Examples with solutions for Vertical Addition: Addition of 3-digit numbers with the regrouping of tens and hundreds

Exercise #1

amp;137+amp;amp;523amp;776amp; \begin{aligned} &137 \\ +& \\ &523 \\ &\underline{\phantom{776}} & \\ \end{aligned}

Video Solution

Step-by-Step Solution

To solve this problem, we will perform vertical addition of the numbers 137 and 523:

  • Step 1: Add the ones place: 7+3=107 + 3 = 10. We write down 0 and carry over the 1 to the tens place.
  • Step 2: Add the tens place: 3+2=53 + 2 = 5, and include the carried over 1, totaling 5+1=65 + 1 = 6. We write down 6.
  • Step 3: Add the hundreds place: 1+5=61 + 5 = 6. We write down 6.

By following these steps, the sum of the numbers 137 and 523 is calculated as 660.

Therefore, the solution to the problem is indeed 660 660 , which matches with choice 2 among the given options.

Answer

660

Exercise #2

amp;228+amp;amp;512amp;776amp; \begin{aligned} &228 \\ +& \\ &512 \\ &\underline{\phantom{776}} & \\ \end{aligned}

Video Solution

Step-by-Step Solution

To solve this problem, we'll perform the vertical addition of the given numbers:

  • Step 1: Write the numbers 228228 and 512512 vertically aligned by place value:

228+512 \begin{array}{c} \\ &228 \\ + &512 \\ \hline \end{array}

  • Step 2: Add the digits in the ones column (8+28 + 2). This sum is 1010. Write down 00 in the ones place and carry over 11 to the tens column.

1228+512?0 \begin{array}{c} 1 \\ &228 \\ +&512 \\ \hline & ?0 \\ \end{array}

  • Step 3: Add the digits in the tens column (2+12 + 1) along with the carry of 11. This gives 44. Write 44 in the tens place.

228+512?40 \begin{array}{c} &228 \\ +&512 \\ \hline & ?40 \\ \end{array}

  • Step 4: Add the digits in the hundreds column (2+52 + 5). This sum is 77. Write down 77 in the hundreds place.

228+512740 \begin{array}{c} &228 \\ +&512 \\ \hline &740 \\ \end{array}

Thus, the final answer is 740740.

Therefore, the solution to the problem is 740 740 .

Answer

740

Exercise #3

amp;376+amp;amp;214amp;776amp; \begin{aligned} &376 \\ +& \\ &214 \\ &\underline{\phantom{776}} & \\ \end{aligned}

Video Solution

Step-by-Step Solution

To solve this problem, we'll use a step-by-step approach with vertical addition:

  • Step 1: Write both numbers vertically, aligning by place value.
    1376+1214 \begin{aligned} & \phantom{1}376 \\ + & \phantom{1}214 \\ \end{aligned}
  • Step 2: Start with the ones place (rightmost column). Add 6 (from 376) and 4 (from 214):
    6+4=10 6 + 4 = 10 . Write 0 in the ones place and carry over 1 to the tens place.
  • Step 3: Move to the tens place. Add 7 + 1 (carry) + 1:
    7+1+1=9 7 + 1 + 1 = 9 . Write 9 in the tens place.
  • Step 4: Move to the hundreds place. Add 3 + 2:
    3+2=5 3 + 2 = 5 . Write 5 in the hundreds place.

The final result of the addition is 590 590 .

Therefore, the solution to the problem is 590 590 .

Answer

590

Exercise #4

amp;574+amp;amp;333amp;776amp; \begin{aligned} &574 \\ +& \\ &333 \\ &\underline{\phantom{776}} & \\ \end{aligned}

Video Solution

Step-by-Step Solution

To solve this problem, we will perform vertical addition, ensuring proper handling of place values and carrying, as necessary.

Here’s how the addition progresses step-by-step:

  • Step 1: Add the ones place (rightmost column).
    4+3=74 + 3 = 7
    No carrying is needed since the sum is less than 10.
  • Step 2: Add the tens place.
    7+3=107 + 3 = 10
    Write 0 in the tens position and carry over 1 to the hundreds column.
  • Step 3: Add the hundreds place with the carried over value.
    5+3+1=95 + 3 + 1 = 9
    There's no further carrying needed because the sum is less than 10.

The final sum is obtained by combining the results from each column, giving us:

907 \underline{907}

So, the sum of 574 and 333 is 907907.

Answer

907

Exercise #5

amp;614+amp;amp;290amp;776amp; \begin{aligned} &614 \\ +& \\ &290 \\ &\underline{\phantom{776}} & \\ \end{aligned}

Video Solution

Step-by-Step Solution

To solve this problem, let's perform vertical addition following these steps:

Step 1: Add the unit digits (rightmost column):

  • 4+0=44 + 0 = 4

Step 2: Add the tens digits (middle column):

  • 1+9=101 + 9 = 10
  • Write 00 and carry over 11 to the hundreds column.

Step 3: Add the hundreds digits (leftmost column), including the carryover:

  • 6+2+1=96 + 2 + 1 = 9

The sum of the numbers 614614 and 290290 is 904904.

Therefore, the solution to the problem is 904 904 .

Answer

904

Exercise #6

amp;115+amp;amp;236amp;776amp; \begin{aligned} &115 \\ +& \\ &236 \\ &\underline{\phantom{776}} & \\ \end{aligned}

Video Solution

Step-by-Step Solution

To solve this problem, we'll use the following steps:

  • Step 1: Align the numbers 115 and 236 vertically by their place values:

115+236776 \begin{aligned} &115 \\ +&236 \\ &\underline{\phantom{776}} \\ \end{aligned}

Step 2: Start by adding the digits in the units (right-most) column:
5+6=115 + 6 = 11
Write 1 in the units place and carry over 1 to the tens column.

Step 3: Add the digits in the tens column with the carry:
1+3+1=51 + 3 + 1 = 5
Write 5 in the tens place.

Step 4: Add the digits in the hundreds column:
1+2=31 + 2 = 3
Write 3 in the hundreds place.

Putting it all together, we have:
115+236351\begin{aligned} &115 \\ +&236 \\ &\underline{351} \\ \end{aligned}

Therefore, the sum of 115 and 236 is 351\textbf{351}. The correct choice is option 3.

Answer

351

Exercise #7

amp;274+amp;amp;519amp;776amp; \begin{aligned} &274 \\ +& \\ &519 \\ &\underline{\phantom{776}} & \\ \end{aligned}

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps for vertical addition:

  • Step 1: Add the digits in the units place.
  • Step 2: Add the digits in the tens place, remembering to carry over if needed.
  • Step 3: Add the digits in the hundreds place, again carrying over if needed.

Let's work through each step:

Step 1: Add the units digits: 4+9=13 4 + 9 = 13 . We write down the 3 and carry over the 1.

Step 2: Add the tens digits, including the carried over 1: 7+1+1=9 7 + 1 + 1 = 9 . Write down 9.

Step 3: Add the hundreds digits: 2+5=7 2 + 5 = 7 . No need to carry over as the sum is less than 10. Write down 7.

The final sum from our calculation is 793, written directly below the line in the vertical addition setup.

Therefore, the solution to the problem is 793 793 .

Answer

793

Exercise #8

amp;453+amp;amp;152amp;776amp; \begin{aligned} &453 \\ +& \\ &152 \\ &\underline{\phantom{776}} & \\ \end{aligned}

Video Solution

Answer

605