Algebraic Method

Algebraic Method is a general term for various tools and techniques that will help us solve more complex exercises in the future. It is mostly concern about using algebraic operations to isolate variables and solve equations. This approach is fundamental for solving equations in various mathematical contexts.

Distributive Property

This property helps us to clear parentheses and assists us with more complex calculations. Let's remember how it works. Generally, we will write it like this:

Z×(X+Y)=ZX+ZY Z\times(X+Y)=ZX+ZY

Z×(XY)=ZXZY Z\times(X-Y)=ZX-ZY

Extended Distributive Property

The extended distributive property is very similar to the distributive property, but it allows us to solve exercises with expressions in parentheses that are multiplied by other expressions in parentheses.
It looks like this:

(a+b)×(c+d)=ac+ad+bc+bd (a+b)\times(c+d)=ac+ad+bc+bd

Factoring

The factoring method is very important. It will help us move from an expression with several terms to one that includes only one by taking out the common factor from within the parentheses.
For example:
2A+4B2A + 4B

This expression consists of two terms. We can factor it by reducin by the greatest common factor. In this case, it's the 2 2 .
We will write it as follows:

2A+4B=2×(A+2B) 2A+4B=2\times(A+2B)

Algebraic Method

In this article, we’ll explain each of these topics in detail, But each of these topics will be explained even more in detail in their respective articles.

Practice Algebraic Technique

Examples with solutions for Algebraic Technique

Exercise #1

Break down the expression into basic terms:

2x2 2x^2

Step-by-Step Solution

The expression 2x2 2x^2 can be factored and broken down into the following basic terms:

  • The coefficient 2 2 remains as it is since it is already a basic term.
  • The term x2 x^2 can be broken down into xx x \cdot x .
  • Therefore, the entire expression can be written as 2xx 2 \cdot x \cdot x .

This breakdown helps in understanding the multiplicative nature of the expression.

Among the provided choices, the correct one that matches this breakdown is choice 2: 2xx 2\cdot x\cdot x .

Answer

2xx 2\cdot x\cdot x

Exercise #2

Break down the expression into basic terms:

6x 6x

Step-by-Step Solution

To solve this problem, we'll clearly delineate the expression 6x 6x as follows:

  • The number 6 is the coefficient.
  • The letter x x is the variable.
  • These two components are connected by multiplication, represented as 6x 6 \cdot x .

Thus, the expression 6x 6x is equivalent to 6x 6 \cdot x , where 6 is multiplied by x x .

Examining the choice options:

  • Choice 1: 6x 6\cdot x is correct because it represents the expression as a product of the coefficient and the variable.
  • Choice 2: xxxxxx x \cdot x \cdot x \cdot x \cdot x \cdot x represents a repeated multiplication of x x , not applicable here.
  • Choice 3: 6x \frac{6}{x} represents division, not the required approach.
  • Choice 4: Incorrect, as 6x 6x can indeed be expressed as 6x 6 \cdot x .

Therefore, the best breakdown of the expression is 6x 6 \cdot x , matching choice 1.

Answer

6x 6\cdot x

Exercise #3

Break down the expression into basic terms:

3a3 3a^3

Step-by-Step Solution

To break down the expression 3a3 3a^3 , we recognize that a3 a^3 means a×a×a a \times a \times a . Therefore, 3a3 3a^3 can be decomposed as 3aaa 3 \cdot a\cdot a\cdot a .

Answer

3aaa 3 \cdot a\cdot a\cdot a

Exercise #4

Break down the expression into basic terms:

3x2+2x 3x^2 + 2x

Step-by-Step Solution

The expression can be broken down as follows:

3x2+2x 3x^2 + 2x

Breaking down each term we have:

- 3x2 3x^2 becomes 3xx 3\cdot x\cdot x

- 2x 2x remains 2x 2 \cdot x

Finally, the expression is:

3xx+2x 3\cdot x\cdot x+2\cdot x

Answer

3xx+2x 3\cdot x\cdot x+2\cdot x

Exercise #5

Break down the expression into basic terms:

3y2+6 3y^2 + 6

Step-by-Step Solution

To break down the expression 3y2+6 3y^2 + 6 , we need to recognize common factors or express terms in basic forms.

The term 3y2 3y^2 can be rewritten by breaking down the operations: 3yy 3\cdot y\cdot y .

The constant 6 6 remains as it is in its basic term.

Thus, the broken down expression becomes 3yy+6 3\cdot y\cdot y + 6 .

Answer

3yy+6 3\cdot y\cdot y+6

Exercise #6

Break down the expression into basic terms:

3y3 3y^3

Step-by-Step Solution

To break down the expression 3y3 3y^3 into its basic terms, we understand the components of the expression:

3is a constant multiplier 3 \, \text{is a constant multiplier}

y3 y^3 can be rewritten as yyy y \cdot y \cdot y

Thus, 3y3 3y^3 can be decomposed into 3yyy 3 \cdot y \cdot y \cdot y .

Answer

3yyy 3\cdot y\cdot y \cdot y

Exercise #7

Break down the expression into basic terms:

4a2 4a^2

Step-by-Step Solution

To break down the expression 4a2 4a^2 into basic terms, we need to look at each factor:

4is a constant multiplier 4 \, \text{is a constant multiplier}

a2 a^2 means aa a \cdot a

Hence, 4a2 4a^2 is equivalent to 4aa 4 \cdot a \cdot a .

Answer

4aa 4\cdot a\cdot a

Exercise #8

Break down the expression into basic terms:

4x2+3x 4x^2 + 3x

Step-by-Step Solution

The expression can be broken down as follows:

4x2+3x 4x^2 + 3x

1. Notice that both terms contain a common factor of x x .

2. Factor out the common x x :

x(4x+3) x(4x + 3) .

3. Thus, breaking down each term we have:

- 4x2 4x^2 becomes 4xx 4x \cdot x after factoring out x x .

- 3x 3x remains 3x 3 \cdot x after factoring out x x .

Finally, the expression is:

4xx+3x 4x\cdot x + 3\cdot x

Answer

4xx+3x 4\cdot x\cdot x+3\cdot x

Exercise #9

Break down the expression into basic terms:

4x2+6x 4x^2 + 6x

Step-by-Step Solution

To break down the expression4x2+6x 4x^2 + 6x into its basic terms, we need to look for a common factor in both terms.

The first term is 4x2 4x^2 , which can be rewritten as 4xx 4\cdot x\cdot x .

The second term is6x 6x , which can be rewritten as 23x 2\cdot 3\cdot x .

The common factor between the terms is x x .

Thus, the expression can be broken down into 4x2+6x 4\cdot x^2 + 6\cdot x , and further rewritten with common factors as 4xx+6x 4\cdot x\cdot x + 6\cdot x .

Answer

4xx+6x 4\cdot x\cdot x+6\cdot x

Exercise #10

Break down the expression into basic terms:

5m 5m

Step-by-Step Solution

To break down the expression 5m 5m , we recognize it as the product of 5 5 and m m :

5m=5m 5m = 5 \cdot m

This expression can be seen as a multiplication of the constant 5 5 and the variable m m .

Answer

5m 5\cdot m

Exercise #11

Break down the expression into basic terms:

5x2+10 5x^2 + 10

Step-by-Step Solution

To break down the expression 5x2+10 5x^2 + 10 , identify the common factors.

The first term is 5x2 5x^2 , which can be rewritten as 5xx 5\cdot x\cdot x .

The second term is 10 10 , which can be rewritten as 52 5\cdot 2 .

Notice that both terms share a common factor of 5 5 .

This allows the expression to be broken down to 5(x2)+10 5(x^2) + 10 , which translates to 5xx+10 5\cdot x\cdot x + 10 using common terms.

Answer

5xx+10 5\cdot x\cdot x+10

Exercise #12

Break down the expression into basic terms:

5x2 5x^2

Step-by-Step Solution

To break down the expression 5x2 5x^2 into its basic terms, we identify each component in the expression:

5is a constant multiplier 5 \, \text{is a constant multiplier}

x2 x^2 means xx x \cdot x

Therefore, 5x2 5x^2 can be rewritten as 5xx 5 \cdot x \cdot x .

Answer

5xx 5\cdot x\cdot x

Exercise #13

Break down the expression into basic terms:

6b2 6b^2

Step-by-Step Solution

To break down the expression 6b2 6b^2 into its fundamental parts, we analyze each element:

6is a constant multiplier 6 \, \text{is a constant multiplier}

b2 b^2 represents bb b \cdot b

Therefore, 6b2 6b^2 is decomposed as 6bb 6 \cdot b \cdot b .

Answer

6bb 6\cdot b\cdot b

Exercise #14

Break down the expression into basic terms:

8y2 8y^2

Step-by-Step Solution

To break down the expression 8y2 8y^2 , we identify the basic components. The expression y2 y^2 is a shorthand fory×y y \times y . Therefore, 8y2 8y^2 can be decomposed as 8yy 8 \cdot y \cdot y .

Answer

8yy 8\cdot y\cdot y

Exercise #15

Break down the expression into basic terms:

8y 8y

Step-by-Step Solution

To break down the expression 8y 8y , we can see it as the multiplication of 8 8 and y y :

8y=8y 8y = 8 \cdot y

This shows the expression as a product of two factors, 8 8 and y y .

Answer

8y 8\cdot y