Perimeter of a Triangle - Examples, Exercises and Solutions

The perimeter of a triangle is equal to the sum of all its sides together:

$11+7+13=11+20=31$

The perimeter of the triangle is equal to the sum of all sides together, therefore:

$6+8+10=14+10=24$

To find the perimeter of triangle $\triangle ABC$, we need to sum the lengths of its sides:

• Side $AB = 3$
• Side $BC = 4$
• Side $CA = 5$

Using the formula for the perimeter of a triangle:

$\text{Perimeter} = AB + BC + CA$

Substitute the known values:

$\text{Perimeter} = 3 + 4 + 5$

$\text{Perimeter} = 12$

Thus, the perimeter of triangle $\triangle ABC$ is $\mathbf{12}$.

From the multiple-choice options provided, the correct choice is option 1: 12.

To solve this problem, we'll follow these steps:

• Step 1: Identify the given information.
• Step 2: Apply the perimeter formula for a triangle.
• Step 3: Perform the addition to find the perimeter.

Now, let's work through each step:

Step 1: We have the lengths of the sides of $\triangle ABC$ as follows:
$AB = 7$, $BC = 14$, and $CA = 8$.

Step 2: We'll use the formula for the perimeter of a triangle, which is the sum of its side lengths:
$P = AB + BC + CA$.

Step 3: Plugging in the values, we calculate:
$P = 7 + 14 + 8 = 29$.

Therefore, the perimeter of $\triangle ABC$ is $\textbf{29}$.

Due to the fact that the the triangle is isosceles, its two legs are equal to one another.

Therefore, the base is 7 and the other two sides are 12.

The perimeter of a triangle is equal to the sum of all the sides together:

$12+12+7=24+7=31$