Solve: (400÷(-5)-[-2(93-61)])÷4 | Order of Operations Challenge

Question

Solve the following equation:

400 ⁣:(5)[2(9361)]4= \frac{400\colon(-5)-\lbrack-2(93-61)\rbrack}{4}=

Video Solution

Solution Steps

00:00 Think
00:04 Always calculate parentheses first
00:40 Negative times negative always equals positive
00:46 Always solve multiplication and division before addition and subtraction
01:05 And this is the solution to the question

Step-by-Step Solution

We begin by addressing the numerator of the fraction.

First we solve the division exercise and the exercise within the parentheses:

400:(5)=80 400:(-5)=-80

(9361)=32 (93-61)=32

We obtain the following:

80(2×32)4= \frac{-80-(-2\times32)}{4}=

We then solve the parentheses in the numerator of the fraction:

80(64)4= \frac{-80-(-64)}{4}=

Let's remember that a negative times a negative equals a positive:

80+644= \frac{-80+64}{4}=

164=4 \frac{-16}{4}=-4

Answer

4 -4