Parentheses in advanced Order of Operations: Using negative numbers

We begin by addressing the numerator of the fraction.

First we solve the division exercise and the exercise within the parentheses:

$400:(-5)=-80$

$(93-61)=32$

We obtain the following:

$\frac{-80-(-2\times32)}{4}=$

We then solve the parentheses in the numerator of the fraction:

$\frac{-80-(-64)}{4}=$

Let's remember that a negative times a negative equals a positive:

$\frac{-80+64}{4}=$

$\frac{-16}{4}=-4$

Initially, we address the first parentheses in the numerator of the fraction:

$(15\times8+15)=$

According to the rules, we first must solve the multiplication exercise and then the addition:

$120+15=135$

We obtain the following exercise:

$\frac{(135:27+45)\times8:20}{-5}=$

We will again address the parentheses in the numerator of the fraction. First by solving the division and then addition exercise.

$5+45=50$

We are left with the following exercise:

$\frac{50\times8:20}{-5}=$

We divide 50 into a multiplication exercise:

$\frac{5\times10\times8:20}{-5}=$

We then simplify:

$-10\times8:20=$

Lastly we solve from left to right:

$-80:20=-4$

According to the order of arithmetic operations, we begin by solving the innermost parenthesis and the division exercise first:

$-9-(15-3-3+4)+4\times7=$

We then solve the parenthesis exercise from left to right:

$15-3-3+4=12-3+4=9+4=13$

We obtain the following exercise:

$-9-13+(4\times7)=$

We then solve the multiplication exercise and obtain:

$-9-13+28=$

Lastly we solve the exercise from left to right:

$-9-13=-22$

$-22+28=6$

We begin by solving the two parentheses in the numerator of the fraction:

$(32\times4+8)=128+8=136$

$(-27+35)=8$

We obtain the following exercise:

$\frac{136:8}{-2}=$

$\frac{17}{-2}=-8.5$