Extended Distributive Property Practice Problems & Worksheets

Master the extended distributive property with step-by-step practice problems. Learn to multiply two binomials, simplify expressions, and solve real-world applications.

📚What You'll Master in This Practice Session
  • Multiply two binomials using the extended distributive property method
  • Apply FOIL technique to expressions like (x+3)(x-2) with confidence
  • Combine like terms after distributing to simplify final answers
  • Solve real-world area problems using binomial multiplication
  • Handle negative signs correctly when multiplying binomial expressions
  • Work with variables and coefficients in extended distributive problems

Understanding Extended Distributive Property

Complete explanation with examples

The extended distributive property allows us to solve exercises with two sets of parentheses that are multiplied by eachother.

For example: (a+1)×(b+2) (a+1)\times(b+2)

To find the solution, we will go through the following steps:

  • Step 1: Multiply the first term in the first parentheses by each of the terms in the second parentheses.
  • Step 2: Multiply the second term in the first parentheses by each of the terms in the second parentheses.
  • Step 3: Associate like terms.

ab+2a+b+2 ab+2a+b+2

The Extended Distributive Property

Detailed explanation

Practice Extended Distributive Property

Test your knowledge with 29 quizzes

It is possible to use the distributive property to simplify the expression below?

What is its simplified form?

\( (ab)(c d) \)

\( \)

Examples with solutions for Extended Distributive Property

Step-by-step solutions included
Exercise #1

Expand the following expression:

(x+4)(x+3)= (x+4)(x+3)=

Step-by-Step Solution

Let's simplify the given expression by opening the parentheses using the extended distribution law:

(a+b)(c+d)=ac+ad+bc+bd (\textcolor{red}{a}+\textcolor{blue}{b})(c+d)=\textcolor{red}{a}c+\textcolor{red}{a}d+\textcolor{blue}{b}c+\textcolor{blue}{b}d

Note that in the formula template for the above distribution law, we take by default that the operation between the terms inside the parentheses is addition. Therefore we won't forget of course that the sign preceding the term is an inseparable part of it. We will also apply the rules of sign multiplication and thus we can present any expression in parentheses. We'll open the parentheses using the above formula, first as an expression where an addition operation exists between all terms. In this expression it's clear that all terms have a plus sign prefix. Therefore we'll proceed directly to opening the parentheses,

Let's begin:

(x+4)(x+3)xâ‹…x+xâ‹…3+4â‹…x+4â‹…3x2+3x+4x+12 (\textcolor{red}{x}+\textcolor{blue}{4})(x+3)\\ \textcolor{red}{x}\cdot x+\textcolor{red}{x}\cdot3+\textcolor{blue}{4}\cdot x +\textcolor{blue}{4}\cdot3\\ x^2+3x+4x+12

In calculating the above multiplications, we used the multiplication table and the laws of exponents for multiplication between terms with identical bases:

amâ‹…an=am+n a^m\cdot a^n=a^{m+n}

In the next step we'll combine like terms, which we define as terms where the variable (or variables each separately), in this case x, have identical exponents .(In the absence of one of the variables from the expression, we'll consider its exponent as zero power given that raising any number to the power of zero yields 1) We'll apply the commutative property of addition, furthermore we'll arrange (if needed) the expression from highest to lowest power from left to right (we'll treat the free number as having zero power):
x2+3x+4x+12x2+7x+12 \textcolor{purple}{x^2}\textcolor{green}{+3x}\textcolor{green}{+4x}+12\\ \textcolor{purple}{x^2}\textcolor{green}{+7x}+12 In the combining of like terms performed above, we highlighted the different terms using colors, and as emphasized before, we made sure that the sign preceding the term is an inseparable part of it,

Thus the correct answer is C.

Answer:

x2+7x+12 x^2+7x+12

Video Solution
Exercise #2

(a+b)(c+d)= (a+b)(c+d)= ?

Step-by-Step Solution

Let's simplify the expression by opening the parentheses using the distributive property:

(a+b)(c+d)=ac+ad+bc+bd (\textcolor{red}{a}+\textcolor{blue}{b})(c+d)=\textcolor{red}{a}c+\textcolor{red}{a}d+\textcolor{blue}{b}c+\textcolor{blue}{b}d

Therefore, the correct answer is (a).

Answer:

ac + ad+bc+bd \text{ac + ad}+bc+bd

Video Solution
Exercise #3

(2x+y)(x+3)= (2x+y)(x+3)=

Step-by-Step Solution

To solve this problem, we'll apply the FOIL method for multiplying binomials:

  • First: Multiply the first terms in each binomial: (2x)(x)=2x2(2x)(x) = 2x^2.
  • Outer: Multiply the outer terms in the product: (2x)(3)=6x(2x)(3) = 6x.
  • Inner: Multiply the inner terms: (y)(x)=xy(y)(x) = xy.
  • Last: Multiply the last terms: (y)(3)=3y(y)(3) = 3y.

Next, we combine these results to form the expanded expression:

2x2+6x+xy+3y 2x^2 + 6x + xy + 3y .

Since terms 6x6x and xyxy are not like terms, they cannot be combined, resulting in the final expression:

2x2+xy+6x+3y 2x^2 + xy + 6x + 3y .

Upon reviewing the multiple-choice options, the correct answer is the expanded expression, choice 4: 2x2+xy+6x+3y 2x^2 + xy + 6x + 3y .

Answer:

2x2+xy+6x+3y 2x^2+xy+6x+3y

Video Solution
Exercise #4

(a+4)(c+3)= (a+4)(c+3)=

Step-by-Step Solution

When we encounter a multiplication exercise of this type, we know that we must use the distributive property.

Step 1: Multiply the first factor of the first parentheses by each of the factors of the second parentheses.

Step 2: Multiply the second factor of the first parentheses by each of the factors of the second parentheses.

Step 3: Group like terms.

a * (c+3) =

a*c + a*3

4 * (c+3) =

4*c + 4*3

ac+3a+4c+12

There are no like terms to simplify here, so this is the solution!

Answer:

ac+3a+4c+12 ac+3a+4c+12

Video Solution
Exercise #5

(x+13)(y+4)= (x+13)(y+4)=

Step-by-Step Solution

To solve this problem, we'll perform a step-by-step expansion of the expression (x+13)(y+4)(x+13)(y+4) using the distributive property:

  • Step 1: Multiply the first terms (xâ‹…y)=xy (x \cdot y) = xy .
  • Step 2: Multiply the outer terms (xâ‹…4)=4x (x \cdot 4) = 4x .
  • Step 3: Multiply the inner terms (13â‹…y)=13y (13 \cdot y) = 13y .
  • Step 4: Multiply the last terms (13â‹…4)=52 (13 \cdot 4) = 52 .

After completing these steps, combine the results:

xy+4x+13y+52 xy + 4x + 13y + 52

This is the final expanded form of the expression. By comparing with the given choices, the correct answer is:

xy+4x+13y+52 xy + 4x + 13y + 52

Therefore, the correct choice is option 3.

Answer:

xy+4x+13y+52 xy+4x+13y+52

Video Solution

Frequently Asked Questions

What is the extended distributive property formula?

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The extended distributive property formula is (a+b)(c+d) = ac + ad + bc + bd. You multiply each term in the first parentheses by each term in the second parentheses, then combine like terms if possible.

How do you multiply two binomials step by step?

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Follow these steps: 1) Multiply the first term in the first binomial by each term in the second binomial, 2) Multiply the second term in the first binomial by each term in the second binomial, 3) Combine like terms to simplify your final answer.

What's the difference between basic and extended distributive property?

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Basic distributive property involves one term multiplied by a binomial: a(b+c) = ab + ac. Extended distributive property involves multiplying two binomials: (a+b)(c+d) = ac + ad + bc + bd.

How do you handle negative signs in extended distributive property?

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Treat negative signs as part of the terms. Remember that multiplying two negatives gives a positive result, while multiplying a positive and negative gives a negative result. For example: (-3)(-5) = +15, but (-3)(+5) = -15.

What are common mistakes when using extended distributive property?

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Common mistakes include: • Forgetting to multiply all four combinations of terms • Making sign errors with negative numbers • Failing to combine like terms in the final answer • Rushing through the multiplication without checking work

When do you use the extended distributive property in real life?

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The extended distributive property is used in calculating areas of rectangles with variable dimensions, solving quadratic equations, and simplifying algebraic expressions in physics and engineering problems.

Is FOIL the same as extended distributive property?

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Yes, FOIL (First, Outer, Inner, Last) is a memory device for the extended distributive property when multiplying two binomials. Both methods produce the same result by ensuring you multiply all combinations of terms.

How do you check if your extended distributive property answer is correct?

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You can check by: 1) Substituting simple numbers for variables and verifying both sides equal the same value, 2) Expanding your answer back to factored form, or 3) Using online algebra calculators to verify your work.

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