Trapeze - Examples, Exercises and Solutions

Formula for the area of a trapezoid:

$\frac{(base+base)}{2}\times altura$

We substitute the data into the formula and solve:

$\frac{9+12}{2}\times5=\frac{21}{2}\times5=\frac{105}{2}=52.5$

To find the perimeter we will add all the sides:

$4+5+9+6=9+9+6=18+6=24$

To find the perimeter of the trapezoid, we will sum the lengths of all its sides. The given side lengths are:

• Base 1: $7.5$
• Base 2: $1.5$
• Leg 1: $3$
• Leg 2: $4$

Using the formula for the perimeter $P$ of the trapezoid, we have:

$P = a + b + c + d$

Substituting in the given values:

$P = 7.5 + 1.5 + 3 + 4$

Performing the addition:

$P = 7.5 + 1.5 = 9$

$P = 9 + 3 = 12$

$P = 12 + 4 = 16$

Therefore, the perimeter of the trapezoid is $16$.

To solve this problem, we'll follow these steps:

• Step 1: Identify all given side lengths of the trapezoid.
• Step 2: Apply the formula for the perimeter of the trapezoid.
• Step 3: Sum up the lengths to find the perimeter.

Now, let's work through each step:
Step 1: The problem gives us the lengths of the trapezoid's sides:
- $AB = 2.5$
- $BC = 10.4$
- $CD = 5.3$
- $DA = 6$

Step 2: We use the formula for the perimeter of a trapezoid:

$P = AB + BC + CD + DA$

Step 3: Plugging in the given values, we calculate:

$P = 2.5 + 10.4 + 5.3 + 6$

Calculating further, we have:

$P = 24.2$

Therefore, the perimeter of the trapezoid is $24.2$.

In order to calculate the perimeter of the trapezoid we must add together the measurements of all of its sides:

7+10+7+12 =

36

And that's the solution!

Let's recall that in an isosceles trapezoid, the sum of the two angles on each of the trapezoid's legs equals 180 degrees.

In other words:

$A+C=180$

$B+D=180$

Since angle D is known to us, we can calculate:

$180-50=B$

$130=B$

Given that the trapezoid is isosceles and the angles on both sides are equal, it can be argued that:

$∢C=∢D$

$∢A=∢B$

We know that the sum of the angles of a quadrilateral is 360 degrees.

Therefore we can create the formula:

$∢A+∢B+∢C+∢D=360$

We replace according to the existing data:

$120+120+2x+2x=360$

 $240+4x=360$

$4x=360-240$

$4x=120$

We divide the two sections by 4:

$\frac{4x}{4}=\frac{120}{4}$

$x=30$

True: in every isosceles trapezoid the base angles are equal to each other.

To solve this problem, we'll follow these steps:

• Step 1: Define the geometric properties of a trapezoid.
• Step 2: Define the geometric properties of an isosceles trapezoid.
• Step 3: Conclude whether an isosceles trapezoid has two pairs of parallel sides based on these definitions.

Now, let's work through each step:
Step 1: A trapezoid is defined as a quadrilateral with at least one pair of parallel sides.
Step 2: An isosceles trapezoid is a special type of trapezoid where the non-parallel sides (legs) are of equal length. Its defining feature is having exactly one pair of parallel sides, which is the same characteristic as a general trapezoid.
Step 3: Since the definition of a trapezoid inherently allows for only one pair of parallel sides, an isosceles trapezoid, as a type of trapezoid, cannot have two pairs of parallel sides. A quadrilateral with two pairs of parallel sides is typically designated as a parallelogram, not a trapezoid.

Therefore, the solution to the problem is that isosceles trapezoids do not have two pairs of parallel sides. No.

To determine the area of the trapezoid, we will follow these steps:

• Step 1: Identify the provided dimensions of the trapezoid.
• Step 2: Apply the formula for the area of a trapezoid.
• Step 3: Perform the arithmetic to calculate the area.

Let's proceed through these steps:

Step 1: Identify the dimensions
The given dimensions from the diagram are:
Height $h = 3$ cm.
One base $b_1 = 4$ cm.
The other base $b_2 = 7$ cm.

Step 2: Apply the area formula
To find the area $A$ of the trapezoid, use the formula:
$A = \frac{1}{2} \times (b_1 + b_2) \times h$

Step 3: Calculation
Substituting the known values into the formula:
$A = \frac{1}{2} \times (4 + 7) \times 3$

Simplify the expression:
$A = \frac{1}{2} \times 11 \times 3$

Calculate the result:
$A = \frac{1}{2} \times 33 = \frac{33}{2} = 16.5$ cm²

The area of the trapezoid is therefore $16.5$ cm².

Given the choices, this corresponds to choice : $16.5$ cm².

Therefore, the correct solution to the problem is $16.5$ cm².

To find the area of the trapezoid, we will follow these steps:

• Step 1: Identify the given dimensions of the trapezoid.
• Step 2: Apply the area formula for a trapezoid using these dimensions.
• Step 3: Perform the calculation to determine the area.

Let's work through each step more clearly:
Step 1: From the problem, we identify that the trapezoid has one base $b_1 = 13$ units, another base $b_2 = 8$ units, and its height $h = 5$ units.
Step 2: The formula for the area of a trapezoid is:

$A = \frac{1}{2} \times (b_1 + b_2) \times h$

Step 3: Substitute the values into the formula:

$A = \frac{1}{2} \times (13 + 8) \times 5$

$A = \frac{1}{2} \times 21 \times 5$

$A = \frac{1}{2} \times 105$

$A = 52.5 \, \text{units}^2$

Therefore, the area of the trapezoid is $52.5 \, \text{units}^2$.

We use the following formula to calculate the area of a trapezoid: (base+base) multiplied by the height divided by 2:

$\frac{(AB+DC)\times BE}{2}$

$\frac{(7+15)\times2}{2}=\frac{22\times2}{2}=\frac{44}{2}=22$

The problem requires calculating the perimeter of the trapezoid by summing the lengths of its sides. Based on the given trapezoid diagram, the side lengths are clearly marked as follows:

• First side: $4$
• Second side: $9$
• Third side: $6$
• Fourth side: $13$

According to the formula for the perimeter of a trapezoid:

$P = a + b + c + d$

Substituting the respective values:

$P = 4 + 9 + 6 + 13$

Calculating the sum, we find:

$P = 32$

Thus, the perimeter of the trapezoid is $32$.

To solve this problem, we'll follow these steps:

• Step 1: Identify the given information relevant to the trapezoid.
• Step 2: Apply the appropriate formula for the area of a trapezoid.
• Step 3: Perform the necessary calculations to find the area.

Now, let's work through each step:
Step 1: The problem gives us two bases, $b_1 = 6$ cm and $b_2 = 12$ cm, and a height $h = 4$ cm.
Step 2: We'll use the formula for the area of a trapezoid: $A = \frac{1}{2} \cdot (b_1 + b_2) \cdot h$
Step 3: Substituting in the given values: $A = \frac{1}{2} \cdot (6 + 12) \cdot 4 = \frac{1}{2} \cdot 18 \cdot 4 = \frac{72}{2} = 36 \text{ cm}^2$

Therefore, the solution to the problem is $36$ cm².

To solve this problem, we'll compute the area of the trapezoid using the given dimensions and the area formula:

• Step 1: Identify the given dimensions:
• Base $b_1 = 10$ cm
• Base $b_2 = 6.5$ cm
• Height $h = 4$ cm
• Step 2: Use the trapezoid area formula:

The formula for the area of a trapezoid is $A = \frac{1}{2}(b_1 + b_2)h$.

• Step 3: Substitute the given values into the formula:

$A = \frac{1}{2}(10 + 6.5) \times 4$

• Step 4: Calculate the area:

First, calculate the sum of the bases: $10 + 6.5 = 16.5$.

Next, multiply by the height: $16.5 \times 4 = 66$.

Finally, divide by 2 to get the area: $\frac{66}{2} = 33$ cm².

Therefore, the area of the trapezoid is $33$ cm².