Vertical Addition: Addition of 2-digit and 2-digit numbers with the regrouping of tens

To solve this problem, we'll perform vertical addition of two numbers, 14 and 56:

• Step 1: Align the numbers vertically by place value.
  The units digit of each number are aligned in one column, and the tens digit in another.
• Step 2: Add the units column:
  $4 + 6 = 10$. Since this result is a two-digit number, write down the 0 and carry over the 1 to the tens column.
• Step 3: Add the tens column, including the carry from the previous step:
  $1 + 1 + 5 = 7$

Therefore, the sum of 14 and 56 is $70$.

To solve this problem, we will perform the following steps:

• Step 1: Align the given numbers vertically according to their place values.
• Step 2: Add the digits in the ones and tens places, carrying over if necessary.

Let's break down the calculation process:

Step 1: Write the numbers in a vertical format.
$\begin{aligned} &\phantom{0}21 \\ +&\phantom{0}59 \\ &\underline{\phantom{776}} \end{aligned}$

Step 2: Start by adding the ones digits: $1 + 9 = 10$. Since 10 is a two-digit number, we write 0 in the ones place and carry 1 over to the tens place.

Step 3: Now, add the tens digits, including the carried 1: $2 + 5 + 1 = 8$.

Since there is no further place value beyond tens in this problem, the result of the addition is:

$\begin{aligned} &\phantom{0}21 \\ +&\phantom{0}59 \\ &\underline{\phantom{8}80} \end{aligned}$

Therefore, the solution to the problem is 80.

Let's solve the problem of adding 37 and 43 using vertical addition:

• Step 1: Align the Numbers Vertically
  Write the numbers such that their digits align according to place value: $\begin{array}{c} & 37 \\ + & 43 \\ \hline \end{array}$
• Step 2: Add the Units Place
  Start with the units place (rightmost digits). Add 7 (from 37) to 3 (from 43): $7 + 3 = 10$
  Since 10 is greater than 9, we write 0 in the units place and carry over 1 to the tens place.
• Step 3: Add the Tens Place
  Now, add the tens digits: 3 (from 37) and 4 (from 43), plus the 1 we carried over: $3 + 4 + 1 = 8$
• Step 4: Write the Final Sum
  Combining these results, we place 0 in the units position and 8 in the tens position, resulting in: $\begin{array}{c} & 37 \\ + & 43 \\ \hline & 80 \\ \end{array}$

Therefore, the sum of 37 and 43 is $80$.

The given problem involves adding the numbers 48 and 22 using vertical addition. Let's solve it step-by-step:

• Step 1: Align the numbers vertically, with each digit placed under the correct column (units or tens).
• Step 2: Add the digits in the units column:
  8 (from 48) + 2 (from 22) = 10. Write down 0 (in the units column) and carry over 1 to the tens column.
• Step 3: Add the digits in the tens column:
  4 (from 48) + 2 (from 22) + 1 (carry from units column) = 7. Write 7 in the tens column.

The result of the addition is 70.

Therefore, the solution to the problem is $70$.

To solve this problem, we'll follow these steps:

• Step 1: Align the numbers
• Step 2: Add the digits in the ones columm and handle carrying if necessary
• Step 3: Add the digits in the tens column, including any carry value

Now, let's work through each step:

Step 1: Align the numbers vertically by place value:

$\begin{aligned} &53 \\ + &37 \\ \hline \end{aligned}$

Step 2: Add the digits in the ones column (3 + 7 = 10):

Write 0 below the line in the ones column and carry over 1 to the tens column.

$\begin{aligned} &1 & \\ &53 \\ + &37 \\ \hline &0 \\ \end{aligned}$

Step 3: Add the digits in the tens column, considering the carried over 1 (5 + 3 + 1 = 9):

Write 9 below the line in the tens column:

$\begin{aligned} &1 & \\ &53 \\ + &37 \\ \hline 9 &0 \\ \end{aligned}$

Therefore, the sum of 53 and 37 is $90$.

This matches the correct answer: 90.

To solve this problem, we'll follow these steps:

• Step 1: Align the numbers by place value:
  $\begin{aligned} &75 \\ + &15 \\ \end{aligned}$

• Step 2: Add the units digits: $5 + 5 = 10$. Write down $0$ in the units place and regroup by carrying over $1$ to the tens place.

• Step 3: Add the tens digits, including the carry: $7 + 1 + 1 = 9$.

By following these steps, the sum of $75$ and $15$ is $90$.

Therefore, the solution to the problem is $90$.