring each digit lines up with the same place value:

$\begin{array}{c}
    & 4 & 6 & 8 & 9 & 1 \\
  + & 2 & 7 & 1 & 0 & 8 \\
  \hline
\end{array}$

Now, we add each column from right to left:
1. Units place: $1 + 8 = 9$. Write 9.
2. Tens place: $9 + 0 = 9$. Write 9.
3. Hundreds place: $8 + 1 = 9$. Write 9.
4. Thousands place: $6 + 7 = 13$. Write 3 and carry over 1 to the ten-thousands place.
5. Ten-thousands place: $4 + 2 + 1 \text{ (carry over)} = 7$. Write 7.

The result is formed as:

$\begin{array}{c}
    & 7 & 3 & 9 & 9 & 9 \\
\end{array}$
\)

Thus, the solution to the problem is $73999$.

Let's solve the problem step-by-step:

Step 1: Align the numbers for vertical addition as follows:

\begin{array}{c@{}c@{}c@{}c@{}c@{}c} & 6 & 6 & 5 & 4 & 3 \\ + & 5 & 2 & 4 & 5 & 6 \\ \hline \end{array}

Step 2: Perform the addition from the rightmost digit (units place):

• Units place: $3 + 6 = 9$
• Tens place: $4 + 5 = 9$
• Hundreds place: $5 + 4 = 9$
• Thousands place: $6 + 2 = 8$
• Ten-thousands place: $6 + 5 = 11$
• Write 1 in the ten-thousands place and carry over 1 to the next column.
• Since there are no more columns left to add the carry over, the final digit in the ten-thousands place is 11.

The final result is:

\begin{array}{c@{}c@{}c@{}c@{}c@{}c} & 1 & 1 & 8 & 9 & 9 & 9 \\ \end{array}

Therefore, the sum of 66543 and 52456 is $118999$.

To solve this problem, we will add the two numbers using vertical addition:

• Step 1: Write the numbers vertically, aligning them by their place values:
  \begin{array}{c@{}c@{}c@{}c@{}c@{}c} & 7 & 2 & 3 & 5 & 4 \\ + & & 2 & 9 & 5 & 6 & 3 \\ \hline \end{array}
• Step 2: Add the digits in each column starting from the rightmost (units) column:
• Units place: $4 + 3 = 7$
• Tens place: $5 + 6 = 11$. Write 1 and carry over 1 to the hundreds place.
• Hundreds place: $3 + 5 + 1 = 9$ (including the carry-over).
• Thousands place: $2 + 9 = 11$. Write 1 and carry over 1 to the ten-thousands place.
• Ten-thousands place: $7 + 2 + 1 = 10$ (including the carry-over). Write 0 and carry over 1.
• Step 3: Write down the complete sum:

\begin{array}{c@{}c@{}c@{}c@{}c@{}c} & & 1 & 0 & 1 & 9 & 1 & 7 \\ \hline \end{array}

• Adding all values gives us the final sum.

Therefore, the sum of 72354 and 29563 is $101917$.

To solve this problem, we'll follow these steps:

• Step 1: Arrange the numbers vertically and align by the rightmost digit.
• Step 2: Add digits starting from the right (units place) and move left.
• Step 3: Carry over any value over 9 to the next set of digits.

Now, let's work through each step:

Step 1: Arrange the numbers:

$\begin{aligned} &\phantom{+}81541 \\ + &\phantom{+}17759 \\ \end{aligned}$

Step 2: Add digits starting from the rightmost digit:

1. Units place: $1 + 9 = 10$. Write down 0 and carry over 1.
2. Tens place: $4 + 5 = 9$. Add the carried 1: $9 + 1 = 10$. Write down 0 and carry over 1.
3. Hundreds place: $5 + 7 = 12$. Add the carried 1: $12 + 1 = 13$. Write down 3 and carry over 1.
4. Thousands place: $1 + 7 = 8$. Add the carried 1: $8 + 1 = 9$. Write down 9.
5. Ten-thousands place: $8 + 1 = 9$. Write down 9.

The addition will look like this:

$\begin{aligned} &\phantom{8}81541 \\ + &\phantom{8}17759 \\ \hline &\phantom{8}99300 \\ \end{aligned}$

Therefore, the addition of these two numbers results in $99300$.

To solve this problem, we'll follow these steps:

• Step 1: Align the numbers vertically for addition.
• Step 2: Add each column starting from the rightmost digit (units) and moving to the left.
• Step 3: Record any carry needed for sums exceeding 9.

Let's execute the vertical addition:
Write the numbers aligning each digit according to its place value:

$\begin{array}{c} 95781 \\ +22245 \\ \end{array}$

Step-by-step vertical addition:

• Starting with the units place: $1 + 5 = 6$. Record 6.
• Tens place: $8 + 4 = 12$. Record 2, carry over 1 to the hundreds place.
• Hundreds place: $7 + 2 = 9$, add the carry 1 to get $10$. Record 0, carry over 1 to the thousands place.
• Thousands place: $5 + 2 = 7$, add the carry 1 to get $8$. Record 8.
• Ten-thousands place: $9 + 2 = 11$. Record 1 and carry over 1 to the next place.
• Since there's no next place, record this final carry in the ten-thousands place: 1.

Therefore, the sum of 95781 and 22245 is:

$\boxed{118026}$

The correct choice in the multiple-choice options is option 2, which matches our calculated sum.

Therefore, the solution to the problem is 118026.

To solve this problem, we'll follow these steps:

• Step 1: Align the two numbers, 19785 and 30406, for vertical addition.
• Step 2: Add the numbers column by column, starting from the rightmost digit.
• Step 3: Carry over any value greater than 9 to the next column on the left.

Now, let's work through each step:

Step 1: Align the numbers:
$\begin{array}{c} 19785 \\ +30406 \\ \hline \end{array}$

Step 2: Add the columns starting from the right:

• Rightmost column (ones): $5 + 6 = 11$. Write down $1$, carry over $1$.
• Tens column: $8 + 0 = 8$, plus the carry over $1$ gives $9$.
• Hundreds column: $7 + 4 = 11$. Write down $1$, carry over $1$.
• Thousands column: $9 + 0 = 9$, plus the carry over $1$ gives $10$. Write down $0$, carry over $1$.
• Ten-thousands column: $1 + 3 = 4$, plus the carry over $1$ gives $5$.
• Assembling these results, we have the sum of $50191$.

Therefore, the solution to the problem is $\boxed{50191}$.

To solve this problem, we will perform vertical addition of the two numbers:

We have: \begin{array}{c@{}c@{}c@{}c@{}c@{}c} & & & & & \\ & 7 & 8 & 1 & 5 & 6 \\ + & 1 & 9 & 7 & 6 & 3 \\ \hline \end{array}

Let's add the numbers column by column from right to left:

• Units place: $6 + 3 = 9$. Write 9.
• Tens place: $5 + 6 = 11$. Write 1 and carry over 1 to the hundreds place.
• Hundreds place: $1 + 7 + 1 \, (\text{carried}) = 9$. Write 9.
• Thousands place: $8 + 9 = 17$. Write 7 and carry over 1 to the ten-thousands place.
• Ten-thousands place: $7 + 1 + 1 \, (\text{carried}) = 9$. Write 9.

Thus, the sum is $\boxed{97919}$.

The solution to the problem is $97919$, which matches choice :

97919

.

To solve this problem, we'll follow these steps for vertical addition:

• Add the digits in the units place: $6 + 7 = 13$. Write down $3$ and carry over $1$.
• Add the digits in the tens place with the carry-over: $3 + 9 + 1 = 13$. Write down $3$ and carry over $1$.
• Add the digits in the hundreds place with the carry-over: $6 + 1 + 1 = 8$. Write down $8$.
• Add the digits in the thousands place: $3 + 2 = 5$. Write down $5$.
• Add the digits in the ten-thousands place: $6 + 1 = 7$. Write down $7$.

Carrying out these calculations step-by-step gives us the final sum as:

$75833$

This corresponds to choice 4. Therefore, the solution to the problem is $75833$.

To solve this problem, we'll follow a systematic vertical addition process:

• Step 1: Align the numbers vertically by their place values:

$\begin{array}{c} 83716 \\ +19194 \end{array}$

• Step 2: Start adding from the rightmost column (units place).
      - Units: $6 + 4 = 10$ — write down $0$ and carry $1$.
• Step 3: Move to the tens column.
      - Tens: $1 + 9 = 10$, plus the carry of $1$, gives $11$ — write down $1$ and carry $1$.
• Step 4: Move to the hundreds column.
      - Hundreds: $7 + 1 = 8$, plus the carry of $1$, gives $9$ — write down $9$.
• Step 5: Move to the thousands column.
      - Thousands: $3 + 9 = 12$ — write down $2$ and carry $1$.
• Step 6: Move to the ten-thousands column.
      - Ten-thousands: $8 + 1 = 9$, plus the carry of $1$, gives $10$ — write down $0$ and carry $1$, adding it as a new leading digit.

Thus, the resulting sum of $83716 + 19194$ is $102910$.

To solve this problem, we need to perform vertical addition on the two numbers $15637$ and $29181$. Follow these steps:

• Step 1: Align the numbers vertically, ensuring the rightmost digits (units place) align.
• Step 2: Start adding from the rightmost digits (units place):
  • Add 7 (from 15637) + 1 (from 29181) = 8. Write 8 in the units place.
  • Move to the next column: add 3 + 8 = 11. Write 1 in the tens place and carry over 1 to the hundreds place.
  • Now add the hundreds place: 6 + 1 (carry-over) + 1 = 8. Write 8 in the hundreds place.
  • Next, add the thousands place: 5 + 9 = 14. Write 4 in the thousands place and carry over 1 to the ten-thousands place.
  • Finally, add the ten-thousands place: 1 + 1 (carry-over) + 2 = 4. Write 4 in the ten-thousands place.
• After carrying over appropriately and adding each digit, the result is 44818.

Therefore, the sum of $15637$ and $29181$ is $44818$.

To solve this problem using vertical addition, we'll follow these steps:

• Step 1: Align the numbers 24679 and 35813 by their place values. Write the numbers one above the other, ensuring digits align from right (units) to left (ten-thousands).
• Step 2: Add each column starting from the rightmost side:
• Add the units: $9 + 3 = 12$. Write 2 in the units place and carry over 1 to the tens.
• Add the tens: $7 + 1 = 8$ plus carry 1 gives 9. Write 9 in the tens place.
• Add the hundreds: $6 + 8 = 14$. Write 4 in the hundreds place and carry over 1 to the thousands.
• Add the thousands: $4 + 5 = 9$ plus carry 1 gives 10. Write 0 in the thousands place and carry over 1 to the ten-thousands.
• Add the ten-thousands: $2 + 3 = 5$ plus carry 1 gives 6. Write 6 in the ten-thousands place.

Therefore, the sum of 24679 and 35813 is $60492$.

To solve the problem effectively, we will follow a systematic approach:

• Step 1: Write the two numbers one above the other, aligning by columns according to their place value.
• Step 2: Begin adding from the rightmost column (the units place), moving leftward. Remember to carry over any tens to the next place value.
• Step 3: Continue to add column by column, including any carries from the previous column.

Let's work through these steps with the given numbers:

$\begin{aligned} &\phantom{+}36715 \\ + &45192 \\ \hline \end{aligned}$

Units Column (far right):
5 (from 36715) + 2 (from 45192) = 7

Tens Column:
1 (from 36715) + 9 (from 45192) = 10
Write down 0, and carry over 1.

Hundreds Column:
7 (from 36715) + 1 (carry) + 1 (from 45192) = 9

Thousands Column:
6 (from 36715) + 5 (from 45192) = 11
Write down 1, and carry over 1.

Tens of Thousands Column:
3 (from 36715) + 4 (from 45192) + 1 (carry) = 8

Thus, the sum is:

$\begin{aligned} &\phantom{+}36715 \\ + &45192 \\ \hline &81907 \\ \end{aligned}$

Therefore, the solution to the problem is $81907$.