Vertical Subtraction: Simple subtraction of double digits

To solve this problem, we'll perform simple vertical subtraction for the numbers given, 15 and 4:

Step-by-step solution:

• Step 1: Write the numbers in a column, aligning the digits according to place value.
  
• Step 2: Start subtracting from the rightmost column (the ones column).
  In the ones column, subtract 4 from 5:$5 - 4 = 1$.
• Step 3: Move to the tens column. There is no subtraction to perform here since it's only $1 - 0$, which leaves the digit as is.

Thus, there is no borrowing needed because the digits in the minuend are sufficient to carry out the subtraction.

The result of the subtraction $15 - 4$ is $11$.

Therefore, the solution to the problem is $11$.

The correct multiple-choice answer is option 1: $11$.

To solve this problem, we'll perform vertical subtraction:

• Step 1: Write down the numbers vertically with the larger number (the minuend) on top:

$\begin{aligned} &27 \\ -& \\ &~~3 \\ &\underline{\phantom{776}} &\\ \end{aligned}$

• Step 2: Subtract the digits in the ones place: $7$ (from $27$) minus $3$ (from $3$) equals $4$.
• Step 3: Subtract the digits in the tens place: $2$ (from $27$) minus $0$ (no tens in $3$) equals $2$.

Therefore, the difference is $24$.

The solution to the problem is $24$, which corresponds to choice 2.

To solve this problem, we'll follow these steps:

• Step 1: Write the numbers vertically, with each digit aligned in their respective place value.

• Step 2: Begin subtracting starting from the rightmost column.

• Step 3: Move to the left, repeating the process for each subsequent column until finished.

Now, let's work through each step:
Step 1: Arrange the numbers vertically, aligning according to the decimal place.
 39
-   6
-----
Step 2: Start subtracting from the right. Subtract the ones place: $9 - 6 = 3$.
 39
-   6
-----
    3
Step 3: Since there is no need to borrow, move to the tens place:
The tens place comprises '3' from '39', as there is no corresponding digit above '6' to subtract from: $3 - 0 = 3$.
  39
-   6
-----
   33


Therefore, the solution to the problem is $33$.

To solve this problem, we'll follow these steps:

• Step 1: Align the numbers vertically by place value.

• Step 2: Subtract the units place.

• Step 3: Subtract the tens place if necessary.

Now, let's work through each step:
Step 1: Write the numbers 48 and 7 in columns where the digits (ones place) are aligned: $\begin{array}{c} 48 \\ -~7 \\ \end{array}$ Step 2: Subtract the units (8 - 7 = 1) and write the result in the units position.
Step 3: The tens place after subtraction is unchanged because there is no borrowing needed, so the 4 from 48 stays as 4.
Thus, we have: $\begin{array}{c} 48 \\ -~7 ~~\\ \underline{41} \end{array}$

Therefore, the solution to the problem is 41.

To solve this problem, let's use a methodical approach as follows:

• Step 1: Write the numbers in a vertical format, aligning the digits by place value.
• Step 2: Subtract the ones digit: $6$ (from $56$) minus $5$ equals $1$.
• Step 3: Bring down the tens digit since we are not subtracting anything from it: $5$.

In detail:

1. Align the numbers vertically, with the larger number on top:
   $\begin{array}{r} 56 \\ - \phantom{400}5 \\ \hline \end{array}$
2. Subtract the digits in the ones column. The ones digit in $56$ is $6$ and the ones digit in $5$ is $5$. Subtract $5$ from $6$ to get $1$.
3. Since there are no numbers to subtract from the tens column of the first number, write down the $5$ from $56$.

The result of the vertical subtraction is thus:
$\begin{array}{r} 56 \\ - \phantom{400}5 \\ \hline 51 \\ \end{array}$

Therefore, the solution to this problem is $51$.

To solve the problem, let's perform the subtraction using the vertical method:

Step-by-Step Solution:
Given the problem:
$\begin{array}{c} 64 \\ - \, 1 \\ \hline \end{array}$

• Step 1: Align the numbers vertically with 64 on top and 1 on the bottom, making sure to align by the units place.
• Step 2: Subtract the digit 1 from the digit 4 in the units column:
$4 - 1 = 3$
• Step 3: Since there is no subtraction needed in the tens place (as 6 is only being carried over), bring down the 6:
$63$

Therefore, the result of the subtraction $64 - 1$ is $\boxed{63}$.

Since the correct answer matches the choices given, the correct multiple-choice answer is Choice 2.

To solve this problem, we will perform the subtraction $73 - 3$ step by step:

• Step 1: Align the numbers vertically with the minuend (73) on top and the subtrahend (3) directly below it, ensuring proper placement by place value, especially since the subtrahend has fewer digits than the minuend.
• Step 2: Start from the rightmost digit. We have the units place:
• The digit in the units place of the minuend is 3.
• The digit in the units place of the subtrahend is 3.
• Subtract these units digits: $3 - 3 = 0$.
• Step 3: Move to the tens place.
• The digit in the tens place of the minuend is 7.
• There is no corresponding tens digit in the subtrahend, so it can be considered as $0$.
• Subtract these tens: $7 - 0 = 7$.
• Step 4: Combine the results. The digits in the tens and units places are 7 and 0, respectively, forming the number 70.

Therefore, the result of the subtraction $73 - 3$ is $70$.

To find the result of subtracting 9 from 89, we will look at it digit by digit:

• Step 1: Subtract the units digits:
  9 - 9 = 0.
• Step 2: Subtract the tens digits:
  8 - 0 = 8.

The subtraction does not require any borrowing since both digits are smaller than or equal to the digits we are subtracting from.

Thus, the result of the subtraction $89 - 9$ is $80$.

Considering the given multiple-choice options, the correct choice is option 4: $80$.

To solve this problem, we'll follow these steps:

• Step 1: Subtract the one's digits (8 - 2).
• Step 2: Subtract the ten's digits (9 - 0).

Now, let's work through each step:
Step 1: We start with the least significant digit. The one's digit in $98$ is $8$ and in $2$ is $2$. We perform the subtraction $8 - 2 = 6$. So, the one's place in the answer is $6$.

Step 2: Next, we proceed to the ten's digits. The ten's digit in $98$ is $9$ and in $2$ is $0$ (since the subtrahend is only a single digit, it’s effectively $0$ in the tens place). Therefore, the calculation is $9 - 0 = 9$. This makes the ten's digit of the result $9$.

By combining these results, the answer is $96$.

Therefore, the solution to the problem is $96$.

To solve this problem, let's perform vertical subtraction:

• Step 1: Align the numbers 99 and 9 for subtraction.
• Step 2: Subtract starting from the rightmost digits: the ones place.
• Step 3: $9 - 9 = 0$ in the ones place.
• Step 4: Move to the tens place: $9 - 0 = 9$. (Since we did not borrow any value from the tens place, the 9 remains.)

Thus, the result of the subtraction is $90$.

Therefore, the solution to the mathematical problem is $90$, which corresponds to choice 2.