Simplify the Expression: 7z+10b+2bz+35 Using Like Terms

Which of the expressions is equivalent to the expression?

7z+10b+2bz+35 7z+10b+2bz+35

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the common factor
00:06 Use the commutative property and arrange the exercise
00:16 Factor 35 into factors 7 and 5
00:24 Factor 10 into factors 5 and 2
00:34 Mark the common factors
00:56 Take out the common factors from the parentheses;
01:21 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Which of the expressions is equivalent to the expression?

7z+10b+2bz+35 7z+10b+2bz+35

2

Step-by-step solution

To solve this problem, we'll focus on factorization by grouping:

  • Step 1: Identify groupable terms in 7z+10b+2bz+35 7z + 10b + 2bz + 35 .
  • Step 2: Reorganize and group terms for greatest common factor extraction.
  • Step 3: Factor each group and simplify.

Now, let's work through each step:

Step 1:
Observe that we can reorganize the expression to facilitate grouping:

7z+35+10b+2bz 7z + 35 + 10b + 2bz .

Step 2:
Group into pairs: (7z+35)+(10b+2bz)(7z + 35) + (10b + 2bz).
Within each pair, extract common factors:

=7(z+5)+2b(z+5)= 7(z + 5) + 2b(z + 5), noticing that each group factors nicely.

Step 3:
Since both terms now have a common factor of (z+5)(z + 5), we can factor it out:

=(7+2b)(z+5)= (7 + 2b)(z + 5).

Therefore, the expression 7z+10b+2bz+35 7z + 10b + 2bz + 35 is equivalent to (7+2b)(z+5)(7 + 2b)(z + 5).

This matches choice 1: (7+2b)(z+5) (7+2b)(z+5) .

3

Final Answer

(7+2b)(z+5) (7+2b)(z+5)

Practice Quiz

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Break down the expression into basic terms:

\( 4x^2 + 6x \)

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