Vertical Addition: Addition of 3-digit numbers with the regrouping of tens and hundreds

To solve this problem, we'll use the following steps:

• Step 1: Align the numbers 115 and 236 vertically by their place values:

$\begin{aligned} &115 \\ +&236 \\ &\underline{\phantom{776}} \\ \end{aligned}$

Step 2: Start by adding the digits in the units (right-most) column:
$5 + 6 = 11$
Write 1 in the units place and carry over 1 to the tens column.

Step 3: Add the digits in the tens column with the carry:
$1 + 3 + 1 = 5$
Write 5 in the tens place.

Step 4: Add the digits in the hundreds column:
$1 + 2 = 3$
Write 3 in the hundreds place.

Putting it all together, we have:
$\begin{aligned} &115 \\ +&236 \\ &\underline{351} \\ \end{aligned}$

Therefore, the sum of 115 and 236 is $\textbf{351}$. The correct choice is option 3.

To solve this problem, we will perform vertical addition of the numbers 137 and 523:

• Step 1: Add the ones place: $7 + 3 = 10$. We write down 0 and carry over the 1 to the tens place.
• Step 2: Add the tens place: $3 + 2 = 5$, and include the carried over 1, totaling $5 + 1 = 6$. We write down 6.
• Step 3: Add the hundreds place: $1 + 5 = 6$. We write down 6.

By following these steps, the sum of the numbers 137 and 523 is calculated as 660.

Therefore, the solution to the problem is indeed $660$, which matches with choice 2 among the given options.

To solve this problem, we'll perform the vertical addition of the given numbers:

• Step 1: Write the numbers $228$ and $512$ vertically aligned by place value:

$\begin{array}{c} \\ &228 \\ + &512 \\ \hline \end{array}$

• Step 2: Add the digits in the ones column ($8 + 2$). This sum is $10$. Write down $0$ in the ones place and carry over $1$ to the tens column.

$\begin{array}{c} 1 \\ &228 \\ +&512 \\ \hline & ?0 \\ \end{array}$

• Step 3: Add the digits in the tens column ($2 + 1$) along with the carry of $1$. This gives $4$. Write $4$ in the tens place.

$\begin{array}{c} &228 \\ +&512 \\ \hline & ?40 \\ \end{array}$

• Step 4: Add the digits in the hundreds column ($2 + 5$). This sum is $7$. Write down $7$ in the hundreds place.

$\begin{array}{c} &228 \\ +&512 \\ \hline &740 \\ \end{array}$

Thus, the final answer is $740$.

Therefore, the solution to the problem is $740$.

To solve this problem, we'll follow these steps for vertical addition:

• Step 1: Add the digits in the units place.
• Step 2: Add the digits in the tens place, remembering to carry over if needed.
• Step 3: Add the digits in the hundreds place, again carrying over if needed.

Let's work through each step:

Step 1: Add the units digits: $4 + 9 = 13$. We write down the 3 and carry over the 1.

Step 2: Add the tens digits, including the carried over 1: $7 + 1 + 1 = 9$. Write down 9.

Step 3: Add the hundreds digits: $2 + 5 = 7$. No need to carry over as the sum is less than 10. Write down 7.

The final sum from our calculation is 793, written directly below the line in the vertical addition setup.

Therefore, the solution to the problem is $793$.

To solve this problem, we'll use a step-by-step approach with vertical addition:

• Step 1: Write both numbers vertically, aligning by place value.
  $\begin{aligned} & \phantom{1}376 \\ + & \phantom{1}214 \\ \end{aligned}$
• Step 2: Start with the ones place (rightmost column). Add 6 (from 376) and 4 (from 214):
  $6 + 4 = 10$. Write 0 in the ones place and carry over 1 to the tens place.
• Step 3: Move to the tens place. Add 7 + 1 (carry) + 1:
  $7 + 1 + 1 = 9$. Write 9 in the tens place.
• Step 4: Move to the hundreds place. Add 3 + 2:
  $3 + 2 = 5$. Write 5 in the hundreds place.

The final result of the addition is $590$.

Therefore, the solution to the problem is $590$.

To solve this problem, we will perform vertical addition, ensuring proper handling of place values and carrying, as necessary.

Here’s how the addition progresses step-by-step:

• Step 1: Add the ones place (rightmost column).
  $4 + 3 = 7$
  No carrying is needed since the sum is less than 10.
• Step 2: Add the tens place.
  $7 + 3 = 10$
  Write 0 in the tens position and carry over 1 to the hundreds column.
• Step 3: Add the hundreds place with the carried over value.
  $5 + 3 + 1 = 9$
  There's no further carrying needed because the sum is less than 10.

The final sum is obtained by combining the results from each column, giving us:

$\underline{907}$

So, the sum of 574 and 333 is $907$.

To solve this problem, let's perform vertical addition following these steps:

Step 1: Add the unit digits (rightmost column):

• $4 + 0 = 4$

Step 2: Add the tens digits (middle column):

• $1 + 9 = 10$
• Write $0$ and carry over $1$ to the hundreds column.

Step 3: Add the hundreds digits (leftmost column), including the carryover:

• $6 + 2 + 1 = 9$

The sum of the numbers $614$ and $290$ is $904$.

Therefore, the solution to the problem is $904$.