Vertical Addition: Addition of 3-digit and 2-digit numbers with some regrouping

To solve this problem, we'll follow these steps:

• Step 1: Add the digits in the units column.
• Step 2: Add the digits in the tens column, including any carry from the units column.
• Step 3: Add the digits in the hundreds column, including any carry from the tens column.

Now, let's work through each step:

Step 1: Adding Units
- Consider the rightmost column (units place). We add the digits: $6$ (from 156) and $4$ (from 254).
- $6 + 4 = 10$.
- We write down $0$ in the units place and carry over $1$ to the tens place.

Step 2: Adding Tens
- Move to the next column on the left (tens place). We add the digits: $5$ (from 156), $5$ (from 254), plus the carry-over $1$ from the previous step.
- $5 + 5 + 1 = 11$.
- We write down $1$ in the tens place and carry over $1$ to the hundreds place.

Step 3: Adding Hundreds
- Move to the hundreds column. We add the digits: $1$ (from 156), $2$ (from 254), plus the carry-over $1$.
- $1 + 2 + 1 = 4$.
- We write down $4$ in the hundreds place.

Putting it all together, the sum of $156 + 254 = 410$.

Therefore, the solution to the problem is $410$.

To solve this problem, we'll perform vertical addition:

• Step 1: Add the digits in the units place:
  $7 + 3 = 10$. Write down 0 and carry over 1 to the tens place.
• Step 2: Add the digits in the tens place including the carried over 1:
  $4 + 6 + 1 = 11$. Write down 1 and carry over 1 to the hundreds place.
• Step 3: Add the digits in the hundreds place including the carried over 1:
  $2 + 3 + 1 = 6$.

Therefore, the solution to the problem is $610$.

To solve this problem, we'll follow these steps:

• Step 1: Align the numbers vertically by their place values.
• Step 2: Add each column starting from the right (ones place), carrying over if necessary.
• Step 3: Compile the results to get the final sum.

Now, let's work through each step:

Step 1: Align the numbers: $\begin{array}{c} 376 \\ + 234 \\ \end{array}$

Step 2: Add starting from the ones place:

• Ones place: $6 + 4 = 10$. Write down $0$ and carry over $1$.
• Tens place: $7 + 3 = 10$, plus the carry over $1$ equals $11$. Write down $1$ and carry over $1$.
• Hundreds place: $3 + 2 = 5$, plus the carry over $1$ equals $6$. Write down $6$.

Step 3: Compile the results: The sum is $610$.

Therefore, the solution to the problem is $610$.

To solve this addition problem, we will use vertical addition, adding each place value step-by-step:

• Step 1: Add the units place
  Add the digits in the units place: $4 + 6 = 10$.
  Write down 0 and carry over 1 to the tens column.
• Step 2: Add the tens place
  Add the digits in the tens place along with the carry: $3 + 7 + 1 = 11$.
  Write down 1 and carry over 1 to the hundreds column.
• Step 3: Add the hundreds place
  Add the digits in the hundreds place along with the carry: $4 + 3 + 1 = 8$.
  Write down 8.

After performing these steps, the final result of the addition is $810$.

810

To solve this problem, we'll follow these steps:

• Step 1: Add the units digits: 2 (from 712) + 8 (from 198) = 10. Write down 0 and carry over 1 to the tens place.
• Step 2: Add the tens digits and the carry: 1 (carry) + 1 (from 712) + 9 (from 198) = 11. Write down 1 and carry over 1 to the hundreds place.
• Step 3: Add the hundreds digits and the carry: 1 (carry) + 7 (from 712) = 8 and 2 from 198 is not used here, we have already accounted it. Write down 9 as the total.

Thus, the final result of adding 712 and 198 is $910$.

To solve this problem, we'll follow these steps:

• Step 1: Align the numbers $728$ and $182$ vertically by their respective place values (ones, tens, hundreds).

• Step 2: Add the digits in each column starting from the ones place and moving to the left (tens, then hundreds), carrying as necessary.

Now, let's work through each step:
Step 1: The numbers are aligned as follows:

$\begin{array}{c} & 7 & 2 & 8 \\ + & 1 & 8 & 2 \\ \hline \end{array}$

Step 2: Start adding from the rightmost column (ones):

$8 + 2 = 10$. We write down the $0$ and carry over the $1$ to the tens column.

Next, add the tens column including the carried $1$:

$2 + 8 + 1 = 11$. We write down the $1$ and carry over the $1$ to the hundreds column.

Finally, add the hundreds column including the carried $1$:

$7 + 1 + 1 = 9$. Write the $9$.

Therefore, the sum is $910$.

The solution to the problem is $\boxed{910}$.