Factorization - Common Factor: Solving the problem

$2x^{90}-4x^{89}=0$

The equation in the problem is:

$2x^{90}-4x^{89}=0$Let's pay attention to the left side:

The expression can be broken down into factors by taking out a common factor, The greatest common factor for the numbers and letters in this case is $2x^{89}$since the power of 89 is the lowest power in the equation and therefore included both in the term where the power is 90 and in the term where the power is 89.

Any power higher than that is not included in the term where the power of 89 is the lowest, and therefore it is the term with the highest power that can be taken out of all the terms in the expression as a common factor for the variables.

For the numbers, note that the number 4 is a multiple of the number 2, so the number 2 is the greatest common factor for the numbers for the two terms in the expression.

Continuing and performing the factorization:

$2x^{90}-4x^{89}=0 \\ \downarrow\\ 2x^{89}(x-2)=0$Let's continue and remember that on the left side of the equation that was obtained in the last step there is an algebraic expression and on the right side the number is 0.

Since the only way to get the result 0 from a product is for at least one of the factors in the product on the left side to be equal to zero,

Meaning:

$2x^{89}=0 \hspace{8pt}\text{/}:2\\ x^{89}=0 \hspace{8pt}\text{/}\sqrt[89]{\hspace{6pt}}\\ \boxed{x=0}$

Or:

$x-2=0 \\ \boxed{x=2}$

In summary:

$2x^{90}-4x^{89}=0 \\ \downarrow\\ 2x^{89}(x-2)=0 \\ \downarrow\\ 2x^{89}=0 \rightarrow\boxed{ x=0}\\ x-2=0\rightarrow \boxed{x=2}\\ \downarrow\\ \boxed{x=0,2}$And therefore the correct answer is answer a.

$x=0,2$

$4x^4-12x^3=0$

Solve the equation above for x.

$x=0,3$

$x^6-4x^4=0$

$x=0,x=\pm2$

$7x^3-x^2=0$

$x=0,x=\frac{1}{7}$

$x^7-x^6=0$

$x=0,1$

$x^4+x^2=0$

$x=0$

$x^6+x^5=0$

$x=-1,x=0$

$7x^{10}-14x^9=0$

$x=2,x=0$

$x^5-4x^4=0$

$x=4,x=0$

$3x^2+9x=0$

$x=0,x=-3$

Solve for x:

$7x^5-14x^4=0$

$x=0,2$

$8x-x^4=0$

$x=0,2$

$12x^4-3x^3=0$

$x=0,\frac{1}{4}$

$x^7-5x^6=0$

$x=0,5$

$x^{100}-9x^{99}=0$

$x=0,9$

$7x^8-21x^7=0$

$x=0,3$

$x^{14}-x^7=0$

Answers a + b

Solve for x:

$28x^8-7x^7=0$

Answers a and b are correct.

$x^2-x=0$

$x=0,1$

$15x^4-30x^3=0$

$x=0,2$