Triangle Area Coverage: Calculate Tiles Needed for 10m × 8m Pool

A hotel plans to build a special pool in its garden in the shape of a triangle.

The length of the pool 10 meters and its width 8 meters.

The pool is covered with tiles. The length of each tile is 2 meters and its width is 2 meters.

How many tiles do you need to cover the pool area?

Video Solution

Solution Steps

00:00 How many times does a square 2 m in length fit into triangle ABC?

00:03 First, we want to calculate the area of triangle ABC

00:06 Let's use the formula for calculating the area of a triangle

00:10 (Height(AC) x by Base(BC)) divided by 2

00:14 Substitute the numerical values into the formula and solve as follows

00:20 This is the area of triangle ABC

00:25 Our square tile according to the given data

00:28 We want to calculate its area

00:31 Let's use the formula for calculating the area of a square

00:34 Side(2) multiplied by Side(2)

00:38 This is the area of our tile

00:43 Divide the areas in order to find the ratio

00:47 Substitute the appropriate values into the formula and solve

00:51 Here is the solution

Step-by-Step Solution

To find out how many tiles are needed we will calculate the triangular area and the area of each tile and then divide.

$\frac{\text{A.triángulo}}{A.baldosa}$

The result is equal to the number of tiles needed.

In a triangle its length is equal to its height and its width is equal to the base of the triangle

$\text{A.triangulo=}\frac{10\cdot8}{2}=40$

Given=h=length= $10$ meters

Given=base=width= $8$ meters

Given that the length is $2$ meters

The width: $2$ meters

Tile area $2\cdot2=4$

$\frac{40}{4}=10$