Simplify: 10^(-3) × 10^4 - (7×9×5)^3 + (4^2)^5 Expression Challenge

Exponent Rules with Mixed Operations

Simplify the following expression:

103104(795)3+(42)5= 10^{-3}\cdot10^4-(7\cdot9\cdot5)^3+(4^2)^5=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:14 Let's simplify this expression.
00:17 When multiplying powers with the same base, add the exponents.
00:22 So, the new power is the sum of the old powers.
00:26 We'll use this idea in our practice example.
00:33 Now, let's find the product.
00:37 If you have a power of a power, multiply the exponents.
00:43 We'll apply this rule in our example.
00:50 Let's calculate these powers.
00:53 And finally, compute the product.
01:01 That's how we solve this problem!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Simplify the following expression:

103104(795)3+(42)5= 10^{-3}\cdot10^4-(7\cdot9\cdot5)^3+(4^2)^5=

2

Step-by-step solution

In solving the problem, we use two laws of exponents, which we will mention:

a. The law of exponents for multiplying powers with the same bases:

aman=am+n a^m\cdot a^n=a^{m+n} b. The law of exponents for a power of a power:

(am)n=amn (a^m)^n=a^{m\cdot n} We will apply these two laws of exponents in solving the problem in two steps:

Let's start by applying the law of exponents mentioned in a' to the first expression on the left side of the problem:

103104=103+4=101=10 10^{-3}\cdot10^4=10^{-3+4}=10^1=10 When in the first step we applied the law of exponents mentioned in a' and in the following steps we simplified the expression that was obtained,

We continue to the next step and apply the law of exponents mentioned in b' and handle the third expression on the left side of the problem:

(42)5=425=410 (4^2)^5=4^{2\cdot5}=4^{10} When in the first step we applied the law of exponents mentioned in b' and in the following steps we simplified the expression that was obtained,

We combine the two steps detailed above to the complete problem solution:

103104(795)3+(42)5=10(795)3+410 10^{-3}\cdot10^4-(7\cdot9\cdot5)^3+(4^2)^5= 10-(7\cdot9\cdot5)^3+4^{10} In the next step we calculate the result of multiplying the numbers inside the parentheses in the second expression on the left:

10(795)3+410=103153+410 10-(7\cdot9\cdot5)^3+4^{10}= 10-315^3+4^{10} Therefore, the correct answer is answer b'.

3

Final Answer

1013153+410 10^1-315^3+4^{10}

Key Points to Remember

Essential concepts to master this topic
  • Exponent Laws: Use aman=am+n a^m \cdot a^n = a^{m+n} and (am)n=amn (a^m)^n = a^{m \cdot n}
  • Step-by-Step: Simplify 103104=101 10^{-3} \cdot 10^4 = 10^1 and (42)5=410 (4^2)^5 = 4^{10} first
  • Check: Verify each exponent calculation: 103+4=101 10^{-3+4} = 10^1 and 425=410 4^{2 \cdot 5} = 4^{10}

Common Mistakes

Avoid these frequent errors
  • Adding exponents when bases are different
    Don't try to combine 101 10^1 and 410 4^{10} using exponent rules = invalid operation! Exponent laws only work with the same base. Always keep different bases separate and only simplify within each base.

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why can't I just multiply the exponents in 103104 10^{-3} \cdot 10^4 ?

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You add exponents when multiplying powers with the same base, not multiply them! The rule is aman=am+n a^m \cdot a^n = a^{m+n} , so 103104=103+4=101 10^{-3} \cdot 10^4 = 10^{-3+4} = 10^1 .

What's the difference between (42)5 (4^2)^5 and 4245 4^2 \cdot 4^5 ?

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For (42)5 (4^2)^5 , you multiply the exponents: 42×5=410 4^{2 \times 5} = 4^{10} . For 4245 4^2 \cdot 4^5 , you add the exponents: 42+5=47 4^{2+5} = 4^7 . Different operations!

Do I need to calculate 3153 315^3 and 410 4^{10} ?

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No! The question asks you to simplify, not evaluate. Leave your answer as 1013153+410 10^1 - 315^3 + 4^{10} . Computing those large numbers would be unnecessary work.

Why is 7×9×5=315 7 \times 9 \times 5 = 315 ?

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Calculate step by step: 7×9=63 7 \times 9 = 63 , then 63×5=315 63 \times 5 = 315 . You can also rearrange: 7×5×9=35×9=315 7 \times 5 \times 9 = 35 \times 9 = 315 .

Can I combine 101 10^1 with the other terms?

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No, you cannot use exponent rules to combine terms with different bases like 10 and 4. The final simplified form is 1013153+410 10^1 - 315^3 + 4^{10} , which cannot be simplified further.

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