Examples with solutions for Vertical Addition: Addition of 3-digit and 2-digit numbers with the regrouping of thousands

Exercise #1

amp;957+amp;amp;  43amp;776amp; \begin{aligned} &957 \\ +& \\ &~~43 \\ &\underline{\phantom{776}} & \\ \end{aligned}

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Align the Numbers
  • We will align the numbers by their place values:

    957+  43\begin{aligned} &957 \\ +& \\ &~~43 \\ \end{aligned}

  • Step 2: Perform Addition from Right to Left
    • Units Place (rightmost column):
    • Add the digits in the ones place: 7+3=107 + 3 = 10.
      Since 10 is greater than 9, write down 0 in the ones place and carry over 1 to the tens place.

    • Tens Place (middle column):
    • Add the digits in the tens place, including the carry-over: 5+4+1=105 + 4 + 1 = 10.
      Again, write down 0 in the tens place and carry over 1 to the hundreds place.

    • Hundreds Place (leftmost column):
    • Add the digits in the hundreds place, including the carry-over: 9+1=109 + 1 = 10.
      Write down the entire 10 since there is no further place to carry over.

  • Step 3: Write Down the Final Answer
  • The result of the addition is 1000.

Therefore, the solution to the problem is 1000 1000 .

Answer

1000

Exercise #2

amp;987+amp;amp;  13amp;776amp; \begin{aligned} &987 \\ +& \\ &~~13 \\ &\underline{\phantom{776}} & \\ \end{aligned}

Video Solution

Step-by-Step Solution

To solve this problem, we'll perform a vertical addition of two numbers:

  • Step 1: Arrange the numbers vertically by their place value:

987+13\begin{aligned} & 987 \\ + & 13 \\ \hline \end{aligned}

  • Step 2: Add the digits in the ones place.

Add 7 (ones place of 987) to 3 (ones place of 13) to get 10. Since this sum is 10, we write down 0 in the ones place and carry over 1 to the tens place.

  • Step 3: Add the digits in the tens place.

Add 8 (tens place of 987) to 1 (tens place of carry-over) + 1 (tens place of 13). This is 8 + 1 + 1 = 10. We write 0 in the tens place and carry over 1 to the hundreds place.

  • Step 4: Add the digits in the hundreds place.

Add 9 (hundreds place of 987) to 1 (carry-over). This sum is 9 + 1 = 10. We write 0 in the hundreds place and carry over 1 to the next higher place, the thousands place.

  • Step 5: Combine the result.

Since the only carried-over is 1 to the thousands place, we write it as is. So the result of the addition is 1000.

Therefore, the solution to this problem is 1000 1000 .

Answer

1000

Exercise #3

amp;921+amp;amp;  79amp;776amp; \begin{aligned} &921 \\ +& \\ &~~79 \\ &\underline{\phantom{776}} & \\ \end{aligned}

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Align the numbers vertically by place value.
  • Step 2: Add digits in each column starting from the right (units) to the left (hundreds), carrying over if necessary.
  • Step 3: Write the final sum at the bottom.

Let's work through the solution:

Step 1: We have the numbers aligned as:

921+  79 \begin{aligned} &921 \\ +& \\ &~~79 \\ \end{aligned}

Step 2: Start adding from the units column:

  • Units: 1+9=101 + 9 = 10. Write 0 and carry over 1 to the tens column.
  • Tens: 2+7+1 (carry over)=102 + 7 + 1 \text{ (carry over)} = 10. Write 0 and carry over 1 to the hundreds column.
  • Hundreds: 9+1 (carry over)=109 + 1 \text{ (carry over)} = 10. Write 0 and carry over 1 to a new thousands column.
  • Thousands: No additional digits to add, so just write 1.

Step 3: Combine the results to obtain the final sum:

The sum is 10001000.

Therefore, the solution to the problem is 1000 1000 .

Answer

1000

Exercise #4

amp;945+amp;amp;  45amp;776amp; \begin{aligned} &945 \\ +& \\ &~~45 \\ &\underline{\phantom{776}} & \\ \end{aligned}

Video Solution

Step-by-Step Solution

To solve this problem, we need to add 945 and 45 using vertical addition. We'll do this step by step:

Step 1: Write both numbers vertically, aligning them by place value:

945+45000 \begin{array}{c} 945 \\ +45 \\ \underline{\phantom{000}} \end{array}

Step 2: Start adding from the rightmost column (the units):

  • Add the units place: 5+5=105 + 5 = 10. Write 0 in the units place and carry over 1 to the next tens place.

1945+45000 \begin{array}{c} &1 \\ 945 \\ +45 \\ \underline{\phantom{00}0} \end{array}

Step 3: Move to the tens place and add, including the carryover:

  • Add tens place: 4+4+1=94 + 4 + 1 = 9. Write 9 in the tens place.

945+45090 \begin{array}{c} 945 \\ +45 \\ \underline{\phantom{0}90} \end{array}

Step 4: Finally, add the hundreds place:

  • Add hundreds place: Since there is no carryover, 9+0=99 + 0 = 9.

945+45990 \begin{array}{c} 945 \\ +45 \\ \underline{990} \end{array}

Therefore, the sum of 945 and 45 is 990 990 .

Answer

990

Exercise #5

amp;977+amp;amp;  23amp;776amp; \begin{aligned} &977\\ +& \\ &~~23 \\ &\underline{\phantom{776}} & \\ \end{aligned}

Video Solution

Step-by-Step Solution

To solve this vertical addition problem, we follow these steps:

  • Step 1: Align the numbers for vertical addition:
       977\ \ \ 977
    +23+ 23
  • Step 2: Start by adding the units digits.
    The units digit of 977977 is 77 and the units digit of 2323 is 33.
    7+3=107 + 3 = 10. Write 00 in the units place and carry over 11 to the tens place.
  • Step 3: Add the tens digits including the carryover.
    The tens digit of 977977 is 77 and the tens digit of 2323 is 22.
    Including the carryover 11:
    7+2+1=107 + 2 + 1 = 10. Write 00 in the tens place and carry over 11 to the hundreds place.
  • Step 4: Add the hundreds digits including the carryover.
    The hundreds digit of 977977 is 99. There are no hundreds in 2323, so only the carryover 11 is added:
    9+1=109 + 1 = 10. Write 00 in the hundreds place and carry over 11 to the thousands place.
  • Step 5: Since 2323 does not have a thousands place digit, just write the 11 from the previous carryover in the thousands place.

After completing all these steps, the final sum is 10001000.

Answer

1000