Vertical Subtraction: 2-digit and 1-digit numbers -regrouping of tens

To solve this problem, we'll follow these steps:

• Step 1: Align the numbers vertically by place value, with larger on top.
• Step 2: Subtract the digit in the ones place.
• Step 3: Consider if regrouping is needed for subtraction.

Now, let's work through each step:

Step 1: Align the numbers vertically like this:
$\begin{array}{r} 24 \\ - \phantom{0}\\ ~~5 \\ \end{array}$

Step 2: Start subtraction at the units (ones) place and go from right (ones column) to left (tens column):

Subtract the ones place:
4 (top number) - 5 (bottom number) is not possible without borrowing because 4 is less than 5.

Step 3: Regroup: Borrow 1 ten from the tens place of the top number $24$:
- Turn the 2 tens into 1 ten, so it becomes 1 in the tens place, and add 10 to the ones place, turning it into 14.

Now we have:
$\begin{array}{r} 1 {14} \\ - \phantom{0}\\ ~~~5 \\ \end{array}$

Now subtract the ones: $14 - 5 = 9$
Subtract the tens: $1 - 0 = 1$ (as there are no tens in $5$).
Combine them to get 19.

Therefore, the solution to the problem is $19$.

To solve this problem, follow these steps:

• Step 1: Write the numbers vertically with 35 on top and 7 underneath. Align them by their rightmost digits.
• Step 2: Start subtracting the rightmost digit (units place). Subtract 7 from 5.
• Step 3: Since 5 is smaller than 7, we need to regroup. We take 1 ten from the tens place, turning 35 into 25 and 15.
• Step 4: Subtract 7 from 15 in the units place, which gives us 8.
• Step 5: Move to the tens place. After regrouping, 25 has a digit of 2 in the tens place. Subtract 0 from 2, which remains 2.

The result of the subtraction is $28$.

Therefore, the correct answer is 28.

To solve this problem, we'll follow these steps:

• Step 1: Perform vertical subtraction aligning the numbers by place value.

• Step 2: Subtract the digits in the ones place and the tens place, borrowing if needed.

Now, let's work through each step:

Step 1: Write the numbers vertically:

$\begin{aligned} &43 \\ -& \\ &~~6 \\ \end{aligned}$

Step 2: Begin subtracting from the right (ones place):

- $3 - 6$ needs borrowing since 3 is less than 6.
- We borrow 1 from the tens digit, turning 3 into 13 and reducing the 4 to 3 in the tens place.

- Now, subtract: $13 - 6 = 7$.

Move to the tens place:

- With the tens place borrowed from earlier, $3 - 0 = 3$.

Therefore, the answer to the subtraction $43 - 6$ is $\mathbf{37}$.

Thus, the correct answer is $37$

To solve this problem, we'll perform the subtraction $55 - 8$ using a step-by-step process:

• Step 1: Identify place values for subtraction. The number 55 has a 'tens' place (5) and a 'ones' place (5).
• Step 2: Subtract the ones place. We need to subtract 8 from 5. Since 5 is smaller than 8, borrowing is necessary.
• Step 3: Borrow from the tens place. Change 55 to 4 tens and 15 ones:
• The tens digit is reduced by 1 (from 5 to 4).
• Add 10 to the ones digit, changing it from 5 to 15.
• Step 4: Subtract the ones place now: $15 - 8 = 7$.
• Step 5: Subtract the tens place: Now we have 4 in the tens place (after borrowing), so $4 - 0 = 4$.

Therefore, the result of $55 - 8$ is $\mathbf{47}$.

The correct answer is 47, corresponding to choice 3.

To solve this subtraction problem, we'll use the following steps:

• Step 1: Subtract the ones place.

• Step 2: Employ borrowing if necessary.

• Step 3: Subtract the tens place after borrowing.

Now, let's apply these steps:

Step 1: Subtract the ones place.
In the ones place, we have $7 - 9$. Since $7$ is smaller than $9$, we need to borrow.

Step 2: Borrow from the tens place.
Borrow $1$ from the tens place, turning the $67$ into $5$ tens and $17$ in the ones place. Now, perform $17 - 9 = 8$.

Step 3: Subtract the tens place after borrowing.
Now that we've borrowed, we have $5$ in the tens place. Subtract $0$ (there's nothing to subtract, effectively). So, the tens remain $5$.

The final result after the subtraction is:
Therefore, the answer is $58$.

To solve this vertical subtraction problem, follow these steps:

Step 1: Set up the problem vertically.

Write 72 and 8 ensuring that the digits are aligned according to their place values:

72
- 8
$\underline{\phantom{72}}$

Step 2: Start subtracting from the rightmost digit (ones place).

In the ones place, we have 2 (from 72) and 8 (from -8). Since 2 is less than 8, we need to regroup.

Step 3: Perform regrouping.

Take 1 ten from the tens place of 72, leaving 6 tens. Adding 10 ones to 2 makes it 12 in the ones place.

Rewritten, the problem now looks like this:

6 12
- 8
$\underline{\phantom{72}}$

Step 4: Continue with subtraction in the ones place.

Subtract 8 from 12, which equals 4.

Step 5: Subtract in the tens place.

Now, move to the tens place. We have 6 tens (from the regrouped value) and since there is no tens digit to subtract, it remains 6.

Conclusion: Combine the results from each place value to find the final difference: $6$ tens and $4$ ones make $64$.

Therefore, the solution to the problem is $64$.

To solve this problem, we'll perform vertical subtraction with regrouping:

• Step 1: Write the numbers vertically:

$88$
$-9$

• Step 2: Start with the units column (rightmost). We have $8 - 9$.

• Step 3: Since you can't subtract 9 from 8 directly without going negative, we regroup. Borrow 1 from the tens place of 88.

• Step 4: Change the tens column: $88$ becomes $7$ tens and the units column becomes $18$ (since you borrowed 10).

• Step 5: Now subtract: $18 - 9 = 9$.

• Step 6: Move to the tens column (now 7): Subtract 0 from 7 (since no tens are in 9): $7 - 0 = 7$.

Therefore, the result of the subtraction is $79$.

To conclude, the solution to the subtraction problem is $79$.

To solve the subtraction problem $91 - 7$, we'll align the numbers vertically and perform the operation step by step.

Step 1: Align the numbers vertically:

$\begin{aligned} &91 \\ -& \\ &~~7 \\ \end{aligned}$

Step 2: Subtract the units:

The units digits are $1$ from $91$ and $7$. Notice that $1$ is less than $7$, so we need to borrow from the tens digit of $91$.

- Regroup the tens and units: Borrow $1$ ten from the tens place $9$:
$91$ becomes $8$ in the tens place and $11$ in the units place, represented as:

$\begin{aligned} 8~11& \\ -~~~~ 7~& \end{aligned}$

Step 3: Perform the final subtraction:

- Subtract the units: $11 - 7 = 4$.

- The tens remain $8$, so the resulting number is $84$.

Therefore, the solution to the problem is $84$.

Let us solve the subtraction problem $72 - 8$ step-by-step.

1. Write the numbers vertically, ensuring that the digits are aligned by place value:

•     72
  -      8
  $\underline{\phantom{776}}$

2. Subtract the digits in the units column:

• Since $2$ is smaller than $8$, we need to borrow from the tens column.
• Adjust the tens digit from $7$ to $6$ (because we borrow 10 from it) and make the units digit $2 + 10 = 12$.

3. Now perform the subtraction for the units column:

• Subtract $8$ from $12$, which equals $4$.

4. Now, focus on the tens column:

• Subtract the adjusted tens digit, $6$, from $0$ (as there is no digit under it in the subtrahend), resulting in $6$.

5. This gives us the final answer:

• The result of $72 - 8$ is $\mathbf{64}$.

Therefore, the solution to the problem is $64$.

To solve this problem, we will perform vertical subtraction with regrouping:

Step 1: Set up the subtraction vertically:

$\begin{aligned} 88& \\ -~~~ 9& \\ \hline & \phantom{\ } \\ \end{aligned}$

Step 2: Compare the unit places:

The units digit in 88 (8) is less than the units digit in 9 (9), necessitating regrouping.

Step 3: Regrouping:

• Borrow 1 ten from the tens digit (8 tens becomes 7 tens).

• Add that ten to the units digit, making it $18$ instead of $8$.

Step 4: Perform the subtraction:

• Subtract the units place: $18 - 9 = 9$.

• Subtract the tens place: $7 - 0 = 7$, since the tens place in 9 is effectively 0.

Step 5: Combine the results.

The difference is $79$.

Thus, the solution to the subtraction problem is $79$.

Let's solve the subtraction problem:

When subtracting two numbers vertically, begin with the rightmost column, which involves the ones.
Step 1: Subtract the ones place digits: 6 - 8. Since 6 is less than 8, we cannot subtract directly. Therefore, we need to borrow 1 ten (equivalent to 10 ones) from the tens place.
Step 2: After borrowing, the tens digit of 76 (7) reduces by 1, becoming 6, and the ones digit gets 10 more, making it 16.
Step 3: Now, subtract the ones place: 16 - 8 = 8.
Step 4: Then, subtract the tens place: 6 - 0 = 6. Recall that we subtracted 1 ten earlier.
Combine the two results for the final answer: 68.

Therefore, the solution to the subtraction problem is $76 - 8 = 68$.

To solve this subtraction problem, we will use the vertical subtraction method. Here’s how to approach it step-by-step:

• Step 1: Arrange the numbers in a column, aligning them by place value. The top number (the minuend) is 94, and the bottom number (the subtrahend) is 6.

• Step 2: Begin subtracting from the rightmost column (the ones place). Here we have:

$~~~~4$

$-~~6$

• Since 4 is less than 6, we need to regroup. We'll borrow 1 ten from the tens place:

$~~~~14$ (after borrowing)

$-~~6$

• Step 3: Subtract the ones now: 14 - 6 = 8, write 8 under the ones column.

• Step 4: Move to the tens column where we initially had 9 tens, but now it’s reduced by 1 tens due to regrouping, making it 8 tens. Thus:

$~~~~8$

$-~~0$

• There’s nothing to subtract from 8 in the tens place, so it remains 8. Write 8 under the tens column.

• Therefore, after performing the subtraction, the final result is 88.

Hence, the solution to the subtraction problem is $88$.