Calculate the DE:EC Ratio in a Trapezoid with 1:3 Area Division

Area Ratios with Trapezoid Division

The area of trapezoid ABCD is X cm².

The line AE creates triangle AED and parallelogram ABCE.

The ratio between the area of triangle AED and the area of parallelogram ABCE is 1:3.

Calculate the ratio between sides DE and EC.

AAABBBCCCDDDEEE

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:18 Let's find the ratio between D E and E C.
00:22 Use the triangle area formula to begin.
00:25 Draw a height and label it H.
00:28 Then, it's height H times D E, all divided by 2.
00:33 Now, for the parallelogram's area formula.
00:37 It's base E C times height H.
00:44 Using the data, notice the area ratio is one-third.
00:51 Let's set up our area equations step-by-step.
00:59 Remember, dividing by 2 is like multiplying by one-half.
01:06 Watch how the heights cancel out.
01:13 Next, multiply by the denominators, E C and 3.
01:20 Now, let's isolate E C.
01:24 Divide by E C to get the expression we need.
01:31 Divide by 1.5 to find our ratio.
01:39 And there's the ratio of the sides.
01:42 Great job! That's how we solve this.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

The area of trapezoid ABCD is X cm².

The line AE creates triangle AED and parallelogram ABCE.

The ratio between the area of triangle AED and the area of parallelogram ABCE is 1:3.

Calculate the ratio between sides DE and EC.

AAABBBCCCDDDEEE

2

Step-by-step solution

To calculate the ratio between the sides we will use the existing figure:

AAEDAABCE=13 \frac{A_{AED}}{A_{ABCE}}=\frac{1}{3}

We calculate the ratio between the sides according to the formula to find the area and then replace the data.

We know that the area of triangle ADE is equal to:

AADE=h×DE2 A_{ADE}=\frac{h\times DE}{2}

We know that the area of the parallelogram is equal to:

AABCD=h×EC A_{ABCD}=h\times EC

We replace the data in the formula given by the ratio between the areas:

12h×DEh×EC=13 \frac{\frac{1}{2}h\times DE}{h\times EC}=\frac{1}{3}

We solve by cross multiplying and obtain the formula:

h×EC=3(12h×DE) h\times EC=3(\frac{1}{2}h\times DE)

We open the parentheses accordingly:

h×EC=1.5h×DE h\times EC=1.5h\times DE

We divide both sides by h:

EC=1.5h×DEh EC=\frac{1.5h\times DE}{h}

We simplify to h:

EC=1.5DE EC=1.5DE

Therefore, the ratio between is: ECDE=11.5 \frac{EC}{DE}=\frac{1}{1.5}

3

Final Answer

1:1.5 1:1.5

Key Points to Remember

Essential concepts to master this topic
  • Area Formula: Triangle area = 12×base×height \frac{1}{2} \times base \times height , parallelogram = base × height
  • Ratio Setup: AreatriangleAreaparallelogram=13 \frac{Area_{triangle}}{Area_{parallelogram}} = \frac{1}{3} gives cross-multiplication equation
  • Verification: Check DE:EC = 1:1.5 means EC = 1.5×DE in the original setup ✓

Common Mistakes

Avoid these frequent errors
  • Using wrong area formulas for shapes
    Don't confuse triangle and parallelogram area formulas = wrong ratios! Triangle AED uses ½×base×height while parallelogram ABCE uses base×height only. Always identify the shape type before applying area formulas.

Practice Quiz

Test your knowledge with interactive questions

Angle A is equal to 30°.
Angle B is equal to 60°.
Angle C is equal to 90°.

Can these angles form a triangle?

FAQ

Everything you need to know about this question

Why is the parallelogram area h×EC and not something else?

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In this trapezoid setup, when line AE divides it, the parallelogram ABCE has parallel sides AB and EC. The height is the same as the trapezoid's height h, and the base is EC.

How do I know which segments to use as bases?

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Look at the diagram carefully! Triangle AED has base DE and the same height h. Parallelogram ABCE has base EC and height h. The line AE creates this division.

Why do we cross-multiply in the ratio?

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Cross-multiplication helps us solve the proportion AreatriangleAreaparallelogram=13 \frac{Area_{triangle}}{Area_{parallelogram}} = \frac{1}{3} . This gives us 3 × (triangle area) = 1 × (parallelogram area), which we can solve.

What does the final ratio 1:1.5 actually mean?

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The ratio DE:EC = 1:1.5 means that if DE has length 1 unit, then EC has length 1.5 units. In other words, EC is 1.5 times longer than DE.

Can I check my answer using the original area ratio?

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Yes! If DE:EC = 1:1.5, then triangle area should be 12h×1=0.5h \frac{1}{2}h \times 1 = 0.5h and parallelogram area should be h×1.5=1.5h h \times 1.5 = 1.5h . The ratio is 0.5h:1.5h = 1:3 ✓

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