Solve Complex Fraction: [(15×8+15)÷27+45]×8÷20÷(-5)

Question

Solve the following equation:

[(15×8+15) ⁣:27+45]×8 ⁣:205= \frac{\lbrack(15\times8+15)\colon27+45\rbrack\times8\colon20}{-5}=

Video Solution

Solution Steps

00:00 Solve
00:03 Always solve parentheses first, even within parentheses
00:07 Always solve multiplication and division before addition and subtraction
00:28 Let's continue calculating the parentheses
00:47 Let's continue solving according to proper order of operations, from left to right
01:07 Let's break down 50 into factors 10 and 5
01:20 Let's reduce what we can
01:26 Let's continue solving according to proper order of operations, from left to right
01:31 And this is the solution to the question

Step-by-Step Solution

Initially, we address the first parentheses in the numerator of the fraction:

(15×8+15)= (15\times8+15)=

According to the rules, we first must solve the multiplication exercise and then the addition:

120+15=135 120+15=135

We obtain the following exercise:

(135:27+45)×8:205= \frac{(135:27+45)\times8:20}{-5}=

We will again address the parentheses in the numerator of the fraction. First by solving the division and then addition exercise.

5+45=50 5+45=50

We are left with the following exercise:

50×8:205= \frac{50\times8:20}{-5}=

We divide 50 into a multiplication exercise:

5×10×8:205= \frac{5\times10\times8:20}{-5}=

We then simplify:

10×8:20= -10\times8:20=

Lastly we solve from left to right:

80:20=4 -80:20=-4

Answer

4-