Factorization

The factorization we do by extracting the common factor is our way of modifying the way the exercise is written, that is, from an expression with addition to an expression with multiplication.

For example, the expression
2A+4B2A + 4B
is composed of two terms and a plus sign. We can factor it by excluding the largest common term.
In this case it is 2 2 .

We will write it as follows:
​​​​​​​2A+4B=2×(A+2B)​​​​​​​2A + 4B = 2\times (A + 2B)

Since both terms ( A A and B B ) were multiplied by 2 2 we could "extract" it. The remaining expression is written in parentheses and the common factor (the 2 2 ) is kept out.
In this way we went from having two terms in an addition operation to having a multiplication. This procedure is called factorization.

A - Factorization

You can also apply the distributive property to do a reverse process as needed.
In certain cases we will prefer to have a multiplication and in others an addition.

Practice Factorization: Common factor extraction

Examples with solutions for Factorization: Common factor extraction

Exercise #1

Break down the expression into basic terms:

2x2 2x^2

Step-by-Step Solution

The expression 2x2 2x^2 can be factored and broken down into the following basic terms:

  • The coefficient 2 2 remains as it is since it is already a basic term.
  • The term x2 x^2 can be broken down into xx x \cdot x .
  • Therefore, the entire expression can be written as 2xx 2 \cdot x \cdot x .

This breakdown helps in understanding the multiplicative nature of the expression.

Among the provided choices, the correct one that matches this breakdown is choice 2: 2xx 2\cdot x\cdot x .

Answer

2xx 2\cdot x\cdot x

Exercise #2

Break down the expression into basic terms:

6x 6x

Step-by-Step Solution

To solve this problem, we'll clearly delineate the expression 6x 6x as follows:

  • The number 6 is the coefficient.
  • The letter x x is the variable.
  • These two components are connected by multiplication, represented as 6x 6 \cdot x .

Thus, the expression 6x 6x is equivalent to 6x 6 \cdot x , where 6 is multiplied by x x .

Examining the choice options:

  • Choice 1: 6x 6\cdot x is correct because it represents the expression as a product of the coefficient and the variable.
  • Choice 2: xxxxxx x \cdot x \cdot x \cdot x \cdot x \cdot x represents a repeated multiplication of x x , not applicable here.
  • Choice 3: 6x \frac{6}{x} represents division, not the required approach.
  • Choice 4: Incorrect, as 6x 6x can indeed be expressed as 6x 6 \cdot x .

Therefore, the best breakdown of the expression is 6x 6 \cdot x , matching choice 1.

Answer

6x 6\cdot x

Exercise #3

Break down the expression into basic terms:

8y2 8y^2

Step-by-Step Solution

To break down the expression 8y2 8y^2 , we identify the basic components. The expression y2 y^2 is a shorthand fory×y y \times y . Therefore, 8y2 8y^2 can be decomposed as 8yy 8 \cdot y \cdot y .

Answer

8yy 8\cdot y\cdot y

Exercise #4

Break down the expression into basic terms:

3a3 3a^3

Step-by-Step Solution

To break down the expression 3a3 3a^3 , we recognize that a3 a^3 means a×a×a a \times a \times a . Therefore, 3a3 3a^3 can be decomposed as 3aaa 3 \cdot a\cdot a\cdot a .

Answer

3aaa 3 \cdot a\cdot a\cdot a

Exercise #5

Break down the expression into basic terms:

8y 8y

Step-by-Step Solution

To break down the expression 8y 8y , we can see it as the multiplication of 8 8 and y y :

8y=8y 8y = 8 \cdot y

This shows the expression as a product of two factors, 8 8 and y y .

Answer

8y 8\cdot y

Exercise #6

Break down the expression into basic terms:

5m 5m

Step-by-Step Solution

To break down the expression 5m 5m , we recognize it as the product of 5 5 and m m :

5m=5m 5m = 5 \cdot m

This expression can be seen as a multiplication of the constant 5 5 and the variable m m .

Answer

5m 5\cdot m

Exercise #7

Break down the expression into basic terms:

5x2 5x^2

Step-by-Step Solution

To break down the expression 5x2 5x^2 into its basic terms, we identify each component in the expression:

5is a constant multiplier 5 \, \text{is a constant multiplier}

x2 x^2 means xx x \cdot x

Therefore, 5x2 5x^2 can be rewritten as 5xx 5 \cdot x \cdot x .

Answer

5xx 5\cdot x\cdot x

Exercise #8

Break down the expression into basic terms:

3y3 3y^3

Step-by-Step Solution

To break down the expression 3y3 3y^3 into its basic terms, we understand the components of the expression:

3is a constant multiplier 3 \, \text{is a constant multiplier}

y3 y^3 can be rewritten as yyy y \cdot y \cdot y

Thus, 3y3 3y^3 can be decomposed into 3yyy 3 \cdot y \cdot y \cdot y .

Answer

3yyy 3\cdot y\cdot y \cdot y

Exercise #9

Break down the expression into basic terms:

4a2 4a^2

Step-by-Step Solution

To break down the expression 4a2 4a^2 into basic terms, we need to look at each factor:

4is a constant multiplier 4 \, \text{is a constant multiplier}

a2 a^2 means aa a \cdot a

Hence, 4a2 4a^2 is equivalent to 4aa 4 \cdot a \cdot a .

Answer

4aa 4\cdot a\cdot a

Exercise #10

Break down the expression into basic terms:

6b2 6b^2

Step-by-Step Solution

To break down the expression 6b2 6b^2 into its fundamental parts, we analyze each element:

6is a constant multiplier 6 \, \text{is a constant multiplier}

b2 b^2 represents bb b \cdot b

Therefore, 6b2 6b^2 is decomposed as 6bb 6 \cdot b \cdot b .

Answer

6bb 6\cdot b\cdot b

Exercise #11

Break down the expression into basic terms:

3x2+2x 3x^2 + 2x

Step-by-Step Solution

The expression can be broken down as follows:

3x2+2x 3x^2 + 2x

Breaking down each term we have:

- 3x2 3x^2 becomes 3xx 3\cdot x\cdot x

- 2x 2x remains 2x 2 \cdot x

Finally, the expression is:

3xx+2x 3\cdot x\cdot x+2\cdot x

Answer

3xx+2x 3\cdot x\cdot x+2\cdot x

Exercise #12

Break down the expression into basic terms:

4x2+3x 4x^2 + 3x

Step-by-Step Solution

The expression can be broken down as follows:

4x2+3x 4x^2 + 3x

1. Notice that both terms contain a common factor of x x .

2. Factor out the common x x :

x(4x+3) x(4x + 3) .

3. Thus, breaking down each term we have:

- 4x2 4x^2 becomes 4xx 4x \cdot x after factoring out x x .

- 3x 3x remains 3x 3 \cdot x after factoring out x x .

Finally, the expression is:

4xx+3x 4x\cdot x + 3\cdot x

Answer

4xx+3x 4\cdot x\cdot x+3\cdot x

Exercise #13

Simplify the expression:

5x3+3x2 5x^3 + 3x^2

Step-by-Step Solution

To simplify the expression 5x3+3x2 5x^3 + 3x^2 , we can break it down into basic terms:

The term 5x3 5x^3 can be written as 5xxx 5 \cdot x \cdot x \cdot x .

The term3x2 3x^2 can be written as 3xx 3 \cdot x \cdot x .

Thus, the expression simplifies to5xxx+3xx 5 \cdot x \cdot x \cdot x + 3 \cdot x \cdot x .

Answer

5xxx+3xx 5\cdot x\cdot x\cdot x + 3\cdot x\cdot x

Exercise #14

Rewrite using basic components:

6z2+z 6z^2 + z

Step-by-Step Solution

To rewrite the expression 6z2+z 6z^2 + z , break it down into basic components:

The term 6z2 6z^2 can be expressed as 6zz 6 \cdot z \cdot z .

The term z z is 1z 1 \cdot z .

Thus, rewriting gives 6zz+1z 6 \cdot z \cdot z + 1 \cdot z .

Answer

6zz+1z 6\cdot z\cdot z + 1\cdot z

Exercise #15

Rewrite using basic components:

8x24x 8x^2 - 4x

Step-by-Step Solution

To rewrite the expression 8x24x 8x^2 - 4x using its basic components, we'll follow these steps:

  • Step 1: Identify the greatest common factor of the terms.
  • Step 2: Factor each term using the greatest common factor.

Let's go through each step:

Step 1: Recognize that both terms 8x2 8x^2 and 4x 4x contain x x as a common factor.
Moreover, the numerical coefficients 8 and 4 have a common factor of 4.

Step 2: Factor the expression:
- 8x2 8x^2 can be expressed as 8xx 8 \cdot x \cdot x .
- 4x 4x can be written as 4x 4 \cdot x .

Bringing them together, we can rewrite the expression:

8x24x=8xx4x 8x^2 - 4x = 8 \cdot x \cdot x - 4 \cdot x .

Thus, the solution to the problem is 8xx4x 8\cdot x\cdot x-4\cdot x .

Answer

8xx4x 8\cdot x\cdot x-4\cdot x