Power of a Power

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Power of a Power

When we have an expression raised to a power that, in turn, is raised (within parentheses) to another power, we can multiply the exponents and raise the base number to the result of this multiplication.

Formula of the property

(an)m=a(nƗm) (a^n)^m=a^{(n\times m)}
This property is also concerning algebraic expressions.

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Test yourself on power of a power!

einstein

Insert the corresponding expression:

\( \)\( \left(6^2\right)^7= \)

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A - When there is a power inside parentheses.

Power of a power basic examples

Example 1

(43)2=(4^3 )^2=
We can see that the exponent 2 2 applies to the entire expression 43 4^3 .
therefore, we can multiply both exponents and raise the base to the result of the multiplication.
We will obtain:
43Ɨ2=46=4096 4^{3\times2}=4^6=4096


If we were presented with an exercise in which there is a certain power over a term that already has another power, we will multiply the powers that have equal bases.

Example 2

Let's start with an easy one:

(X6āˆ’3)4= (X^{6-3})^4=

We'll see that there is a subtraction in the exponents of X X and that, first, we must deal with it.

We'll do this and obtain:

(X3)4= (X^3)^4=

Now we can apply the power of a power property and multiply the exponents, we will obtain:

X12 X^{12}


Good. Let's move on to a more complicated example:

Example 3

(2X2X)4ā‹…(4Y2Y)3= (\frac{2X^2}{X})^4\cdot(\frac{4Y^2}{Y})^3=

Recommendation:

Before applying the power located outside the parentheses to each of the terms separately, first, it is advisable to carefully observe the exercise.

Upon observing it, you will realize that you can reduce or subtract exponents from the fractions themselves, before touching the exponent located outside the parentheses.

We will subtract the exponents of the corresponding bases (we will reduce) and obtain:

(2X)4ā‹…(4Y)3= (2X)^4\cdot(4Y)^3=

Now we can apply the exponent to each of the terms separately (do not forget about the coefficients) and we will get:

16X4ā‹…64Y3= 16X^4\cdot64Y^3=

We can try to find a common term to better organize the exercise and we will obtain:

16(X4ā‹…4Y3) 16(X^4\cdot4Y^3)


Perfect! Now, let's move on to a complex and slightly different example:

Power of a power advanced examples:

Example 4

(2X+3)Xā‹…(2X)4= (2^{X+3})^X\cdot(2^X)^4=

Don't worry, even if there are mathematical operations among the exponents, the properties do not change.

Let's start with the first expression which is a bit more complex. We learned that, when we have a power of a power we multiply the exponents.

We will multiply the entire exponent that is inside the parentheses by the entire exponent located outside the parentheses. We will do the same with the other term and we will obtain:

2(X+3)ā‹…Xā‹…24X= 2^{(X+3)\cdot X}\cdot2^{4X}=

We will multiply the exponents of the first expression and we will obtain:

2X2+3Xā‹…24X= 2^{X^2+3X}\cdot2^{4X}=

Now let's remember that, if we have a multiplication operation between equal bases we can add the exponents.

We will do this and we will obtain:

2X2+3X+4X= 2^{X^2+3X+4X}=

We simplify terms in the exponent and it will give us:

2X2+7X= 2^{X^2+7X}=


Example 5

Simplify the following expression:

(3x3y2)2(2x2y4)4(2xy2)3 \frac{\left(3x^3y^2\right)^2\left(2x^2y^4\right)^4}{\left(2xy^2\right)^3}

To simplify the expression, first apply the power of a product property, which allows us to raise each of the factors inside the parenthesis to the indicated power, then apply the power of a power property. We obtain:

(32(x3)2(y2)2)ā‹…(24(x2)4(y4)4)23(x)3(y2)3=(9x6y4)ā‹…(16x8y16)8x3y6 \frac{\left(3^2\left(x^3\right)^2\left(y^2\right)^2\right)\cdot\left(2^4\left(x^2\right)^4\left(y^4\right)^4\right)}{2^3\left(x^{}\right)^3\left(y^2\right)^3}=\frac{\left(9x^6y^4\right)\cdot\left(16x^8y^{16}\right)}{8x^3y^6}

Finally, apply the properties of products and quotients of powers with the same base:

144x6+8y4+168x3y6=114x14y208x3y6=18x14āˆ’3y20āˆ’6=18x11y14 \frac{144x^{6+8}y^{4+16}}{8x^3y^6}=\frac{114x^{14}y^{20}}{8x^3y^6}=18x^{14-3}y^{20-6}=18x^{11}y^{14}


Exercises on Power of a Power

Basic Exercises of Power of a Power:

(42)2= \left(4^2\right)^2=

(33)2= \left(3^3\right)^2=

(22)2= \left(2^2\right)^2=

(52)5= \left(5^2\right)^5=

(72)2= \left(7^2\right)^2=


Exercises of Power of a Power:

(X2āˆ’4)2= \left(X^{2-4}\right)^2=

(X2+4)3= \left(X^{2+4}\right)^3=

(X21āˆ’7)2= \left(X^{21-7}\right)^2=

(X11āˆ’9)3= \left(X^{11-9}\right)^3=

(X5āˆ’3)3= \left(X^{5-3}\right)^3=


Intermediate Level Power of a Power Exercises

(4X5X)2ā‹…(3Y3Y)3= (\frac{4X^5}{X})^2\cdot(\frac{3Y^3}{Y})^3=

(4Y52Y)2ā‹…(Y42Y)4= (\frac{4Y^5}{2Y})^2\cdot(\frac{Y^4}{2Y})^4=

(2X52X)3ā‹…(X32X)3= (\frac{2X^5}{2X})^3\cdot(\frac{X^3}{2X})^3=

(2Y52Y5)3ā‹…(X32X3)3= (\frac{2Y^5}{2Y^5})^3\cdot(\frac{X^3}{2X^3})^3=

(2Y52Y5)3ā‹…(X32X3)3ā‹…(2Y32Y6)2ā‹…(X22X2)2= (\frac{2Y^5}{2Y^5})^3\cdot(\frac{X^3}{2X^3})^3\cdot(\frac{2Y^3}{2Y^6})^2\cdot(\frac{X^2}{2X^2})^2=


Advanced Level Power of a Power Exercises

(3X+7)Xā‹…(3X)3= (3^{X+7})^X\cdot(3^X)^3=

(2Xāˆ’2)Xā‹…(3Xāˆ’2)6= (2^{X-2})^X\cdot(3^{X-2})^6=

(3Xāˆ’3)Xā‹…(3Xāˆ’3)3= (3^{X-3})^X\cdot(3^{X-3})^3=

(32āˆ’3)2ā‹…(7Xāˆ’5)2= (3^{2-3})^2\cdot(7^{X-5})^2=

(8Xāˆ’3)Xā‹…(72X+2)X= (8^{X-3})^X\cdot(72^{X+2})^X=


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Review Questions

What is a power of a power?

A power of a power is an expression in which we raise a power to another power.

What is a power of a power and example?

A power of a power is a power in which the base is also a power, for example:

  • (32)5 \left(3^2\right)^5
  • (52x+1)2 \left(5^{2x+1}\right)^2

How do you calculate a power of a power?

To solve a power of a power, we must multiply the exponents, and the result of the multiplication is placed as the exponent on the initial base.


Exercises on Power of a Power

Exercise 1

Assignment

23Ɨ24+(43)2+2523= 2^3\times2^4+(4^3)^2+\frac{2^5}{2^3}=

Solution

23ā‹…24+(43)2+2523= 2^3\cdot2^4+\left(4^3\right)^2+\frac{2^5}{2^3}=

23+4+43ā‹…2+2(5āˆ’3)= 2^{3+4}+4^{3\cdot2}+2^{\left(5-3\right)}=

27+46+22 2^7+4^6+2^2

Answer

22+27+46 2^2+2^7+4^6


Do you know what the answer is?

Exercise 2

Assignment

(4x)y= (4^x)^y=

Solution

(4x)y=4xā‹…y \left(4^x\right)^y=4^{x\cdot y}

Answer

4xy 4^{xy}


Exercise 3

Assignment

(22)3+(33)4+(92)6= (2^2)^3+(3^3)^4+(9^2)^6=

Solution

We will use the formula

(am)n=amā‹…n \left(a^m\right)^n=a^{m\cdot n}

22ā‹…3+33ā‹…4ā‹…92ā‹…6= 2^{2\cdot3}+3^{3\cdot4}\cdot9^{2\cdot6}=

26+312ā‹…912 2^6+3^{12}\cdot9^{12}

Answer

26+312+912 2^6+3^{12}+9^{12}


Check your understanding

Exercise 4

Assignment

(42)3+(g3)4= (4^2)^3+(g^3)^4=

Solution

We will use the formula

(am)n=amā‹…n \left(a^m\right)^n=a^{m\cdot n}

42ā‹…3+93ā‹…4= 4^{2\cdot3}+9^{3\cdot4}=

46+912 4^6+9^{12}

Answer

46+912 4^6+9^{12}


Exercise 5

Assignment

((7Ɨ3)2)6+(3āˆ’1)3Ɨ(23)4= ((7\times3)^2)^6+(3^{-1})^3\times(2^3)^4=

Solution

We will use the formula

(am)n=amā‹…n \left(a^m\right)^n=a^{m\cdot n}

(7ā‹…3)2ā‹…6+3āˆ’1ā‹…3ā‹…23ā‹…4= (7\cdot3)^{2\cdot6}+3^{-1\cdot3}\cdot2^{3\cdot4}=

2112+3āˆ’3ā‹…212 21^{12}+3^{-3}\cdot2^{12}

Answer

2112+3āˆ’3ā‹…212 21^{12}+3^{-3}\cdot2^{12}


Do you think you will be able to solve it?

Examples with solutions for Power of a Power

Exercise #1

Insert the corresponding expression:

(62)7= \left(6^2\right)^7=

Video Solution

Step-by-Step Solution

To solve this problem, we need to simplify the expression (62)7 \left(6^2\right)^7 using the power of a power rule.

The power of a power rule states that when you have an expression of the form (am)n (a^m)^n , this can be simplified to amƗn a^{m \times n} .

Let's apply this rule to the given expression:

1. Identify the base and exponents: - Base: 6 6 - First exponent (inside parenthesis): 2 2 - Second exponent (outside parenthesis): 7 7

2. Apply the power of a power rule: - Simplify (62)7=62Ɨ7 (6^2)^7 = 6^{2 \times 7} .

3. Calculate the final exponent: - Multiply the exponents: 2Ɨ7=14 2 \times 7 = 14 . - Therefore, the simplified expression is 614 6^{14} .

Considering the answer choices provided:

  • Choice 1: 62Ɨ7 6^{2 \times 7} (Correct, as per our solution).
  • Choice 2: 62+7 6^{2 + 7} (Incorrect, addition is used instead of multiplication).
  • Choice 3: 67āˆ’2 6^{7-2} (Incorrect, subtraction is used incorrectly).
  • Choice 4: 672 6^{\frac{7}{2}} (Incorrect, division is used incorrectly).

Thus, the correct answer to the problem is 62Ɨ7 6^{2 \times 7} , which simplifies to 614 6^{14} , and aligns with Choice 1.

Answer

62Ɨ7 6^{2\times7}

Exercise #2

Insert the corresponding expression:

(45)2= \left(4^5\right)^2=

Video Solution

Step-by-Step Solution

To solve this problem, let's carefully follow these steps:

  • Step 1: Identify the base and exponents in the expression.
  • Step 2: Use the power of a power rule to simplify the expression.
  • Step 3: Choose the appropriate option from the given answer choices.

Now, let's break this down:

Step 1: The expression given is (45)2(4^5)^2. Here, the base is 4, the inner exponent is 5, and the outer exponent is 2.

Step 2: We apply the power of a power rule for exponents, which states that (am)n=amā‹…n(a^m)^n = a^{m \cdot n}.

Using the rule, we have:

(45)2=45ā‹…2=410 (4^5)^2 = 4^{5 \cdot 2} = 4^{10}

This means the expression (45)2(4^5)^2 can be simplified to 4104^{10}.

Step 3: From the answer choices provided, we need to select the one corresponding to 45ā‹…24^{5 \cdot 2}:

  • Choice 1: 4254^{\frac{2}{5}} - This is incorrect because it deals with division of exponents and not multiplication.
  • Choice 2: 45āˆ’24^{5-2} - This is incorrect as it incorrectly subtracts the exponents.
  • Choice 3: 45Ɨ24^{5 \times 2} - This is the correct choice.
  • Choice 4: 45+24^{5+2} - This is incorrect as it incorrectly adds the exponents.

Therefore, the solution to the problem is 45Ɨ2=4104^{5 \times 2} = 4^{10}, which corresponds to choice 3.

Answer

45Ɨ2 4^{5\times2}

Exercise #3

Insert the corresponding expression:

(32)4= \left(3^2\right)^4=

Video Solution

Step-by-Step Solution

To solve this problem, we'll utilize the Power of a Power rule of exponents, which states:

(am)n=amā‹…n (a^m)^n = a^{m \cdot n}

Given the expression (32)4 (3^2)^4 , we need to simplify this by applying the rule:

  • Step 1: Recognize that we have a base of 3, with an exponent of 2, raised to another exponent of 4.
  • Step 2: According to the Power of a Power rule, we multiply the exponents: 2Ɨ4 2 \times 4 .
  • Step 3: Compute the product of the exponents: 2Ɨ4=8 2 \times 4 = 8 .
  • Step 4: Rewrite the expression as a single power: 38 3^8 .

This simplifies the original expression (32)4 (3^2)^4 to 38 3^{8} .

Comparing this with the given choices:

  • Choice 1: 32Ɨ4 3^{2 \times 4} is equivalent to 38 3^8 , confirming it matches our solution.
  • Choices 2, 3, and 4 involve incorrect operations with exponents (addition, subtraction, division) and therefore do not align with the necessary Power of a Power rule.

Thus, the correct answer to the problem is:

38 3^{8} , and this corresponds to Choice 1: 32Ɨ4 3^{2 \times 4} .

Answer

32Ɨ4 3^{2\times4}

Exercise #4

Insert the corresponding expression:

(22)3= \left(2^2\right)^3=

Video Solution

Step-by-Step Solution

We are given the expression (22)3 (2^2)^3 and need to simplify it using the laws of exponents and identify the corresponding expression among the choices.

To simplify the expression (22)3 (2^2)^3 , we use the "power of a power" rule, which states that (am)n=amƗn(a^m)^n = a^{m \times n}.

Applying this rule to our expression, we have:

(22)3=22Ɨ3(2^2)^3 = 2^{2 \times 3}

Calculating the new exponent:

2Ɨ3=62 \times 3 = 6

Thus, the expression simplifies to:

262^6

Now, let's compare our result 262^6 with the given choices:

  • Choice 1: 22+3=252^{2+3} = 2^5 - Incorrect, as our expression evaluates to 262^6, not 252^5.
  • Choice 2: 22āˆ’3=2āˆ’12^{2-3} = 2^{-1} - Incorrect, as our expression evaluates to 262^6, not 2āˆ’12^{-1}.
  • Choice 3: 2232^{\frac{2}{3}} - Incorrect, as our expression evaluates to 262^6, not a fractional exponent expression.
  • Choice 4: 22Ɨ3=262^{2 \times 3} = 2^6 - Correct, as this matches our simplified expression.

Therefore, the correct choice is Choice 4: 22Ɨ32^{2 \times 3}.

Answer

22Ɨ3 2^{2\times3}

Exercise #5

Insert the corresponding expression:

(103)3= \left(10^3\right)^3=

Video Solution

Step-by-Step Solution

To solve this problem, we will proceed with the following steps:

  • Identify the expression structure.
  • Apply the power of a power rule for exponents.
  • Simplify the expression.

Now, let's work through each step in detail:

Step 1: Identify the expression structure.
We have the expression (103)3(10^3)^3. This indicates a power of a power where the base is 10, the inner exponent is 3, and the entire expression is raised to another power of 3.

Step 2: Apply the power of a power rule.
The rule states (am)n=amƗn(a^m)^n = a^{m \times n}. Applying this to our specific expression gives us:

(103)3=103Ɨ3\left(10^3\right)^3 = 10^{3 \times 3}

Step 3: Perform the multiplication in the exponent.
Calculating 3Ɨ33 \times 3, we get 99. Thus, the expression simplifies to:

10910^9

Therefore, the solution to the problem is:

103Ɨ3\boxed{10^{3 \times 3}}

Examining the provided choices:

  • Choice 1: 103+310^{3+3} - Incorrect, because it uses addition instead of multiplication.
  • Choice 2: 103Ɨ310^{3 \times 3} - Correct, as it matches our derived expression.
  • Choice 3: 103310^{\frac{3}{3}} - Incorrect, because it uses division instead of multiplication.
  • Choice 4: 103āˆ’310^{3-3} - Incorrect, because it uses subtraction instead of multiplication.

The correct answer is 103Ɨ310^{3 \times 3}, which is represented by Choice 2.

Answer

103Ɨ3 10^{3\times3}

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