Exponent of a Multiplication

šŸ†Practice power of a product

When finding an expression with multiplication or an exercise that has only multiplication operations inside a parenthesis and the wholes expression is raised to a certain exponent, we can take the exponent and apply it to each of the terms of the expression or exercise.
We must not forget to keep the multiplication signs between the terms.
Property formula:
(aƗb)n=anƗbn (a\times b)^n=a^n\times b^n
This property also pertains to algebraic expressions.

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Test yourself on power of a product!

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Insert the corresponding expression:

\( \)\( \left(2\times11\right)^5= \)

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Example of the power of a multiplication

First example

(5Ɨ2)3= (5\times2)^3=
Notice that we have a power of a product of whole numbers. We can see that the exponent 3 3 is applied to the entire expression enclosed within the parentheses, therefore, we can raise each of the terms while maintaining the multiplication sign between them.
We will obtain:
5323=Ɨ 5^32^3=\times
125Ɨ8=1000 125\times8=1000


If we have a multiplication exercise with an exponent, we can apply the exponent to each of the terms separately.

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Let's look at some examples

(2X)3 (2X)^3

We will notice that the exponent applies to the entire expression enclosed in parentheses and that between the 2 2 and the X X there is, in fact, a multiplication operation.

We can raise each of the terms of the expression to the exponent and we will obtain:

23ā‹…X3= 2^3\cdot X^3=

8ā‹…X3= 8\cdot X^3=

We will multiply the X X by its coefficient and we will get:

8X3 8X^3


Now let's move on to a slightly more complicated exercise.

(22ā‹…X3)2 (2^2\cdot X^3)^2

We see that the exponent 2 2 is outside the parentheses, therefore, it applies to the entire expression. The terms of the expression are multiplied, therefore, it is the power of a multiplication.

Well, now we can apply the exponent to each of the terms separately and we will not forget to maintain the multiplication between them.

We obtain:

(22)2ā‹…(x3)2 \left(2^2\right)^2\cdot\left(x^3\right)^2

We have obtained what is called: Power of a power

To be able to continue solving the exercise we will remember the following property:

Power of power

If we have a power of a power we must perform a multiplication of exponents, that is, multiply powers.

In symbols:

(an)k=anā‹…k (a^n)^k=a^{n\cdot k}

First we will multiply the exponent located outside the parentheses by the exponent of the base 2 2 and then, we will do it by the exponent of the base X X .

We will get:

24ā‹…X6 2^4\cdot X^6

16ā‹…X6 16\cdot X^6

Now we will multiply the X X by its coefficient and we will have:

16X6 16X^6


Do you know what the answer is?

Let's move on to see another example

which will demonstrate to us that no matter how many terms the exercise includes, as long as there is multiplication between them and as long as they are raised to a certain power located outside of the parentheses, in such a case we can apply the power to each of the terms separately and maintain the multiplication operation between them.

(22Xā‹…X5ā‹…X2ā‹…2ā‹…5)3 (2^2X\cdot X^5\cdot X^2\cdot2\cdot5)^3

Recommendation:

Before applying the power located outside of the parentheses to each of the terms separately, carefully observe the exercise.

If you look closely and are thoroughly familiar with the properties of powers or laws of exponents, you will immediately see that, you can first act inside the parentheses using the property of multiplication of powers with the same base to simplify the expression.

Let's remember that, when we have a multiplication of powers with the same base, we can add the exponents and obtain a single base with a single exponent.

If there is no exponent it means that the exponent is one and it is important that we remember to add it.

Upon observing the exercise we will discover that there are some equal bases: 2 2 and X X .

Since the operation between all the terms is multiplication we can add the relevant exponents and in this way we will arrive at:

(23ā‹…X8ā‹…5)3= (2^3\cdot X^8\cdot5)^3=


Now, with an already abbreviated expression between the parentheses, it will be easier and faster for us to apply the power located outside of the parentheses to each of the terms.

We will do it and obtain:

(23)3ā‹…(x8)3ā‹…(5)3= \left(2^3\right)^3\cdot\left(x^8\right)^3\cdot\left(5\right)^3=

29ā‹…X24ā‹…53= 2^9\cdot X^{24}\cdot5^3=

We can continue solving and we will arrive at:

512ā‹…X24ā‹…125= 512\cdot X^{24}\cdot125=

64,000ā‹…X24= 64,000\cdot X^{24}=

Let's multiply the X X by its coefficient and it will give us:

64,000X24= 64,000X^{24}=


Exercises with the Power of a Multiplication

(2Ɨ5)3= (2\times5)^3=

(1Ɨ2)3= (1\times2)^3=

(3Ɨ3)3= (3\times3)^3=

(2Ɨ2)2= (2\times2)^2=

(7Ɨ4)2= (7\times4)^2=


(32XƗX5ƗX3)3= \left(3^2X\times X^5\times X^3\right)^3=

(52XƗX2ƗX2)2= \left(5^2X\times X^2\times X^2\right)^2=

(82XƗX2ƗX25Ɨ3X)3= \left(8^2X\times X^2\times X^25\times3X\right)^3=

(24Ɨ5X2ƗX37Ɨ3X)3= \left(2^4\times5X^2\times X37\times3X\right)^3=

(24Ɨ5X2ƗXƗ8ƗX2)3= \left(2^4\times5X^2\times X\times8\times X^2\right)^3=


Check your understanding

Review Questions

How to solve a power of a multiplication?

To solve a power of a multiplication we must raise each of the factors to the indicated power and maintain the multiplication sign between the terms.


How to solve multiplication of powers with different bases?

The law of exponents indicates that when we have multiplication of powers with the same base, we must add the exponents, however, if we have different bases we cannot apply this law.


How to multiply powers with different bases and the same exponent?

If the base is different we cannot add the exponents, although in some exercises it will be possible to manipulate the expressions to equalize the bases and apply the law of exponents.


How to solve addition of powers with different bases?

There is no law for the addition of powers. It does not matter if they have the same base or not.


How are powers multiplied with the same exponent and different bases?

If the base is different, we cannot directly apply the law of exponents. Sometimes we may manipulate the bases to try to equalize them and apply the law.


Do you think you will be able to solve it?

Examples with solutions for Power of a Product

Exercise #1

Insert the corresponding expression:

(2Ɨ11)5= \left(2\times11\right)^5=

Video Solution

Step-by-Step Solution

To solve the expression (2Ɨ11)5 \left(2\times11\right)^5 , we can apply the rule for the power of a product, which states that(aƗb)n=anƗbn \left(a \times b\right)^n = a^n \times b^n .

In this case, our expression is (2Ɨ11)5 \left(2\times11\right)^5 , wherea=2 a = 2 and b=11 b = 11 , and n=5 n = 5 .

Applying the power of a product rule gives us:

  • an=25 a^n = 2^5

  • bn=115 b^n = 11^5

Therefore, (2Ɨ11)5=25Ɨ115 \left(2\times11\right)^5 = 2^5 \times 11^5 .

Answer

25Ɨ115 2^5\times11^5

Exercise #2

Insert the corresponding expression:

(9Ɨ7)4= \left(9\times7\right)^4=

Video Solution

Step-by-Step Solution

To solve the problem, we need to apply the exponent rule known as the Power of a Product, which states that if you have a product raised to an exponent, you can apply the exponent to each factor in the product individually.

The general form of this rule is:

(aƗb)n=anƗbn (a \times b)^n = a^n \times b^n

According to this formula, when we have the expression:

(9Ɨ7)4 (9 \times 7)^4

We apply the exponent 4 to each factor within the parentheses. This process results in:

  • Raising 9 to the power of 4: 94 9^4
  • Raising 7 to the power of 4: 74 7^4

Therefore, the expression simplifies to:

94Ɨ74 9^4 \times 7^4

This demonstrates the application of the Power of a Product rule successfully, showing detailed steps and the correct application of exponential laws.

Answer

94Ɨ74 9^4\times7^4

Exercise #3

Insert the corresponding expression:

(5Ɨ7)3= \left(5\times7\right)^3=

Video Solution

Step-by-Step Solution

The problem requires us to simplify the expression (5Ɨ7)3(5 \times 7)^3 using the power of a product rule.

The power of a product rule states that for any numbers a a and b b , and any integer n n , the expression (aƗb)n (a \times b)^n can be expanded to anƗbn a^n \times b^n .

Applying this rule to the given expression:

  • Identify the values of a a and b b as 5 5 and 7 7 , respectively.

  • Identify n n as 3 3 .

  • Substitute into the rule:
    (5Ɨ7)3=53Ɨ73(5 \times 7)^3 = 5^3 \times 7^3

The simplified expression is therefore: 53Ɨ735^3 \times 7^3.

Answer

53Ɨ73 5^3\times7^3

Exercise #4

Insert the corresponding expression:

(2Ɨ6)3= \left(2\times6\right)^3=

Video Solution

Step-by-Step Solution

We are given the expression (2Ɨ6)3 \left(2\times6\right)^3 and need to simplify it using the power of a product rule in exponents.

The power of a product rule states that when you have a product inside a power, you can apply the exponent to each factor in the product individually. In mathematical terms, the rule is expressed as:

  • (aā‹…b)n=anā‹…bn (a \cdot b)^n = a^n \cdot b^n

Applying this to our expression, we have:

(2Ɨ6)3=23Ɨ63 \left(2\times6\right)^3 = 2^3\times6^3

This means that each term inside the parentheses is raised to the power of 3 separately.

Therefore, the expression (2Ɨ6)3 \left(2\times6\right)^3 simplifies to 23Ɨ63 2^3\times6^3 as per the power of a product rule.

Answer

23Ɨ63 2^3\times6^3

Exercise #5

Insert the corresponding expression:

(4Ɨ2)2= \left(4\times2\right)^2=

Video Solution

Step-by-Step Solution

To solve the problem (4Ɨ2)2 \left(4\times2\right)^2, we need to apply the rule of exponents known as the "Power of a Product". This rule states that (ab)n=anƗbn (ab)^n = a^n \times b^n .

Here, a=4 a = 4 , b=2 b = 2 , and n=2 n = 2 .

  • Step 1: Apply the "Power of a Product" rule: (4Ɨ2)2=42Ɨ22 \left(4 \times 2\right)^2 = 4^2 \times 2^2 .

Thus, the expression (4Ɨ2)2 \left(4\times2\right)^2 is equivalent to 42Ɨ22 4^2 \times 2^2 .

Answer

42Ɨ22 4^2\times2^2

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