Vertical Subtraction: 2-digit and 2-digit numbers- regrouping of tens

To solve this problem, we'll follow these steps:

• Write the numbers 33 and 15 vertically, aligning by the rightmost digits.
• Subtract the digit in the units place, which is 3 (from 33) minus 5 (from 15). Since 3 is less than 5, we need to borrow 1 ten from the tens place.
• After borrowing, the units digit becomes 13 (instead of 3).
• Now, perform the subtraction: 13 - 5 equals 8.
• Proceed to the tens place: We borrowed 1, leaving 2 in the tens column of 33.
• Subtract the tens: 2 - 1 equals 1.

The final answer, after borrowing and executing the subtraction, is $(33 - 15)$ which equals $18$.

Therefore, the solution to the problem is $18$.

To solve this problem, we'll follow these steps:

• Step 1: Align the numbers vertically, ensuring the ones and tens digits are in the correct columns.
• Step 2: Subtract starting from the ones place, and if needed, borrow from the tens place.
• Step 3: Subtract the tens place.

Let's work through each step:

Step 1: Write the numbers vertically:
$\begin{array}{c} 47 \\ - 29 \\ \end{array}$

Step 2: Start with the ones place: Subtract 9 from 7. Since 7 is less than 9, we will borrow 1 from the tens column, making 7 become 17 in the ones place and reducing the 4 in the tens place to 3:

- Subtract 17 - 9 = 8

Step 3: Now, move to the tens place. Since we borrowed 1, adjust the tens place. Subtract 2 from 3:
- Subtract 3 - 2 = 1

So, writing the subtraction in full gives us:

$\begin{array}{c} 47 \\ - 29 \\ \hline 18 \\ \end{array}$

Therefore, the solution to the problem is 18.

To solve this problem, we'll follow these steps:

• Step 1: Align the numbers by their place values, so the digits in the same position are directly on top of each other.

• Step 2: Subtract the digits in the ones place and perform borrowing if necessary.

• Step 3: Subtract the digits in the tens place after performing any borrowing from the previous step.

Now, let's work through each step:

Step 1: Align the numbers vertically:

$\begin{aligned} & 53 \\ - & 36 \\ \end{aligned}$

Step 2: Starting with the ones place, we see that 3 (in the minuend) is less than 6 (in the subtrahend). So we need to borrow.

• Borrow 1 from the tens place of 53, giving the tens place a value of 4. The borrowed number converts the ones place's 3 into 13.

Now subtract: $13 - 6 = 7$.

The new arrangement looks like this:

$\begin{aligned} \cancel{5}&4 ~~13 \\ -~~~&3~~~~6 \\ \overline{\phantom{123}}& \overline{\phantom{12345}} \\ \end{aligned}$

Step 3: Move to the tens place. After borrowing, the new value is 4.

Subtract: $4 - 3 = 1$.

Thus, the final result is:

$\begin{aligned} & 53 \\ - & 36 \\ & \underline{17} \\ \end{aligned}$

Therefore, the result of the subtraction $53 - 36$ is $\boxed{17}$.

To solve this subtraction problem, we will follow these steps:

• Step 1: Set up the subtraction vertically.

• Step 2: Subtract the numbers in the ones column.

• Step 3: If needed, borrow from the tens column.

• Step 4: Subtract the numbers in the tens column.

Let's work through each step:

Step 1: Set up the subtraction vertically:
    $62$
$-$
    $37$
$\underline{\phantom{64562}}$

Step 2: Subtract the numbers in the ones column.
We have $2$ in the ones position on the top number and $7$ on the bottom number. Since $2$ is less than $7$, we need to borrow 1 from the tens place of the top number.

After borrowing, the $6$ in the tens place becomes $5$, and we add $10$ to the ones place, transforming $2$ into $12$. Now, subtract $7$ from $12$:
 $12$
$-7$
   $\underline{5}$

Step 3: Subtract the tens column. Now, after borrowing, we have $5$ (since $6 - 1 = 5$) in the tens position, minus $3$ from the tens place of the bottom number:
    $5$
$-3$
    $\underline{2}$

Step 4: The final result is obtained by putting together these results. The subtraction yields:
    $25$

Therefore, the solution to the problem is $\textbf{25}$.

To solve this vertical subtraction problem $76 - 57$, let's go through the steps:

• Step 1: Align the numbers by place value.
  The problem is set up vertically as follows: $\begin{aligned} & 76 \\ - & 57 \\ \end{aligned}$
• Step 2: Start with the units digit.
  From the 6 in the units place of 76, subtract the 7 in the units place of 57:
  Since 6 is less than 7, we need to borrow 1 ten from the tens place of 76.
  The tens digit of 76 changes from 7 to 6 (since we borrowed one ten), and the units digit becomes 16.
• Step 3: Subtract the units digit.
  Subtract 7 from 16, resulting in 9.
  This is written in the units place of the answer.
• Step 4: Subtract the tens digit.
  In the tens column, subtract 5 (from 57) from 6 (the new tens of 76 after borrowing), resulting in 1.

The final calculation looks like this:

Therefore, the result of the subtraction is $19$.

To solve this subtraction problem step-by-step, we perform the following:

First, align the numbers for vertical subtraction:

$\begin{array}{r} 83 \\ -66 \\ \hline \end{array}$

Step 1: Subtract the ones place:

The ones digit of $83$ (3) is smaller than the ones digit of $66$ (6). Therefore, we need to borrow.

• Borrow $1$ from the tens place of $83$, which becomes $7$ leaving the original ones place of 13.
• Subtract the ones digits: $13 - 6 = 7$

Step 2: Subtract the tens place:

Now that we've borrowed, we are left with $7$ in the tens place of the top number:

• Subtract the tens digits: $7 - 6 = 1$

Combine the results of the subtraction:

The final answer, after subtracting the two numbers, is $17$.

Therefore, the solution to the problem is $17$, which corresponds to choice 4.

To solve the subtraction problem $97 - 68$, we'll follow these steps:

• Step 1: Set up the numbers vertically, aligning the digits by place value.
• Step 2: Subtract the digits in the units column. Here, $7 - 8$ is not possible without borrowing.
• Step 3: Borrow 1 from the tens column of 97, changing it to 8, and making the units column 17 (since 7 becomes 17 after borrowing).
• Step 4: Subtract the units: $17 - 8 = 9$.
• Step 5: Move on to the tens column: $8 - 6 = 2$.

Now, let's work through the subtraction:

Starting with the units: Borrow from the tens column, so the number in the tens becomes 8 and the units digit becomes 17.

Calculate the units: $17 - 8 = 9$.

Then, calculate the tens: $8 - 6 = 2$.

Putting it all together, the subtraction $97 - 68$ results in $29$.

Therefore, the solution to the subtraction problem is $29$.

To solve this problem, we'll subtract the two-digit numbers using the vertical subtraction method:

• Step 1: Set up the problem vertically with minuend (98) above the subtrahend (79). Ensure digits are aligned by place value.
• Step 2: Begin subtracting from the right-most column, the units place (8 - 9). Since 8 is less than 9, we must regroup.
• Step 3: Regroup by borrowing 1 ten from the tens place of 98. This changes the tens place from 9 to 8, and the ones place becomes 18.
• Step 4: Subtract the units column: $18 - 9 = 9$.
• Step 5: Now subtract the tens place digit. After borrowing, the tens digit of 98 is 8. Subtract: $8 - 7 = 1$.

Combining the results from the two columns, we find that $98 - 79 = 19$.

Therefore, the solution to the problem is $19$.

To solve this problem, we'll use vertical subtraction:

• Step 1: Set up the subtraction vertically, ensuring the digits align properly. Write 74 above 38, with a subtraction line underneath.
• Step 2: Subtract the units column first. We have $4 - 8$ which cannot be done directly since 4 is smaller than 8.
• Step 3: Borrow (regroup) from the tens column, converting 74 into 60 and 14. This is achieved by reducing 74 to 6 tens (60) and adding 10 to the 4 units to make it 14.
• Step 4: Now, subtract the units: $14 - 8 = 6$.
• Step 5: Next, subtract the tens column: $6 - 3 = 3$.
• Step 6: Combine the results of the tens and units: $36$.

Therefore, the solution to the problem is $36$, which corresponds to choice 4.