Vertical Subtraction: 4-digits with additional regrouping

To solve the subtraction problem $3732 - 2865$, we will use the vertical subtraction method and ensure proper borrowing where needed:

• Step 1: Subtract the units digit: $2 - 5$. Since 2 is less than 5, we borrow 10 from the tens column, making it $12$. Then, $12 - 5 = 7$.

• Step 2: Move to the tens digit: Due to borrowing, we now have $2$ (from the original 3) in the tens column. Subtract $6$, i.e., $2 - 6$. We need to borrow from the hundreds column, so $12 - 6 = 6$.

• Step 3: Hundreds digit: Originally, we have $7$ but reduced to $6$ due to prior borrowing. Subtract $8$, i.e., $6 - 8$. We borrow from the thousands: $16 - 8 = 8$.

• Step 4: Thousands digit: Now having $2$ (from the original 3 due to borrowing), subtract $2$: $2 - 2 = 0$.

The solution to the subtraction of $3732 - 2865$ is $867$.

To solve this problem, we will subtract 2197 from 4176 using vertical subtraction. Here are the steps we'll follow:

• Arrange the two numbers in a vertical format, ensuring the digits are aligned by their place value.
• Subtract starting from the rightmost digit (ones place) to the leftmost digit (thousands place), borrowing from the column to the left if the top digit is smaller than the bottom digit.

Let's carry out each step:

Step 1: Subtract the ones digit. The first number 4176 has 6 in the ones place, and the second number 2197 has 7. Since 6 is less than 7, we need to borrow from the tens place.

Borrow 1 from the tens place (turning 7 into 6), making 16 in the ones place:
16 - 7 = 9
Write 9 in the result's ones place.

Step 2: Subtract the tens digit. After borrowing, the tens place now has the digit 6 in our minuend. The subtrahend's tens digit is 9, and since 6 is less than 9, we borrow again from the hundreds place.

Borrow 1 from the hundreds place (turning 1 into 0), making 16 in the tens place:
16 - 9 = 7
Write 7 in the result's tens place.

Step 3: Subtract the hundreds digit. Now in the minuend, we have 0 in the hundreds place, and the subtrahend has 1. Again, we need to borrow from the thousands place.

Borrow 1 from the thousands place (turning 4 into 3), making 10 in the hundreds place:
10 - 1 = 9
Write 9 in the result's hundreds place.

Step 4: Subtract the thousands digit. Finally, subtract the thousands place:
3 (adjusted from borrowing) - 2 = 1
Write 1 in the result's thousands place.

Putting it all together, the result of the subtraction is:

The final answer is $1979$.

To solve this problem, we'll execute vertical subtraction with regrouping as follows:

Let's start by aligning the numbers one above the other:
$\begin{array}{c} && 5 & 4 & 2 & 1 \\ - & & 3 & 6 & 7 & 5 \\ \hline \end{array}$

We begin subtraction from the rightmost digits (units place):

• Units: $1 - 5$ requires borrowing because 1 is less than 5. Borrow 1 from the tens (making it 3), turning 1 into 11. Now, $11 - 5 = 6$.

Next, subtract the tens:

• Tens: $2 - 7$ requires borrowing because 2 is less than 7. Borrow 1 from the hundreds (making it 3), turning 2 into 12. Now, $12 - 7 = 5$.

Then, subtract the hundreds:

• Hundreds: $3 - 6$ requires borrowing because 3 is less than 6. Borrow 1 from the thousands (making it 4), turning 3 into 13. Now, $13 - 6 = 7$.

Finally, subtract the thousands:

• Thousands: $4 - 3 = 1$.

Putting it all together, the result is:

$\begin{array}{c} & 5 & 4 & 2 & 1 \\ - & 3 & 6 & 7 & 5 \\ \hline & 1 & 7 & 4 & 6 \\ \end{array}$

Therefore, the solution to the problem is $1746$.

Let's solve the subtraction problem step-by-step:

We have:

$\begin{array}{c} 6210 \\ - \, 4242 ~~~~\\ \hline \end{array}$

• Step 1: Subtract the units place.

The units digit of the minuend (0) is less than the units digit of the subtrahend (2). We need to borrow. Borrowing from the tens place changes the 1 to a 0 in the tens place and the units place becomes 10. Finally, 10 - 2 = 8.

• Step 2: Subtract the tens place.

After borrowing, the tens digit in the minuend is 0, with the subtrahend having a tens digit of 4. We need to borrow from the hundreds place. Borrowing changes the hundreds digit of the minuend from 2 to 1, and the tens digit becomes 10. Finally, 10 - 4 = 6.

• Step 3: Subtract the hundreds place.

The hundreds digit of the minuend after borrowing is 1, while the subtrahend has 2. We borrow once more from the thousands place. The thousands digit decreases from 6 to 5, making the hundreds digit 11. So, 11 - 2 = 9.

• Step 4: Subtract the thousands place.

Now, the thousands digit of the minuend is 5, and the subtrahend digit is 4. Simply perform the subtraction: 5 - 4 = 1.

Putting it all together, the result of the subtraction is 1968.

Therefore, the solution to the problem is $1968$.

To solve the subtraction problem $7015 - 4246$, we will proceed with vertical subtraction by following these steps:

• Step 1: Write the numbers vertically, aligning by their place values.
• Step 2: Start subtracting from the rightmost digit (units place).
• Step 3: Handle borrowing (regrouping) where necessary:

Let's perform the subtraction:

Step 1: Align the numbers vertically:

$\begin{array}{cccc} & & & 7015 \\ - & & & 4246 \\ \hline \end{array}$

Step 2: Subtract from the rightmost digit (units place):

• Units: $5 - 6$ is not possible without borrowing, so we borrow 1 from the tens place.
• This makes the units place $15 - 6 = 9$.

Step 3: Move to the tens place:

• After borrowing, tens: $0$ becomes $10$, and you initially borrowed $1$, so you'll have $10 - 1 - 4 = 6$.

Step 4: Move to the hundreds place:

• The hundreds have already been adjusted for borrowing, it's originally $1$ (borrowed from thousands), so computing $9 - 2 = 7$.

Step 5: Move to the thousands place:

• Finally, $7 - 4 = 3$.

Thus, the result of the subtraction $7015 - 4246$ is $2769$.

Therefore, the correct answer choice, comparing against the given options, is 2769, corresponding to choice 2769.

To solve the problem of subtracting 5278 from 8314, we'll follow these steps:

• Step A: Subtract the units: $4 - 8$. Since 4 is less than 8, we need to borrow 1 from the tens column, making it $14 - 8 = 6$.
• Step B: After borrowing, the tens column is $0$ (since the 1 we borrowed from 1 in 31 becomes 30). So, $0 - 7$ again requires borrowing from hundreds, making it $10 - 7 = 3$.
• Step C: The hundreds column reduces to 2 after borrowing, leading to $2 - 2 = 0$.
• Step D: Finally, the thousands column, $8 - 5$, gives us $3$.

Therefore, the result of the subtraction $8314 - 5278$ is $3036$.