Vertical Subtraction: Triple digit addition with regrouping

To solve the problem of subtracting 196 from 285 using vertical subtraction, follow these steps:

• Step 1: Write the numbers vertically, aligning them by place value:
  $\begin{array}{c} \phantom{0}285 \\ -196 \\ \underline{\phantom{076}} \\ \end{array}$
• Step 2: Start with the units column (rightmost digits). Subtract 6 from 5. Since 5 is smaller than 6, we need to carry from the tens column:
  - Take 1 from 8 (in the tens column) to make it 7. - Add 10 to the 5 in the units column, making it 15. - Now, $15 - 6 = 9$.
• Step 3: Move to the tens column. Subtract 9 from 7. Since 7 is smaller than 9, we need to carry from the hundreds column:
  - Take 1 from 2 (in the hundreds column) to make it 1. - Add 10 to the 7 in the tens column, making it 17. - Now, $17 - 9 = 8$.
• Step 4: Finish with the hundreds column. Subtract 1 from 1 (after carrying):
  - $1 - 1 = 0$.
• Step 5: Combine the results to get the final answer:
  - The result of the subtraction is 089, or simply 89.

Therefore, the result of subtracting 196 from 285 is $89$.

To solve this problem, we'll perform vertical subtraction as follows:

We'll align the numbers by their place values:
     $314$
-  126

Start with the rightmost column (the units place):

• Units Place: $4 - 6$ requires borrowing because 4 is less than 6. Borrow 1 from the tens column in 314, turning it into 10, leaving 0 in the tens place. Now, $14 - 6 = 8$.

• Tens Place: After borrowing, $0 - 2$ also requires borrowing from the hundreds column. Borrow 1 from the hundreds column, leaving $2$ in the hundreds place. Now, $10 - 2 = 8$.

• Hundreds Place: Subtract as normal, $2 - 1 = 1$.

When we put it all together, the result is:

• Hundreds: $1$

• Tens: $8$

• Units: $8$

Therefore, $314 - 126 = 188$.

The solution to the problem is $188$, which matches choice $4$.

To solve this problem, we'll perform vertical subtraction:

• Step 1: Subtract the units place.
• Step 2: Subtract the tens place after borrowing if necessary.
• Step 3: Subtract the hundreds place.

Now, let's work through each step:

Step 1: Units Place
We have $3$ (from 453) and $9$ (from 269). Since $3$ is less than $9$, we need to borrow 1 from the tens column:

• Borrow 1 from the tens column (making it $4 \rightarrow 3$), change units to $13$.
• Subtract: $13 - 9 = 4$.

Step 2: Tens Place
After borrowing, we have $3$ in the tens place (originally $5$, but $1$ was borrowed) and $6$ in the tens place of 269. Since $3$ is less than $6$, we need to borrow 1 from the hundreds column:

• Borrow 1 from the hundreds column (making it $4 \rightarrow 3$), change tens to $13$.
• Subtract: $13 - 6 = 7$.

Step 3: Hundreds Place
After borrowing, we have $3$ in the hundreds place and $2$ in the hundreds place of 269:

• Subtract: $3 - 2 = 1$.

Therefore, the solution to the problem is $184$.

To begin solving the subtraction $542 - 356$, we will break it down step by step:

• Step 1: Subtract the units digit
  - The units digits are 2 (from 542) and 6 (from 356).
  - Since 2 is smaller than 6, we need to borrow 1 ten from the tens place, changing it from 40 to 30 (of the minuend).
  - The borrowed 10 changes the 2 to 12: $12 - 6 = 6$.
• Step 2: Subtract the tens digit
  - Now the tens digit is 3 (originally 4 but reduced to 3 due to borrowing) minus 5.
  - We need to borrow 1 hundred (from 5 hundreds), which changes it to 4 hundreds, making the tens digit 13.
  - Calculate $13 - 5 = 8$.
• Step 3: Subtract the hundreds digit
  - The hundreds digit is 4 (from the previous borrow) minus 3 from the subtrahend.
  - Calculate $4 - 3 = 1$.

Thus, combining all these, we obtain the result of the subtraction: $186$.

Therefore, the solution to the problem is $186$.

To solve this problem, we will perform a detailed step-by-step subtraction:

• Step 1: Write the numbers in column format, aligning them by place value:

$\begin{array}{c} 664 \\ -275 ~~~\\ \hline \end{array}$

• Step 2: Start subtracting from the rightmost column (units place):

• Subtract the units: $4 - 5$. Since 4 is smaller than 5, we need to borrow from the tens place.

  - Borrow 1 from the tens (making it 5), the 4 becomes 14: $(14 - 5 = 9).$

• Step 3: Move to the tens place:

• Since we borrowed 1, we have the tens as 5 now, perform: $5 - 7$. Again, 5 is smaller than 7, so borrow from the hundreds place.

  - Borrow 1 from the hundreds (making it 5), the 5 becomes 15: $(15 - 7 = 8).$

• Step 4: Now, proceed to the hundreds place:

• After borrowing, the hundreds place is 5 (originally 6, minus 1 borrowed), perform: $5 - 2$.

  - No need to borrow here, simply calculate: $(5 - 2 = 3).$

• Step 5: Compile the final result from top to bottom:

• $389$

Therefore, the answer to the subtraction $664 - 275$ is $\mathbf{389}$.

To solve this problem, we'll follow these steps in vertical subtraction:

• Step 1: Write down the numbers aligning them by their place values:

$\begin{aligned} & 756 \\ - & 667 \\ \hline \phantom{0} \end{aligned}$

• Step 2: Subtract the units digit:

The units digit of 756 is 6, and the units digit of 667 is 7. Since 6 < 7, we need to regroup. We borrow 1 from the tens column, turning the 5 into a 4, and make the 6 into 16. Now $16 - 7 = 9$.

• Step 3: Subtract the tens digit:

After regrouping, the tens digit of 756 became 4, and we subtract the tens digit of 667, which is 6. Again, since 4 < 6, we need to regroup from the hundreds column. Borrowing 1, we turn the 7 into a 6, and the 4 into 14. Now $14 - 6 = 8$.

• Step 4: Subtract the hundreds digit:

The hundreds digit of 756 after regrouping is now 6, and for 667, it is 6 as well. So, $6 - 6 = 0$.

After completing the subtraction, we have:

$\begin{aligned} & 756 \\ - & 667 \\ \hline & 089 \end{aligned}$

Therefore, the solution to the subtraction problem is $\boldsymbol{89}$.

To solve this problem, we’ll perform vertical subtraction:

• Step 1: Subtract the units digit: $7$ (in 867) - $8$ (in 578) requires borrowing. Borrow 1 ten from the tens place of 867, making the units place $17$ and the tens place $5$.
• Step 2: Now, $17 - 8 = 9$. The digit in the units place of the answer is 9.
• Step 3: Subtract the tens digit: With the new tens digit, $5 - 7$ also requires borrowing. Borrow 1 from the hundreds place, making the tens place $15$ and the hundreds place $7$.
• Step 4: Now, $15 - 7 = 8$. The digit in the tens place of the answer is 8.
• Step 5: Subtract the hundreds digit: $7 - 5 = 2$. The digit in the hundreds place of the answer is 2.

Therefore, the final answer after subtraction is $289$.

To solve this subtraction problem, we'll perform vertical subtraction, which involves subtracting each corresponding pair of digits from right to left.

• Step 1: Arrange the numbers vertically.
  • Write 936 (the minuend) on top.
  • Write 768 (the subtrahend) below it, aligning the digits by place value.
• Step 2: Subtract the ones place.
  Subtract 8 from 6. Since 8 is larger than 6, we need to borrow 1 from the tens place:
  • Decrease the digit in the tens place (from 3 to 2).
  • Increase the ones digit by 10 (making it 16).
  • 16 - 8 = 8, write 8 below the line.
• Step 3: Subtract the tens place.
  Now subtract 6 from the adjusted tens digit (2):
  • Since 6 is larger than 2, borrow 1 from the hundreds place (from 9 to 8).
  • Increase the tens digit by 10 (making it 12).
  • 12 - 6 = 6, write 6 below the line.
• Step 4: Subtract the hundreds place.
  Subtract 7 from the adjusted hundreds digit (8):
  • 8 - 7 = 1, write 1 below the line.

Thus, the result of the subtraction $936 - 768$ is 168.

To solve the problem of subtracting 289 from 478, we perform the following steps:

• Setup: Write the numbers in column form, aligning by place value:
  $\begin{aligned} & 478 \\ - & 289 \\ \end{aligned}$
• Subtract Ones: Start from the rightmost column (ones place):
  $8 - 9$. Since 8 is smaller than 9, borrow 1 from the tens place (7), making it 6 and converting the 8 to 18.
  Now, perform $18 - 9 = 9$.
• Subtract Tens: Move to the tens column, now having $6$ from borrowing from the previous step:
  $6 - 8$. Again, since 6 is less than 8, borrow 1 from the hundreds place (4), making it 3 and converting the 6 to 16.
  Now, perform $16 - 8 = 8$.
• Subtract Hundreds: Finally, subtract the hundreds column:
  $3 - 2 = 1$.
• Assemble the result: The completed subtraction gives us $189$.

Therefore, the solution to the problem is $189$, which corresponds to choice 2.

To solve the subtraction problem $843 - 157$, follow these steps:

• Align the numbers vertically:

     843
    - 157
    ------
    

• Start subtracting from the rightmost column (units):

  • Units place: $3 - 7$. Since 3 is less than 7, we need to borrow. Borrow 1 from the tens place, turning the 4 into a 3, and making the 3 in the units place a 13.

  • After borrowing, subtract: $13 - 7 = 6$.

• Move to the tens column:

  • After borrowing, we have $3 - 5$. Borrow 1 from the hundreds place, turning the 8 into a 7, and making the tens 3 into 13.

  • Subtract: $13 - 5 = 8$.

• Finally, subtract the hundreds column: $7 - 1 = 6$.

 843
- 157
-----
  686

Therefore, the final result of the subtraction $843 - 157$ is $686$.

To solve this problem, we'll follow the vertical subtraction method:

• First, subtract the ones place: $6 - 9$. Since $6$ is less than $9$, we need to borrow from the tens place.
• Turn $8$ in the tens place of $686$ into $7$, and the ones place becomes $16$.
• Now subtract the ones place: $16 - 9 = 7$.
• Then subtract the tens place: $7 - 9$. Again, we need to borrow.
• Turn $6$ in the hundreds place of $686$ into $5$, and the tens place becomes $17$.
• Subtract the tens: $17 - 9 = 8$.
• Finally, subtract the hundreds place: $5 - 4 = 1$.

Therefore, the result of the subtraction $686 - 499$ is $187$.

To solve this problem, we'll follow these steps:

• Step 1: Set up the numbers for vertical subtraction

• Step 2: Perform subtraction starting from the rightmost column

• Step 3: Apply regrouping (borrowing) if necessary

Let's work through each step:

Step 1: Set up the numbers as follows:
$\begin{array}{c} &amp; 3 &amp; 7 &amp; 2 \\ - &amp; 1 &amp; 8 &amp; 5 \\ \hline &amp; &amp; \\ \end{array}$

Step 2: Start with the units column: $2 - 5$. Since 2 is less than 5, we need to regroup:

Step 3: Borrow 1 from the tens column, turning 7 into 6 and 2 into 12. Now subtract the units: $12 - 5 = 7$.

Next, move to the tens column. After borrowing, we have $6$ in the tens column, subtract $8$ (from the subtrahend):

Since $6 - 8$ is not possible without borrowing, we need to regroup.

Borrow 1 from the hundreds column, turning $3$ into $2$ and $6$ into $16$. Now subtract the tens: $16 - 8 = 8$.

Lastly, move to the hundreds column. After borrowing, it's $2 - 1 = 1$. Place this value in the hundreds place.

The final subtraction setup and answer is:
$\begin{array}{c} &amp;2 &amp; 16 &amp; 12 \\ - &amp; 1 &amp; 8 &amp; 5 \\ \hline &amp;1 &amp; 8 &amp; 7 \\ \end{array}$

Therefore, the solution to the problem is $187$.