Vertical Subtraction: 4-digits with 2 additional regrouping

To solve this problem, we'll carry out vertical subtraction by following these steps:

• Step 1: Write the minuend and subtrahend vertically aligned, ensuring each digit stands in its respective column.
• Step 2: Start subtracting from the rightmost column (units) and move leftwards, managing any requisite borrowing.

Let's execute the subtraction:

Step 1: Begin with the units column.

$9 - 3 = 6$

Step 2: Move to the tens column.

$8 - 9$

Since 8 is smaller than 9, we need to borrow 1 from the hundreds column, changing 8 to 18:

$18 - 9 = 9$

Step 3: Move to the hundreds column. Since we've borrowed 1, adjust accordingly.

$6 - 7$

Here, we again need to borrow from the thousands column making it 16:

$16 - 7 = 9$

Step 4: In the thousands column, after borrowing, we have:

$1 - 0 = 0$

Thus, compiling the subtractions, we are left with the final solution:

$996$

Therefore, the solution to the subtraction problem $1789 - 793$ is $996$, which corresponds to choice 2.

Let's solve the problem using vertical subtraction with regrouping:

1. Start by aligning the numbers vertically by place value:

$\begin{aligned} &2382 \\ - &\,453 \\ \end{aligned}$

2. Perform subtraction starting from the units place (rightmost) column:

• Units: $2 - 3$. Since $2$ is smaller than $3$, we need to borrow from the tens place. Change $8$ in the tens place to $7$ and add $10$ to $2$ to make it $12$. Now, $12 - 3 = 9$.
• Tens: Go to the tens column, which is now $7 - 5$. Subtraction results in $2$, as borrowing was resolved previously.
• Hundreds: In the hundreds place, $3 - 4$ is not possible without borrowing. Borrow from the thousands place: Change $2$ to $1$ (thousands place) and add $10$ to $3$ (hundreds place), making it $13$. Now, $13 - 4 = 9$.
• Thousands: The thousands place subtraction is $1 - 0$, which simply results in $1$.

After completing the subtraction across each column, the final result is:

$\begin{aligned} &1929 \\ \end{aligned}$

Thus, the solution to the subtraction problem is $1929$.

To solve the problem $3321 - 145$, we need to conduct vertical subtraction step by step. Let's proceed through each digit from right to left:

• Units Place:
  Current digits: 1 (from 3321) and 5 (from 145).
  We need to subtract 5 from 1, which requires borrowing as 1 is less than 5.
  1: Borrow from tens place (2 becomes 1), making this 11.
  Now calculate: $11 - 5 = 6$.
• Tens Place:
  Current digits: 1 (left after borrowing from 2) and 4 (from 145).
  We need to subtract 4 from 1, which means we borrow as 1 is less than 4.
  21: Borrow from hundreds place (3 becomes 2), making this 11.
  Then calculate: $11 - 4 = 7$.
• Hundreds Place:
  Current digits: 2 (after borrowing from 3) and 1 (from 145).
  Now calculate: $2 - 1 = 1$.
• Thousands Place:
  Current digits: 3 (minuend) and no digit in subtrahend at this place.
  So, the result is unchanged: $3 - 0 = 3$.

By following these step-by-step calculations, the result is $3321 - 145 = 3176$.

Therefore, the final difference is $3176$.

To solve the subtraction problem $4735 - 816$, we will perform each subtraction step by step:

Let's write the numbers vertically:

$\begin{array}{c} 4735 \\ -~\phantom0816~~~~~ \\ \hline \end{array}$

Step 1: Start from the rightmost digit (the units place):

• We need to subtract 6 from 5. Since 5 is smaller than 6, we need to borrow from the tens place.

Step 2: Borrowing from the tens place:

• The 3 (in the tens place) becomes 2, and the 5 (in the units place) becomes 15.

• Now, subtract 6 from 15 to get 9 in the units place.

Step 3: Move to the tens place:

• We now need to subtract 1 from 2 (since we have already borrowed 1 from the tens place).

• This gives us 1 in the tens place.

Step 4: Move to the hundreds place:

• Subtract 8 from 7. Since 7 is smaller than 8, we have to borrow from the thousands place.

Step 5: Borrowing from the thousands place:

• The 4 (in the thousands place) becomes 3, and the 7 (in the hundreds place) becomes 17.

• Now, subtract 8 from 17 to get 9 in the hundreds place.

Step 6: Move to the thousands place:

• Subtract 0 from 3 (since no borrowing is needed here) to get 3 in the thousands place.

Putting it all together, the result is:

$\begin{array}{c} 3919 \\ \hline \end{array}$

Thus, the solution to the subtraction problem $4735 - 816$ is $3919$.

We aim to solve $5763$ minus $178$ using vertical subtraction.

First, align the numbers by their place value:
$\begin{array}{c} \phantom{1}5763 \\ -~~178 \\ \hline \end{array}$

Step 1: Start from the rightmost digit (units place).
Units: $3 - 8$: Since $3$ is less than $8$, we need to borrow.

Borrow from the tens place:
The $6$ in the tens becomes $5$ (after borrowing 1), making the units place $13$.

So, $13 - 8 = 5$.

Step 2: Move to the tens place now.
Tens: $5 - 7$: Borrow again because $5$ is less than $7$.

Borrow from the hundreds place:
The $7$ in the hundreds becomes $6$, turning the tens into $15$.

So, $15 - 7 = 8$.

Step 3: Now the hundreds place.
Hundreds: $6 - 1 = 5$ (Simple subtraction, no borrowing needed).

Step 4: Finally, the thousands place, which is direct.
Thousands: $5 - 0 = 5$.

Thus, after all stages of subtraction, the result is:
$\begin{array}{c} \phantom{1}5763 \\ -~~178 \\ \hline ~~~ 5585 \\ \end{array}$

Therefore, the solution to the subtraction problem is $5585$.

To solve this problem, we'll follow these steps:

• Step 1: Align the numbers by place value.
• Step 2: Subtract each corresponding digit from right to left.
• Step 3: Borrow from the left if the top digit is smaller than the bottom digit.

Now, let's work through each step:

Step 1: Align 6315 and 1506 vertically by place values:
$\begin{aligned} &6315 \\ -&1506 \\ \hline & \end{aligned}$

Step 2: Start subtracting from the units place:

Units place: $5 - 6$. Since 5 is smaller than 6, we need to borrow 1 from the tens place.
1 becomes 0 (in the tens place), and 5 becomes 15:
$15 - 6 = 9$.

Tens place: Now it’s $0 - 0$. That gives us $0$.

Hundreds place: $3 - 5$ in the hundreds place. Since 3 is smaller than 5, we borrow 1 from the thousands place.
3 becomes 13 and 6 becomes 5:
$13 - 5 = 8$.

Thousands place: $5 - 1 = 4$.

Therefore, the result of subtraction is $4809$.

According to the provided answer choices, the correct choice is choice 3, which is the number $4809$.

The solution to the problem is $4809$.

To solve this problem, we'll use the vertical subtraction method, breaking down the problem into each column from right to left:

• Step 1: Start with the rightmost column (units).
• Units: $9 - 2 = 7$.
• Step 2: Move to the tens column.
• Tens: As $8 - 9$ is not possible, regroup by borrowing 1 from the hundreds column, making it $18 - 9 = 9$.
• Step 3: Proceed to the hundreds column.
• After borrowing, the hundreds column has $0 - 3$ (as it was reduced from 1), borrow from the thousands column: $10 - 3 = 7$.
• Step 4: Finally, calculate the thousands column.
• After borrowing from the thousands, it is now $6 - 2 = 4$.

Putting it all together, we find that:

$7189 - 2392 = 4797$.

The correct answer is $4797$.

The solution involves the vertical subtraction of $8731 - 3252$. Let's break it down step-by-step:

• Step 1: Align the numbers at the units column for vertical subtraction:
  $\begin{array}{c} &8 & 7 & 3 & 1 \\ - & 3 & 2 & 5 & 2 \\ \hline \end{array}$

• Step 2: Subtract the units place: $1 - 2$. Since $1$ is smaller than $2$, we need to borrow from the tens.
  Borrowing from $3$ (tens), which becomes $2$, and the units position turns from $1$ to $11$. Now subtract: $11 - 2 = 9$.

• Step 3: Move to the tens place: $2 - 5$. Again, $2$ is smaller than $5$, borrow from the hundreds.
  Borrow from $7$ (hundreds), which becomes $6$, and the tens becomes $12$. Now subtract: $12 - 5 = 7$.

• Step 4: Move to the hundreds place: $6 - 2$. This results in $4$.

• Step 5: Finally, move to the thousands place: $8 - 3$. This results in $5$.

• Scale down the entire calculation:
  $5479$

Therefore, the result of $8731 - 3252$ is $\textbf{5479}$.

This corresponds to choice 4:

5479

.

To solve this problem, we'll follow these steps:

• Step 1: Write the numbers vertically and align by their place value.
• Step 2: Start subtracting from the rightmost digit (the units place).
• Step 3: Move to the left, regroup as needed for each column.

Let's work through each step:

Step 1: Write the numbers vertically, aligning them by place value:

$\begin{array}{r} 9417 \\ -3708 \\ \hline \end{array}$

Step 2: Begin with the units column:

$7 - 8$

We can't subtract 8 from 7, so we need to regroup. We take 1 ten from the tens place, converting the 7 into 17.

Step 3: After regrouping:

$17 - 8 = 9$

Step 4: Move to the tens column:

$0 - 0 = 0$

No regrouping needed here.

Step 5: Move to the hundreds column:

$4 - 7$

We can't subtract 7 from 4, so we again regroup. We take 1 thousand from the thousands column, making the hundreds digit 14.

Step 6: After regrouping:

$14 - 7 = 7$

Step 7: Finally, the thousands column:

$8 - 3 = 5$

We now have each column solved.

Therefore, the result is 5709.

The solution to the problem is $5709$.

Let's solve the subtraction problem step by step:

First, align the numbers vertically by their place values:

$3 \, 6 \, 1 \, 4$

$- 2 \, 0 \, 3 \, 5$

$\underline{\phantom{3\, 1\, 8\, 9}}$

We start the subtraction from the rightmost digit (ones place):

• In the ones column, $4 - 5$ is not possible, so we need to borrow. Borrow 1 from the tens place.

• The 1 in the tens place becomes 0, and the 4 in the ones place becomes 14.

• Perform the subtraction: $14 - 5 = 9$.

Next, move to the tens column:

• After borrowing, we now have $0 - 3$, which is not possible. We need to borrow from the hundreds place.

• The 6 in the hundreds place becomes 5, and the 0 in the tens place becomes 10.

• Perform the subtraction: $10 - 3 = 7$.

Move to the hundreds column:

• We have $5 - 0$, which results in 5.

Finally, address the thousands column:

$3 - 2 = 1$.

Placing it all together, the result of subtracting 2035 from 3614 is:

$\underline{1 \, 5 \, 7 \, 9}$

Therefore, the solution to the problem is $1579$.