When finding an expression with multiplication or an exercise that has only multiplication operationsinside a parenthesis and the wholes expression is raised to a certain exponent, we can take the exponent and apply it to each of the terms of the expression or exercise. We must not forget to keep the multiplication signs between the terms. Property formula: (aĆb)n=anĆbn This property also pertains to algebraic expressions.
Choose the expression that corresponds to the following:
\( \)\( \left(2\times11\right)^5= \)
Incorrect
Correct Answer:
\( 2^5\times11^5 \)
Practice more now
Example of the power of a multiplication
First example
(5Ć2)3= Notice that we have a power of a product of whole numbers. We can see that the exponent3 is applied to the entire expression enclosed within the parentheses, therefore, we can raise each of the terms while maintaining the multiplication sign between them. We will obtain: 5323=Ć 125Ć8=1000
If we have a multiplication exercise with an exponent, we can apply the exponent to each of the terms separately.
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Test your knowledge
Question 1
Choose the expression that corresponds to the following:
\( \left(10\times3\right)^4= \)
Incorrect
Correct Answer:
All of the above
Question 2
Choose the expression that represents the following:
\( \left(9\times7\right)^4= \)
Incorrect
Correct Answer:
\( 9^4\times7^4 \)
Question 3
Choose the expression that corresponds to the following:
\( \left(6\times8\right)^4= \)
Incorrect
Correct Answer:
Answers (a) and (b) are correct.
Let's look at some examples
(2X)3
We will notice that the exponent applies to the entire expression enclosed in parentheses and that between the 2 and the X there is, in fact, a multiplication operation.
We can raise each of the terms of the expression to the exponent and we will obtain:
23ā X3=
8ā X3=
We will multiply theX by its coefficient and we will get:
8X3
Now let's move on to a slightly more complicated exercise.
(22ā X3)2
We see that the exponent 2 is outside the parentheses, therefore, it applies to the entire expression. The terms of the expression are multiplied, therefore, it is the power of a multiplication.
Well, now we can apply the exponent to each of the terms separately and we will not forget to maintain the multiplication between them.
We obtain:
(22)2ā (x3)2
We have obtained what is called: Power of a power
To be able to continue solving the exercise we will remember the following property:
Power of power
If we have a power of a power we must perform a multiplication of exponents, that is, multiply powers.
In symbols:
(an)k=anā k
First we will multiply the exponent located outside the parentheses by the exponent of the base2 and then, we will do it by the exponent of the baseX.
We will get:
24ā X6
16ā X6
Now we will multiply theX by its coefficient and we will have:
16X6
Do you know what the answer is?
Question 1
Choose the expression that corresponds to the following:
\( \left(5\times7\right)^3= \)
Incorrect
Correct Answer:
\( 5^3\times7^3 \)
Question 2
Choose the expression that corresponds to the following:
\( \left(2\times6\right)^3= \)
Incorrect
Correct Answer:
\( 2^3\times6^3 \)
Question 3
Choose the expression that corresponds to the following:
\( \left(5\times3\right)^3= \)
Incorrect
Correct Answer:
Answers (b) and (c) are correct.
Let's move on to see another example
which will demonstrate to us that no matter how many terms the exercise includes, as long as there is multiplication between them and as long as they are raised to a certain power located outside of the parentheses, in such a case we can apply the power to each of the terms separately and maintain the multiplication operation between them.
(22Xā X5ā X2ā 2ā 5)3
Recommendation:
Before applying the power located outside of the parentheses to each of the terms separately, carefully observe the exercise.
If you look closely and are thoroughly familiar with the properties of powers or laws of exponents, you will immediately see that, you can first act inside the parentheses using the property of multiplication of powers with the same base to simplify the expression.
Let's remember that, when we have a multiplication of powers with the same base, we can add the exponents and obtain a single base with a single exponent.
If there is no exponent it means that the exponent is one and it is important that we remember to add it.
Upon observing the exercise we will discover that there are some equal bases: 2 and X.
Since the operation between all the terms is multiplication we can add the relevant exponents and in this way we will arrive at:
(23ā X8ā 5)3=
Now, with an already abbreviated expression between the parentheses, it will be easier and faster for us to apply the power located outside of the parentheses to each of the terms.
We will do it and obtain:
(23)3ā (x8)3ā (5)3=
29ā X24ā 53=
We can continue solving and we will arrive at:
512ā X24ā 125=
64,000ā X24=
Let's multiply theX by its coefficient and it will give us:
64,000X24=
Exercises with the Power of a Multiplication
(2Ć5)3=
(1Ć2)3=
(3Ć3)3=
(2Ć2)2=
(7Ć4)2=
(32XĆX5ĆX3)3=
(52XĆX2ĆX2)2=
(82XĆX2ĆX25Ć3X)3=
(24Ć5X2ĆX37Ć3X)3=
(24Ć5X2ĆXĆ8ĆX2)3=
Check your understanding
Question 1
Choose the expression that corresponds to the following:
\( \left(4\times2\right)^2= \)
Incorrect
Correct Answer:
\( 4^2\times2^2 \)
Question 2
Insert the corresponding expression:
\( \left(2\times3\right)^2= \)
Incorrect
Correct Answer:
\( 2^2\times3^2 \)
Question 3
Choose the expression that corresponds to the following:
\( \left(25\times4\right)^3= \)
Incorrect
Correct Answer:
All answers are correct.
Review Questions
How to solve a power of a multiplication?
To solve a power of a multiplication we must raise each of the factors to the indicated power and maintain the multiplication sign between the terms.
How to solve multiplication of powers with different bases?
The law of exponents indicates that when we have multiplication of powers with the same base, we must add the exponents, however, if we have different bases we cannot apply this law.
How to multiply powers with different bases and the same exponent?
If the base is different we cannot add the exponents, although in some exercises it will be possible to manipulate the expressions to equalize the bases and apply the law of exponents.
How to solve addition of powers with different bases?
There is no law for the addition of powers. It does not matter if they have the same base or not.
How are powers multiplied with the same exponent and different bases?
If the base is different, we cannot directly apply the law of exponents. Sometimes we may manipulate the bases to try to equalize them and apply the law.
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In theTutorelablog, you will find a variety of articles about mathematics.
Do you think you will be able to solve it?
Question 1
Choose the expression that corresponds to the following:
\( \left(2\times4\right)^{10}= \)
Incorrect
Correct Answer:
\( 2^{10}\times4^{10} \)
Question 2
Choose the expression(s) that corresponds to the following:
\( \left(5\times6\right)^9= \)
Incorrect
Correct Answer:
\( 5^9\times6^9 \)
Question 3
Choose the expression that corresponds to the following:
\( \left(20\times5\right)^7= \)
Incorrect
Correct Answer:
All answers are correct.
Examples with solutions for Power of a Product
Exercise #1
Choose the expression that corresponds to the following:
(2Ć11)5=
Video Solution
Step-by-Step Solution
To solve the expression, we can apply the rule for the power of a product, which states that(aĆb)n=anĆbn.
In this case, our expression is (2Ć11)5, wherea=2 and b=11, and n=5.
Applying the power of a product rule gives us:
an=25
bn=115
Therefore, (2Ć11)5=25Ć115.
Answer
25Ć115
Exercise #2
Choose the expression that corresponds to the following:
(10Ć3)4=
Video Solution
Step-by-Step Solution
To solve this problem, we'll apply the power of a product rule to the expression (10Ć3)4.
Step 1: Identify the expression. The given expression is (10Ć3)4.
Step 2: Apply the power of a product law. According to the rule, (aĆb)n=anĆbn, our expression becomes: (10Ć3)4=104Ć34.
Step 3: Evaluate the choices: - First choice: 34Ć104 Rearranging terms, this is equivalent to 104Ć34. Therefore, it matches our transformed expression. - Second choice: 304 Since 30=10Ć3, (10Ć3)4=304. This simplifies to the same expression. - Third choice: 104Ć34
Therefore, the solution is that all answers are correct.
Answer
All of the above
Exercise #3
Choose the expression that represents the following:
(9Ć7)4=
Video Solution
Step-by-Step Solution
To solve the problem, we need to apply the power of a product rule for exponents, which states that if you have a product raised to an exponent, you can apply the exponent to each factor in the product individually.
The general form of this rule is:
(aĆb)n=anĆbn
According to this formula, when we have the expression(9Ć7)4 we apply the exponent 4 to each factor within the parentheses.
This process results in:
Raising 9 to the power of 4: 94
Raising 7 to the power of 4: 74
Therefore, the expression simplifies to:
94Ć74
Answer
94Ć74
Exercise #4
Choose the expression that corresponds to the following:
(6Ć8)4=
Video Solution
Step-by-Step Solution
To solve the problem of rewriting the expression (6Ć8)4, we will apply the power of a product rule. This rule states that (aĆb)n=anĆbn.
Let's apply this rule to our expression:
(6Ć8)4 can be rewritten as 64Ć84 by applying the Power of a Product rule.
Now, let's consider the available options:
Choice 1: 64Ć84 - This choice directly corresponds to our rewritten expression using the power of a product rule.
Choice 2: 484 - This represents the product calculated first (6Ć8=48) and then raised to the fourth power. This is also a valid representation since (6Ć8)4 is equivalent to 484.
Choice 3: 64Ć8 - This is incorrect because it does not correctly apply the power of a product rule.
Therefore, the correct answer according to the given choices is that (a) and (b) are correct.
Answer
Answers (a) and (b) are correct.
Exercise #5
Choose the expression that corresponds to the following:
(5Ć7)3=
Video Solution
Step-by-Step Solution
The problem requires us to simplify the expression (5Ć7)3 using the power of a product rule.
The power of a product rule states that for any numbers a and b, and any integer n, the expression (aĆb)n can be expanded to anĆbn.
Applying this rule to the given expression:
Identify the values of a and b as 5 and 7, respectively.