Vertical Addition: Addition of 2-digit and 2-digit numbers with the regrouping of tens and ones

To solve this problem, we will perform vertical addition on the numbers 15 and 56.

Let's break down the steps:

• Step 1: Write the numbers vertically aligning the digits.
  $\begin{array}{c} \phantom{0}15 \\ +56 \\ \underline{\phantom{776}} \end{array}$
• Step 2: Add the digits in the ones place. The ones digits are 5 and 6.
  $5 + 6 = 11$.
  Write down 1 in the ones place and carry over 1 to the tens place.
• Step 3: Add the digits in the tens place, including the carried over 1. The tens digits are 1 and 5.
  $1 + 5 + 1 = 7$.
  Write down 7 in the tens place.

The complete addition is:

Thus, the solution to the problem is $\boxed{71}$.

To solve this problem, we'll use vertical addition and work through each step:

Consider the numbers:

Step 1: Align the numbers by their place values.
Step 2: Add the units place: $3 + 9 = 12$. Here, $12$ has two digits. We place $2$ in the units column and carry over $1$ to the tens column.
Step 3: Add the tens place along with the carry: $2 + 5 + 1 = 8$. Place $8$ in the tens column.

The final sum will be as follows:

Through these steps, we find that the sum of the numbers $23$ and $59$ is $82$.

Therefore, the solution to the problem is $82$.

To accurately sum the numbers 37 and 46 using vertical addition, follow these steps:

Step 1: Add the Units Column
Start by adding the digits in the units place: $7 + 6 = 13$. Since 13 is greater than 9, we write down the 3 in the units place of the result and carry over 1 to the tens column.

Step 2: Add the Tens Column
Next, add the digits in the tens column, along with any carried over value. Here we have $3 + 4 = 7$, plus the carry over of 1, giving $7 + 1 = 8$.

Final Result:
Combine the tens and units results. The sum is $83$.

Therefore, the solution to the problem is $\boxed{83}$.

To solve this vertical addition problem, we follow these steps:

• Step 1: Write the numbers one below the other, aligning columns by place value.
• Step 2: Begin with the ones column. Add $7$ (from $47$) to $5$ (from $25$).
• Step 3: Calculate the sum in the ones column: $7 + 5 = 12$.
• Step 4: Since $12$ is greater than $9$, we write $2$ in the ones place and carry over $1$ to the tens column.
• Step 5: Add the tens column: $4$ from $47$, $2$ from $25$, and the carried over $1$.
• Step 6: Calculate the tens sum: $4 + 2 + 1 = 7$.

Therefore, the final sum is $72$.

By checking the provided choices, the correct choice is: $72$.

To solve this problem, we'll follow these steps:

• Step 1: Align the numbers 52 and 39 for vertical addition.
• Step 2: Add the ones place digits: 2 + 9.
• Step 3: Handle any carry if needed and proceed to the tens place: 5 + 3.

Let's work through each step:

Step 1: Write the numbers in vertical alignment:

$\begin{array}{c} 52 \\ +39 \\\hline \end{array}$

Step 2: Add the digits in the ones column (rightmost):

$2 + 9 = 11$. Since this is more than 9, write 1 in the ones place and carry over 1 to the tens place.

Step 3: Add the digits in the tens place:

Including the carried over 1 from the ones addition, add $5 + 3 + 1 = 9$.

Write 9 in the tens place.

Therefore, the sum of $52 + 39$ is $91$.

Thus, the correct solution to the problem is 91.

Let's solve the problem of adding two numbers, 65 and 18, step-by-step using vertical addition:

• Step 1: Write the numbers vertically, aligning the tens and ones digits as follows:

$\begin{array}{c} \phantom{+}65 \\ +18 \\ \underline{\phantom{76}} \\ \end{array}$

• Step 2: Add the digits in the ones column. These digits are 5 and 8.

$5 + 8 = 13$

• Since the sum is 13, we place the 3 in the ones column and carry over the 1 to the tens column.

• Step 3: Move to the tens column. Add the digits in this column: 6 (from 65) and 1 (from 18), plus the 1 we carried over from the ones column.

$6 + 1 + 1 = 8$

• Step 4: Write 8 in the tens place.

$\begin{array}{c} \phantom{+}65 \\ +18 \\ \underline{\phantom{76}} \\ 83 \\ \end{array}$

Therefore, the sum of 65 and 18 is $\mathbf{83}$.

To solve this problem, we'll follow these steps:

• Step 1: Align the numbers by place value, ensuring the units and tens are in the correct columns.
• Step 2: Add the digits in the units column (3 and 8).
• Step 3: Address any carryover from the units addition, which affects the tens column calculation.
• Step 4: Add the digits in the tens column (7 and 1), including any carry.

Now, let's work through each step:

Step 1: The problem provides the vertical alignment:
$\begin{array}{c} 73 \\ +18 \\ \end{array}$
We confirm that the units and tens digits are properly aligned.

Step 2: Add the units digits (3 and 8):
$3 + 8 = 11$
Place the 1 in the units position and carry over 1 to the tens position.

Step 3: Add the tens digits along with the carryover:
$7 + 1 + 1 = 9$
Write the 9 in the tens position for the sum.

The resulting sum of the numbers vertically added is:
$\begin{array}{cc} & 91 \\ \end{array}$
Therefore, the solution to the problem is $91$.