Simplify the Exponent Equation: (2^-4 * (1/2)^8 * 2^10) / 2^3

Solve the following problem:

24(12)821023=? \frac{2^{-4}\cdot(\frac{1}{2})^8\cdot2^{10}}{2^3}=\text{?}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following problem
00:05 In order to remove the negative exponents
00:08 We flip the numerator and the denominator and the exponent becomes positive
00:17 We will apply this formula to our exercise
00:45 When multiplying powers with equal bases
00:49 the exponent of the result equals the sum of the exponents
00:53 We will apply this formula to our exercise, we'll add the exponents
01:12 When dividing powers with equal bases
01:18 the exponent of the result equals the difference of the exponents
01:24 We will apply this formula to our exercise, we'll subtract the exponents
01:31 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following problem:

24(12)821023=? \frac{2^{-4}\cdot(\frac{1}{2})^8\cdot2^{10}}{2^3}=\text{?}

2

Step-by-step solution

In order to solve this problem, we'll follow these steps:

  • Step 1: Simplify each component using exponent rules

  • Step 2: Apply multiplication and division of powers

  • Step 3: Simplify the combined expression

Now, let's work through each step:

Step 1: Simplify (12)8(\frac{1}{2})^8. Using the power of a fraction rule, we have:

(12)8=1828=128=28 \left(\frac{1}{2}\right)^8 = \frac{1^8}{2^8} = \frac{1}{2^8} = 2^{-8}

Step 2: Substitute back into the original expression:

242821023 \frac{2^{-4} \cdot 2^{-8} \cdot 2^{10}}{2^3}

Combine the terms in the numerator using the product of powers rule:

2428210=24+(8)+10=22 2^{-4} \cdot 2^{-8} \cdot 2^{10} = 2^{-4 + (-8) + 10} = 2^{-2}

Now the expression becomes:

2223 \frac{2^{-2}}{2^3}

Apply the division of powers rule:

2223=223=25 \frac{2^{-2}}{2^3} = 2^{-2 - 3} = 2^{-5}

Thus, the solution to the problem is 25 2^{-5} .

3

Final Answer

25 2^{-5}

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\( 112^0=\text{?} \)

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