Vertical Addition: Double digit addition beyond 100

To solve this problem, we will perform the following steps:

Step 1: Align the numbers by their place values:

$\begin{array}{c} 17 \\ + 94 \\ \hline \end{array}$

Step 2: Begin adding the rightmost digits, i.e., the ones column:

The ones digits are $7$ and $4$.
$7 + 4 = 11$.

Since $11$ is greater than $9$, we write down $1$ and carry over the $1$.

Step 3: Move to the tens column, adding the tens digits along with the carry:

The tens digits are $1$ and $9$, plus the carried over $1$:

$1 + 9 + 1 = 11$.

Write the last digit $1$ and carry over the $1$ to the hundreds column (excess here becomes the hundreds place).

Step 4: Align the result:

$\begin{array}{cc} \quad \quad \quad 1 ~\text{(carry)} \\ & \\ 17 \\ + 94~~~ \\ \hline 111~~ \\ \end{array}$

Thus, the sum of $17$ and $94$ is $111$.

Therefore, the correct answer is $111$.

To solve this problem, we'll follow the standard procedure for vertical addition:

• Step 1: Write the numbers vertically, aligning by place value. Here, we have:

  $27$

  $+85$

• Step 2: Add the digits in the units place (rightmost column).
  $7 + 5 = 12$
  Since 12 is 10 or more, we write down 2 in the units place and carry over 1 to the tens place.
• Step 3: Move to the tens place and add the digits, including the carryover from the previous step.
  $2 + 8 + 1 = 11$
  Write down 11 in the tens place, as there are no more numbers to add.

Therefore, the sum is $112$.

The correct answer is choice 3: 112.

To solve this problem of adding the numbers $32$ and $89$ using vertical addition, we will proceed as follows:

First, write the numbers vertically, ensuring their digits are aligned as follows:

   32
+  89
------

Now, let's add the numbers column by column:

• Add the rightmost column (units column):
  $2 + 9 = 11$ Since 11 is greater than 9, we write down 1 in the units place and carry over 1 to the tens column.
• Add the tens column:
  Add the numbers in the tens place (3 and 8) with the carryover of 1: $3 + 8 + 1 = 12$ Place 2 in the tens place and write down 1 in the hundreds place.

Therefore, lining it up nicely, the sum can be calculated as:

   32
+  89
------
  121

Thus, the result of adding $32$ and $89$ is $121$.

The correct choice is Choice 1: $\boxed{121}$.

To solve this problem, we'll follow these steps:

• Step 1: Add the digits in the units column.
• Step 2: Add the digits in the tens column, considering any carried value.
• Step 3: Write down the resulting number as the answer.

Now, let's work through each step:
Step 1: Add the units digits. The units digit of 45 is 5, and the units digit of 77 is 7. Adding these gives: $5 + 7 = 12$. Since 12 is greater than 9, we write down 2 in the units column and carry over 1 to the tens column.
Step 2: Add the tens digits. The tens digit of 45 is 4, and the tens digit of 77 is 7. Including the carry-over 1 gives: $4 + 7 + 1 = 12$. Since 12 is a two-digit number, we write down 2 in the tens column and carry over 1 again, which is written in the hundreds column.
Step 3: Since there is nothing to add to the carried 1 in the hundreds column, we simply write it down as is.

Therefore, the solution to the problem is $122$.

To solve this problem, we'll add the numbers 53 and 68 using vertical addition. Follow these steps:

Step 1: Align the numbers vertically by place value:

\begin{aligned} &53 \\ + &68 \\ \end{aligned}

Step 2: Add the units digits (rightmost column):

$3 + 8 = 11$

• The result is 11. Write down 1 in the units column, and carry over 1 to the tens column.

Step 3: Add the tens digits (leftmost column), including the carry:

$5 + 6 + 1 = 12$

• Write down 2 in the tens column, and carry over 1 to the hundreds column. This gives us a final result:

\begin{aligned} &121 \\ \end{aligned}

Therefore, the correct answer is $121$.

To solve this problem, we'll perform vertical addition for the numbers 99 and 25:

• Step 1: Add the ones place digits:
  The ones digit of 99 is 9, and the ones digit of 25 is 5. Adding these together: $9 + 5 = 14$. We write down 4 and carry over the 1.
• Step 2: Add the tens place digits, including the carryover:
  The tens digit of 99 is 9, and the tens digit of 25 is 2. With the 1 carried over, we compute: $9 + 2 + 1 = 12$. Since there's no place to the left of tens for a third digit in this case, the whole number 12 is written in the tens and hundreds place.

Combining these, the sum is put together as 124.

Therefore, the solution to the problem is $124$.